Displaying 20 results from an estimated 38 matches for "comp1".
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com1
2005 Jun 17
4
linux ip forwarding problem
Hi,
I have three linux machines, and I want to let one of them forward packets
betwen the other two. The forwarding node has two ethernet cards,
connecting the two two machines respectively. However, when I ping between
the two end points, the forwarding node can receive the ping requests at
its eth0, but it never forwards them to its eth1. So is the reverse
direction.
The forwarding node is
2003 May 09
4
SIP Confusion
...lain why. I don't
understand
why this wouldn't work.
----[Extra
Information]----------------------------------------------------------------------------
My current setup:
On computer 192.168.10.50
**sip.conf***
[general]
port=5060
bindaddr=0.0.0.0
context=default
allow=gsm
register=>comp1:mysecret@192.168.10.51
[comp2]
type=friend
username=comp2
secret=bigsecret
host=192.168.10.51
**extensions.conf***
[general]
static=yes
writeprotect=no
[default]
exten=>_221,1,Dial,SIP/comp2
-=================
On computer 192.168.10.51
**sip.conf***
[general]
port=5060
bindaddr=0.0.0.0
cont...
2000 Jan 27
2
Files have 555 and they are deletable or is it a bug ?
Hello !
I've a problem with files which are set to 0555.
For example: two users (user1 and user2)
two groups (usergroup1 usergroup2)
/daten/rechner/comp1 is set to 777.
User1 creates a file (test.txt) in the [files] share, which is correctly
set to 0555. It's owner is user1 and it's group is usergroup1.
Now user2 from usergroup2, who can correctly read but not edit test.txt,
can delete this file. I think the reason for this is the
/daten/rec...
2004 Apr 03
7
Few question on HTB
...ar All,
Sorry to trouble again..... After go through www.lartc.org I have implemented the HTB instead of CBQ
for the same scenario.
Now following files are under /etc/sysconfig/htb directory.
eth0 DEFAULT=30 R2Q=10
eth0-2.root RATE=256kbps BURST=25k
eth0-2:10.comp1 RATE=120kbps BURST=12k PRIO=0 LEAF=sfq RULE=192.168.200.0/24
eth0-2:20.comp2 RATE=80kbps BURST=8k PRIO=1 LEAF=sfq RULE=192.168.100.0/24
eth0-2:30.server RATE=56kbps BURST=6k PRIO=3 LEAF=sfq RULE=203.145.134.120/29
--------------------
eth1-2:30.root RATE=56kbps BUR...
2012 Nov 20
1
FOOBAR\usuario1 windows explorer hungs forever while accessing shared dirs in LAPAZ\comp1 (interdomain trust relationships)
....1
openldap2-2.4.12-5.6.1
smbldap-tools-0.9.5-25.1
A winxp called USUARIO1 joined to the FOOBAR domain (ip 192.168.1.100)
domain LAPAZ with pdc server name: SERVERLPZ (ip 192.168.10.4)
openSUSE 12.2
samba-3.6.7-48.12.1.i586
openldap2-2.4.31-2.1.3.i586
smbldap-tools-0.9.6-5.1.noarch
A winxp called COMP1 joined to the LAPAZ domain (ip 192.168.10.101)
I made interdomain trust relationships according to the steps written at the end of this mail,
but when FOOBAR\USUARIO1 tries to access shares available on LAPAZ\COMP1 using windows explorer, it hungs forever.
Doing some packet capture with wireshar...
2006 Aug 04
7
Question about networking setup
Hello everyone!
How are you? Hope you''re well :)
Here''s my setup at home:
Internet -> (eth1) Comp1 (shorewall, DHCP, dns server, Internet sharing)
(eth0) -> Linksys (wireless) ~~~~~~~~~~~~ (wlan0) Comp2 (eth0) -> IP Phone
My computer1 is well confiugred, everything was working right and well.
I decided to move the IP Phone to the COmputer 2.
I was able to make this working by reinstalli...
2009 Dec 09
1
Regedit
...____________________________________________
|
| |
|
| |
_________
_________ ______
| comp1 | | comp2 |
| PDC |
---------------
--------------- ----------
Now when i try to connect to the registry of comp1 from comp2 I get an error
saying i don't have permission to connect using the domain ad...
