search for: minimum

useRs, I am looking to find the minimum positive value of some data I have. Currently, I am able to find the minimum of data after I apply some other functions to it: > x [1] 1 0 1 2 3 3 4 5 5 5 6 7 8 8 9 9 10 10 > sort(x) [1] 0 1 1 2 3 3 4 5 5 5 6 7 8 8 9 9 10 10 > diff(sort(x)) [1] 1 0 1...

...ability. Unfortunately, I hit a snag and couldn't get the tests to run properly. When I used ivreg, I got an error message saying: "Error in eval(predvars, data, env) : object 'WageInequality' not found." Can you please help? Model: numeric(WageInequality) = numeric(EffectiveMinimum) + numeric(EffectiveMinimum2) (whereas EffectiveMinimum2 is the quadratic form of EffectiveMinimum) Instruments: numeric(`Log Real Minimum Wage`) + numeric(`Log Real Minimum Wage2`) + numeric(IVinteration) (whereas Real Minimum Wage2 is the quadratic form of Real Minimum Wage) Time and Region Fix...

...32 31 20 20 20 20 20 20 20 20 20 20 20 20 DIS: Store and forward Internet fax: no Real-time Internet fax: no Preferred octets: 256 Can receive fax Data signalling rate: V.29 R8x7.7lines/mm and/or 200x200pels/25.4mm OK 2D coding OK Scan line length: 215mm Recording length: A4 (297mm) Receiver's minimum scan line time: 0ms at 3.85 l/mm: T7.7 = T3.85 R8x15.4lines/mm OK Inch-based resolution preferred: no Metric-based resolution preferred: no Minimum scan line time for higher resolutions: T15.4 = T7.7 >>> DIS: 80 00 c6 f0 80 80 01 HDLC underflow in state 9 Changed from phase 4 to 3 T4 timeo...

Here is my situation: I have large Speex encoded stream which I would like to playback on wave out device. I could decode whole stream to pcm and play it back as pcm audio, but this is not what I want. Instead I want to decode minimum decodable bits (bytes?) to pcm and play it ... then decode another minimum data chunk and play it, etc. This way I can achieve closest to real-time playback or I can pause and then restart playback. So, my question is: What is minimum length of Speex encoded data where decoder (speex_decode)...

...#39;structure'' as output or creating empty ''data.frame'' and then transform it as output? (fun1 and fun1 is just for illustration). ? Thanks a lot, OV ? code: input <- data.frame(x1 = rnorm(20), x2 = rnorm(20), x3 = rnorm(20)) fun1 <- function(x) { ??? ID <- NULL; minimum <- NULL; maximum <- NULL ??? for(i in seq_along(names(x)))?? { ??????? ID[i]?????? <- names(x)[i] ????????? minimum[i]? <- min(x[, names(x)[i]]) ??????????? maximum[i]? <- max(x[, names(x)[i]]) ??????????????????????????????????? } ??? output <- structure(list(ID, minimum, maximum...

It came up on another thread that our current minimum required CMake version 2.8.8, has some bugs that cause issues when building with MSVC + Ninja, and one potential solution was to raise the minimum required version of CMake. CMake 3.0 is now 6 months old and CMake 3.1 has been released. I would like to propose moving our minimum required CMake ver...

...32 31 20 20 20 20 20 20 20 20 20 20 20 20 DIS: Store and forward Internet fax: no Real-time Internet fax: no Preferred octets: 256 Can receive fax Data signalling rate: V.29 R8x7.7lines/mm and/or 200x200pels/25.4mm OK 2D coding OK Scan line length: 215mm Recording length: A4 (297mm) Receiver's minimum scan line time: 0ms at 3.85 l/mm: T7.7 = T3.85 R8x15.4lines/mm OK Inch-based resolution preferred: no Metric-based resolution preferred: no Minimum scan line time for higher resolutions: T15.4 = T7.7 >>> DIS: 80 00 c6 f0 80 80 01 HDLC underflow in state 9 Changed from phase 4 to 3 T4 timeo...

I’m not too familiar with Ubuntu’s LTS releases, but from some google digging I believe there are 3 active LTS releases. 10.04 has CMake 2.8.0 (which is already below our minimum), but 10.04 will be dropping out of LTS this year. 12.04 has CMake 2.8.7 (also below our minimum) 14.04 has CMake 2.8.12.2, which should also have the fix for MSVC Based on this, it might be reasonable to update the minimum to 2.8.12.2 instead of 3.0.0. Thoughts? -Chris > On Feb 9, 2015, at 1...

I'd like to get a long data set of minimum values from groups in another data set. The following almost does what I want. (Note, I'm using the word factor differently from it's meaning in R; bad choice of words) myframe = data.frame(factor1 = rep(1:2,each=8), factor2 = rep(c("a","b"),each=4, times=2), factor3 =...

