bestbird
2012-Jun-06 07:43 UTC
[R] problem about set operation and computation after split
hi,
I met some problems in R, plz help me.
1. How to do a intersect operation among several groups in one list, without
a loop statement? (I think It may be a list)
create data:
myData <- data.frame(product = c(1,2,3,1,2,3,1,2,2),
year=c(2009,2009,2009,2010,2010,2010,2011,2011,2011),value=c(1104,608,606,1504,508,1312,900,1100,800))
mySplit<- split(myData,myData$year)
mySplit
$`2009`
product year value
1 1 2009 1104
2 2 2009 608
3 3 2009 606
$`2010`
product year value
4 1 2010 1504
5 2 2010 508
6 3 2010 1312
$`2011`
product year value
7 1 2011 900
8 2 2011 1100
9 2 2011 800
I want to get intersection of product between every year. I know the
basic is:
intersect(intersect(mySplit[[1]]$product,
mySplit[[2]]$product),mySplit[[3]]$product)
this will give the correct answer:
[1] 1 2
above code lacks reusability, so It should use a for loop:
myIntersect<-mySplit[[1]]$product
for (i in 1:length(mySplit)-1){
myIntersect<-intersect(myIntersect,mySplit[[i+1]]$product)
}
It's correct too, but stll too complex, so my question is:
Can I do the same thing just use another similar intersect function
(without for/repeat/while).
What's this simple function's name ?
2.how to do a relative computation after split (notice: not befor split)?
create data:
myData1 <- data.frame(product = c(1,2,3,1,2,3),
year=c(2009,2009,2009,2010,2010,2010),value=c(1104,608,606,1504,508,1312),relative=0)
mySplit1<- split(myData1,myData1$year)
mySplit1
$`2009`
product year value relative
1 1 2009 1104 0
2 2 2009 608 0
3 3 2009 606 0
$`2010`
product year value relative
4 1 2010 1504 0
5 2 2010 508 0
6 3 2010 1312 0
I want compute relative value in the every group, what I mean is , I want
get the result is just like below:
$`2009`
product year value relative
1 1 2009 1104 0
2 2 2009 608 -496
3 3 2009 606 -2
$`2010`
product year value relative
4 1 2010 1504 0
5 2 2010 508 -996
6 3 2010 1312 804
I think to use a loop maybe work, but Is there no direct method on list?
3.how to do a sorting after split, It's just like above question, what I
want is sorting by value:
$`2009`
product year value relative
3 3 2009 606 0
2 2 2009 608 0
1 1 2009 1104 0
$`2010`
product year value relative
5 2 2010 508 0
6 3 2010 1312 0
4 1 2010 1504 0
4. how to do a filtering after split, Yes, It's just like above quetion,
what I want is filtering out data which value is more than 1000:
$`2009`
product year value relative
1 1 2009 1104 0
$`2010`
product year value relative
4 1 2010 1504 0
6 3 2010 1312 0
--
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http://r.789695.n4.nabble.com/problem-about-set-operation-and-computation-after-split-tp4632496.html
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bestbird
2012-Jun-13 02:06 UTC
[R] problem about set operation and computation after split
can anyone help me? -- View this message in context: http://r.789695.n4.nabble.com/problem-about-set-operation-and-computation-after-split-tp4632496p4633192.html Sent from the R help mailing list archive at Nabble.com.