2013 Oct 01
5
Análisis de componentes principales con ade4 y FactoMineR
...de cada individuo
que obtiene cada función, las que corresponden al segundo componente
principal tienen idéntica magnitud pero con signos contrarios:
Función dudi.pca:
Comando:
PCA1 <- dudi.pca(df = DATOS[,(2:ncol(DATOS))], center = TRUE, scale =
TRUE, scannf = FALSE, nf = 6)
Individuo Comp1 Comp2
1 -14.18 -4.47
2 -14.63 -4.53
3 -14.77 -2.57
4 -14.12 -1.71
5 -16.32 4.22
6 -17.03 5.94
7 -16.90 3.68
8 -17.75 5.86
9 13.86 -13.33
10 13.16 -12.71
11 13.24 -14.18
12 12.68 -13.07
13 18.43 11.67
14 17.49 10....
2006 Apr 04
2
documenting s4 methods in package
...\item{z}{ ~~Describe \code{z} here~~ }
\item{simplify}{ ~~Describe \code{simplify} here~~ }
\item{descrip}{ ~~Describe \code{descrip} here~~ }
}
\details{
~~ If necessary, more details than the __description__ above ~~
}
\value{
~Describe the value returned
If it is a LIST, use
\item{comp1 }{Description of 'comp1'}
\item{comp2 }{Description of 'comp2'}
...
}
\references{ ~put references to the literature/web site here ~ }
\author{ ~~who you are~~ }
\note{ ~~further notes~~ }
~Make other sections like Warning with \section{Warning }{....} ~
\seealso{ ~~objects...
2011 Dec 01
2
nipals in the chemometrics package in R
Hello
i need some precision about nipals in the chemometrics package in R .
When i use nipals in chemometrics i obtain T and P matrix.
I really don't understand what to do with these two matrix to obtain
the scores for every the component (like in spss fo example)
Comp1 Comp2 Comp3
quest1 0,8434 0,54333 0,3466
quest2 0,665 0,7655 0,433
Thank you very much for your help
(I know that X=TP+E)... But don't understand else....
2018 Jan 15
2
networking remote systems over unknown ip's
...d I want the kids to be able to share programs they
write with each other on the different disk automatically securely. Can
I network these systems without knowing individual ip's and not
touching firewalls. I was thinking maybe I could use a dns service like
duckdns to substitute ip's with comp1.duckdns.org, comp2.duckdns.org,
etc.
Is this even possible/advisable using tinc?
I am guessing I would minimally need to know the internal private ip's
to avoid conflicts.
2017 Sep 18
1
Data arrangement for PLSDA using the ropls package
...quot;sa32",
"sa33", "sa34", "sa35", "sa36", "sa37", "sa38", "sa39", "sa4",
"sa40", "sa5", "sa6", "sa7", "sa8", "sa9"), class = "factor"),
Comp1 = c(1.7686, 0.6873, 1.2322, 1.4874, 1.8986, 1.3484,
1.0959, 0.583, 1.039, 1.6133, 0.9595, 1.6377, 1.4538, 0.8737,
1.3363, 1.7881, 2.3604, 1.1239, 2.1281, 2.037, 0.5314, 0.7147,
0.5917, 0.6671, 0.6645, 0.9865, 1.019, 0.9664, 0.6966, 0.679,
0.7976, 0.8503, 1.2566, 0.5881, 0.8838,...
2013 Apr 07
3
mlogit error
...0, 0, 0, 0, 0, 3, 0, 0, 0, 3, 0), cPROTIUM = c(0, 0, 0, 0,
0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 3, 0, 0, 0, 3, 0
), cZANTAC = c(0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0,
0, 0, 0, 3, 0, 0, 0, 3, 0), cZOTON = c(0, 0, 0, 0, 0, 0, 0, 0,
1, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 1, 0, 0, 0, 1, 0), comp1 = c(0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0), comp2 = c(0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0), comp3 = c(0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0), comp4 = c(0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0...
2013 Oct 01
3
Análisis de componentes principales con ade4 y FactoMineR
...de cada individuo que obtiene cada función,
las que corresponden al segundo componente principal tienen idéntica
magnitud pero con signos contrarios:
Función dudi.pca:
Comando:
PCA1 <- dudi.pca(df = DATOS[,(2:ncol(DATOS))], center = TRUE, scale = TRUE,
scannf = FALSE, nf = 6)
Individuo Comp1 Comp2
1 -14.18 -4.47
2 -14.63 -4.53
3 -14.77 -2.57
4 -14.12 -1.71
5 -16.32 4.22
6 -17.03 5.94
7 -16.90 3.68
8 -17.75 5.86
9 13.86 -13.33
10 13.16 -12.71
11 13.24 -14.18
12 12.68 -13.07
13 18.43 11.67
14...