Dear R helpers, I think that this may be a bit of a math question as the more I consider it, the harder it seems. I am trying to come up with a way to work out the minimum distance between line segments. For instance, consider 20 random line segments: x1 <- runif(20) y1 <- runif(20) x2 <- runif(20) y2 <- runif(20) plot(x1, y1, type = "n") segments(x1, y1, x2, y2) Inititally I thought the solution to this problem was to work out the distance b...

Can someone please explain what the $minimum result of the optimize function actually is? I'm trying to optimize the function: fitIT<-function(ampFac,ts_wave1,ts_template){ template<-stretchWaveTime(ts_template,ampFac) fit<-calcFit(ts_wave1,template) return(fit) } with >optimize(f=fitIT,interval=c(0.5,4),ts_wave1...

Dear All, I would like to ask a question on how to find the index of the minimum of entries of a numeric vector, without using loops or user defined functions. Suppose we have a vector: a <- c(3,1,2) then, min(a) = 1 and its index is 2. Target: how to get the index of this minimum? How to get the indices if multiple entries assume this same minimum? Thank you, Chee [[...

Hallo, I just followed the discussion of the title: minimum from matrix. I have a similar problem. > a=matrix(c(0,2, 0, 0, 1, 3, 0, 3, 2, 0, 3, 5, 0, 4, 0, 0),ncol=4) > a=rbind(a,1:4) > a [,1] [,2] [,3] [,4] [1,] 0 1 2 0 [2,] 2 3 0 4 [3,] 0 0 3 0 [4,] 0 3 5 0 [5,] 1 2 3 4 > > m...

Are there any easy to use snmp(mainly temperature monitoring) tools around for Centos -4? This is on a Dell sc420 server. -- Computer House Calls, Networks, Security, Web Design: http://www.emmanuelcomputerconsulting.com What businesses are in Brunswick, Maryland? Check Brunswick First! http://www.checkbrunswickfirst.com My "Foundation" verse: Isa 54:17 No weapon that is formed

...5600 Using power down flag file C:\killpower 0.015600 debug level is '5' 0.015600 Trying to connect to UPS [upsa at 192.168.10.200] 0.031200 Login on UPS [upsa at 192.168.10.200] failed - got [ERR ACCESS-DENIED] 0.031200 Current power value: 1 0.046800 Minimum power value: 1 5.054409 pollups: upsa at 192.168.10.200 5.054409 get_var: upsa at 192.168.10.200 / status 5.054409 Poll UPS [upsa at 192.168.10.200] failed - Data stale 5.070009 do_notify: ntype 0x0005 (COMMBAD) 5.070009 Communications with UPS upsa at 192.168.10....

Hey everyone, I'm trying to compile a document to send out to our customers that outlines the minimum and recommended requirements to run C4, C5, and C6. Does anyone know the particulars? When we order systems, it's usually Pentium Dual Core CPU, 120GB+ Hard drive, 2GB Ram. I need the ABSOLUTE MINIMUM requirements to install and run any of the aforementioned flavors as a "basic ser...

Hi, I have a matrix BEE and want to find the row and column numbers of the minimum value in that matrix. The command which(BEE==min(BEE)) returns only one value which, I take, is the position of the minimum in a vector with as many elements as the matrix. Is there a quick and simple way of getting row and column numbers? Thanks, Gonçalo [[alternative HTML versi...

...>>> CSI: 40 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 DIS: Preferred octets: 256 Can receive fax Supported data signalling rates: V.27ter and V.29 R8x7.7lines/mm and/or 200x200pels/25.4mm OK 2D coding OK Scan line length: 215mm Recording length: A4 (297mm) Receiver's minimum scan line time: 0ms at 3.85 l/mm: T7.7 = T3.85 R8x15.4lines/mm OK Minimum scan line time for higher resolutions: T15.4 = T7.7 >>> DIS: 80 00 ce f0 80 80 01 HDLC underflow in state 9 Changed from phase 4 to 3 T4 timeout in state 9 Changed from phase 3 to 4 Sending ident >>> CSI: 40...

Hi all, I have installed FAX app as described in several mails. When a fax call is received, I get the following in the * console: -- Starting simple switch on 'Zap/1-1' -- Executing Answer("Zap/1-1", "") in new stack -- Executing Ringing("Zap/1-1", "") in new stack -- Executing Wait("Zap/1-1", "2") in new stack

Dear All, I am using package fPortfolio to run minimum variance portfolio optimizations in R. I already know how to set portfolioSpecs, portfolio objects and constraints. Unfortunately I am not able to set the following type of constraints. I have a timeSeries object with returns data for roughly 1.5k assets for 261 subperiods (workingdays) and want t...