R. Michael Weylandt
2012-Jun-13 04:43 UTC
[R] problem about set operation and computation after split
On Wed, Jun 6, 2012 at 2:43 AM, bestbird <bestbird7788 at gmail.com> wrote:> hi, > ? ?I met some problems in R, plz help me. > 1. How to do a intersect operation among several groups in one list, without > a loop statement? (I think It may be a list) > ? create data: > ? myData <- data.frame(product = c(1,2,3,1,2,3,1,2,2), > year=c(2009,2009,2009,2010,2010,2010,2011,2011,2011),value=c(1104,608,606,1504,508,1312,900,1100,800)) > ? mySplit<- split(myData,myData$year) > ? mySplit > $`2009` > ?product year value > 1 ? ? ? 1 2009 ?1104 > 2 ? ? ? 2 2009 ? 608 > 3 ? ? ? 3 2009 ? 606 > > $`2010` > ?product year value > 4 ? ? ? 1 2010 ?1504 > 5 ? ? ? 2 2010 ? 508 > 6 ? ? ? 3 2010 ?1312 > > $`2011` > ?product year value > 7 ? ? ? 1 2011 ? 900 > 8 ? ? ? 2 2011 ?1100 > 9 ? ? ? 2 2011 ? 800 > ? ?I want to get intersection of product between every year. I know the > basic is: > ? ?intersect(intersect(mySplit[[1]]$product, > mySplit[[2]]$product),mySplit[[3]]$product) > ? ?this will give the correct answer: > ? ?[1] 1 2 > ? ?above code lacks reusability, so It should use a for loop: > ? ?myIntersect<-mySplit[[1]]$product > ? ?for (i in 1:length(mySplit)-1){ > ? ? ? ?myIntersect<-intersect(myIntersect,mySplit[[i+1]]$product) > ? ?} > ? ?It's correct too, but stll too complex, so my question is: > ? ?Can I do the same thing just use another similar intersect function > (without for/repeat/while). > ? ?What's this simple function's name ?Take a look at Reduce()> > 2.how to do a relative computation after split (notice: not befor split)? > ? create data: > ? myData1 <- data.frame(product = c(1,2,3,1,2,3), > year=c(2009,2009,2009,2010,2010,2010),value=c(1104,608,606,1504,508,1312),relative=0) > ? mySplit1<- split(myData1,myData1$year) > ? mySplit1 > $`2009` > ?product year value relative > 1 ? ? ? 1 2009 ?1104 ? ? ? ?0 > 2 ? ? ? 2 2009 ? 608 ? ? ? ?0 > 3 ? ? ? 3 2009 ? 606 ? ? ? ?0 > > $`2010` > ?product year value relative > 4 ? ? ? 1 2010 ?1504 ? ? ? ?0 > 5 ? ? ? 2 2010 ? 508 ? ? ? ?0 > 6 ? ? ? 3 2010 ?1312 ? ? ? ?0 > ? I want compute relative value in the every group, what I mean is , I want > get the result is just like below: > ? $`2009` > ?product year value relative > 1 ? ? ? 1 2009 ?1104 ? ? ? ?0 > 2 ? ? ? 2 2009 ? 608 ? ? ? ?-496 > 3 ? ? ? 3 2009 ? 606 ? ? ? ?-2 > > $`2010` > ?product year value relative > 4 ? ? ? 1 2010 ?1504 ? ? ? ?0 > 5 ? ? ? 2 2010 ? 508 ? ? ? ?-996 > 6 ? ? ? 3 2010 ?1312 ? ? ? ?804 > I think to use a loop maybe work, but Is there no direct method on list?lapply ? possibly in conjunction with sweep.> > 3.how to do a sorting after split, It's just like above question, what I > want is sorting by value: > ? $`2009` > ?product year value relative > 3 ? ? ? 3 2009 ? 606 ? ? ? ?0 > 2 ? ? ? 2 2009 ? 608 ? ? ? ?0 > 1 ? ? ? 1 2009 ?1104 ? ? ? ?0 > $`2010` > ?product year value relative > 5 ? ? ? 2 2010 ? 508 ? ? ? ?0 > 6 ? ? ? 3 2010 ?1312 ? ? ? ?0 > 4 ? ? ? 1 2010 ?1504 ? ? ? ?0lapply probably you'll need order for this one.> > 4. how to do a filtering after split, Yes, It's just like above quetion, > what I want is filtering out data which value is more than 1000: > $`2009` > ?product year value relative > 1 ? ? ? 1 2009 ?1104 ? ? ? ?0 > $`2010` > ?product year value relative > 4 ? ? ? 1 2010 ?1504 ? ? ? ?0 > 6 ? ? ? 3 2010 ?1312 ? ? ? ?0lapply which() and logical indexing. Michael> > -- > View this message in context: http://r.789695.n4.nabble.com/problem-about-set-operation-and-computation-after-split-tp4632496.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > R-help at r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code.