2008 Apr 13
1
promptFunctions() to handle multiple names
..."description above ~~"),
~ "}")
~ Rdtxt$value <- c("\\value{",
~ " ~Describe the values returned",
~ " If it is a LIST, use",
~ " \\item{comp1 }{Description of 'comp1'}",
~ " \\item{comp2 }{Description of 'comp2'}",
~ " ...",
~ "}")
~ Rdtxt$references <- paste("\\references{ ~put references to the",
~...
2000 Oct 03
3
prcomp compared to SPAD
...ponents:
PC1 PC2 PC3 PC4
Standard deviation 83.732 14.2124 6.4894 2.48279
Proportion of Variance 0.966 0.0278 0.0058 0.00085
Cumulative Proportion 0.966 0.9933 0.9991 1.00000
And using SPAD (french editor CISIA) :
Ex: sd pv cp
comp1 | 2.4802 | 62.01 | 62.01 |
comp2 | 0.9898 | 24.74 | 86.75 |
comp3 | 0.3566 | 8.91 | 95.66 |
comp4 | 0.1734 | 4.34 | 100.00 |
Am I wrong using R ? Why the results are so different ?
Furthemore could anyone explain me the difference between prcomp a...
2013 Aug 27
2
Encontrar las variables más importantes en componentes principales
...nseguirlo. Los comandos que utilizo
son los siguientes:
acp <- dudi.pca(df = DATOS[,(2:1013)], scannf = FALSE, nf = 2)
acpI <- inertia.dudi(acp, row.inertia = T, col.inertia = T)
#CONTRIBUCIONES DE LAS COLUMNAS A LOS EJES
acpI$col.abs/100
Con esto obtengo una lista similar a:
Comp1 Comp2
X0 0.02 0.03
X1 0.04 0.00
X2 0.25 0.08
X3 0.12 0.07
X4 0.08 0.10
X5 0.09 0.03
.
.
.
De estos valores parece ser que, por ejemplo, las variables X2 y X3
contribuyen en mayor grado al componente principal 1, y que la variable
X4 contribuye en mayor grado al compo...
2003 May 06
9
SIP configuration question
...e setup), will I be able to
use SIP?
I already have the two computers calling each other using IAX, but I would
like to see if I can get them to work using SIP.
My current setup:
On computer 192.168.10.50
**sip.conf***
[general]
port=5060
bindaddr=0.0.0.0
context=default
allow=gsm
register=>comp1:mysecret@192.168.10.51
[comp2]
type=friend
username=comp2
secret=bigsecret
host=192.168.10.51
**extensions.conf***
[general]
static=yes
writeprotect=no
[default]
exten=>_221,1,Dial,SIP/comp2
-=================
On computer 192.168.10.51
**sip.conf***
[general]
port=5060
bindaddr=0.0.0.0
cont...
2017 Sep 18
0
Q2/R2 ratio in PLSDA
...simplified example data set and my code:
DATA:
> dput(dta)
structure(list(Treatment = structure(c(2L, 1L, 1L, 2L, 2L, 1L,
2L, 2L, 1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L, 1L, 2L, 2L, 2L, 1L, 2L,
1L, 1L, 2L, 1L, 2L, 2L, 1L, 1L), .Label = c("C", "CAT"), class = "factor"),
comp1 = c(0, 0.5677, 0.4486, 0.1772, 0.2145, 0.0302, 0.216,
0.0938, 0.1143, 0.6414, 0.2461, 0.0498, 0.144, 0.0953, 0.3208,
0.296, 0.418, 0.2247, 0.1921, 0.3792, 0.1394, 0.3069, 0.1211,
0.0355, 0.8968, 0.1981, 0.1187, 0.418, 0.4313, 0.0835), comp2 = c(1.8378,
2.3565, 4.6184, 2.3739, 1.3595...
2004 Sep 09
3
Could not create posix account info
...or 'fc2$'
Creating account: linux$
[2004/08/17 14:09:41, 1] utils/net_rpc_samsync.c:fetch_account_info(434)
fetch_account: Running the command `/usr/local/sbin/smbldap-useradd -w
"linux$"' gave 0
Could not create posix account info for 'linux$'
Creating account: COMP1$
[2004/08/17 14:09:41, 1] utils/net_rpc_samsync.c:fetch_account_info(434)
fetch_account: Running the command `/usr/local/sbin/smbldap-useradd -w
"COMP1$"' gave 0
Could not create posix account info for 'COMP1$'
[2004/08/17 14:09:41, 0]
utils/net_rpc_samsync.c:fetch_group...