Rui Barradas
2012-Jun-13 11:22 UTC
[R] problem about set operation and computation after split
Hello, It seems you haven't discovered the *apply functions yet. In this case, since you have a list, the function would be lapply. 1. Reduce(intersect, lapply(mySplit, function(x) x$product)) 2. lapply(mySplit, function(x) within(x, relative <- diff(c(value[1], value)))) 3. lapply(mySplit, function(x) x[order(x$value), ]) And R-intro.pdf in the doc folder of your installation of R. Hope this helps, Rui Barradas Em 06-06-2012 08:43, bestbird escreveu:> hi, > I met some problems in R, plz help me. > 1. How to do a intersect operation among several groups in one list, without > a loop statement? (I think It may be a list) > create data: > myData<- data.frame(product = c(1,2,3,1,2,3,1,2,2), > year=c(2009,2009,2009,2010,2010,2010,2011,2011,2011),value=c(1104,608,606,1504,508,1312,900,1100,800)) > mySplit<- split(myData,myData$year) > mySplit > $`2009` > product year value > 1 1 2009 1104 > 2 2 2009 608 > 3 3 2009 606 > > $`2010` > product year value > 4 1 2010 1504 > 5 2 2010 508 > 6 3 2010 1312 > > $`2011` > product year value > 7 1 2011 900 > 8 2 2011 1100 > 9 2 2011 800 > I want to get intersection of product between every year. I know the > basic is: > intersect(intersect(mySplit[[1]]$product, > mySplit[[2]]$product),mySplit[[3]]$product) > this will give the correct answer: > [1] 1 2 > above code lacks reusability, so It should use a for loop: > myIntersect<-mySplit[[1]]$product > for (i in 1:length(mySplit)-1){ > myIntersect<-intersect(myIntersect,mySplit[[i+1]]$product) > } > It's correct too, but stll too complex, so my question is: > Can I do the same thing just use another similar intersect function > (without for/repeat/while). > What's this simple function's name ? > > 2.how to do a relative computation after split (notice: not befor split)? > create data: > myData1<- data.frame(product = c(1,2,3,1,2,3), > year=c(2009,2009,2009,2010,2010,2010),value=c(1104,608,606,1504,508,1312),relative=0) > mySplit1<- split(myData1,myData1$year) > mySplit1 > $`2009` > product year value relative > 1 1 2009 1104 0 > 2 2 2009 608 0 > 3 3 2009 606 0 > > $`2010` > product year value relative > 4 1 2010 1504 0 > 5 2 2010 508 0 > 6 3 2010 1312 0 > I want compute relative value in the every group, what I mean is , I want > get the result is just like below: > $`2009` > product year value relative > 1 1 2009 1104 0 > 2 2 2009 608 -496 > 3 3 2009 606 -2 > > $`2010` > product year value relative > 4 1 2010 1504 0 > 5 2 2010 508 -996 > 6 3 2010 1312 804 > I think to use a loop maybe work, but Is there no direct method on list? > > 3.how to do a sorting after split, It's just like above question, what I > want is sorting by value: > $`2009` > product year value relative > 3 3 2009 606 0 > 2 2 2009 608 0 > 1 1 2009 1104 0 > $`2010` > product year value relative > 5 2 2010 508 0 > 6 3 2010 1312 0 > 4 1 2010 1504 0 > > 4. how to do a filtering after split, Yes, It's just like above quetion, > what I want is filtering out data which value is more than 1000: > $`2009` > product year value relative > 1 1 2009 1104 0 > $`2010` > product year value relative > 4 1 2010 1504 0 > 6 3 2010 1312 0 > > -- > View this message in context: http://r.789695.n4.nabble.com/problem-about-set-operation-and-computation-after-split-tp4632496.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > R-help at r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code.