Displaying 20 results from an estimated 247 matches for "0.74".
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0.7
2013 Mar 06
3
About basic logical operators
Hello everyone,
I have a basic question regarding logical operators.
> x<-seq(-1,1,by=0.02)
> x
[1] -1.00 -0.98 -0.96 -0.94 -0.92 -0.90 -0.88 -0.86 -0.84 -0.82 -0.80 -0.78
[13] -0.76 -0.74 -0.72 -0.70 -0.68 -0.66 -0.64 -0.62 -0.60 -0.58 -0.56 -0.54
[25] -0.52 -0.50 -0.48 -0.46 -0.44 -0.42 -0.40 -0.38 -0.36 -0.34 -0.32 -0.30
[37] -0.28 -0.26 -0.24 -0.22 -0.20 -0.18 -0.16
2012 Jul 27
1
How to run regressions over increasing time series
Hello,
I would like to run a series of regressions on my data (response variable
over time):
1) regression from T1 to T2
2) regressions from T1 through T3
3) regression from T1 through T4, etc.
I have been struggling to find a way to do this through commands, as
opposed to cutting up the data manually (my dataset has over 6000
rows/observations).
An illustrative dataset can be created thusly:
2010 Jun 04
1
How do I 'merge' a altered subset of a data.frame back into the same data.frame
Hi
Step 1: I create a data.frame called iolm.
Step 2: I create a conditional subset i_wtr.
Step 3: In this subset I add 0.3 to all values in the IOLM_AST column.
Step 4: Now I am looking for the best way to Œmerge¹ the altered subset back
into the original iolm data.frame
## STEP 1
>iolm
ID IOLM_AST IOLM_AXIS
1 1 1.15 165.33
2 2 1.20 79.00
3 3 0.40
2001 Oct 22
10
Winbind, RedHat 7.1, Pam 0.74-22 ohh so close to working
Hello,
I have gone through the howto provided but I am not yet able to
logon to my linux box using NT4 domain accounts. I can however authenticate
to restricted shares and I can obtain groups and users via "getent" and
"wbinfo -u". All I really need now is a working /etc/pam.d/login. I've tried
examples from the howto as with others from the mailing list but I can not
2012 Mar 04
2
How do I create a scatterplot with two explanatory variables?
Hi there,
I'm trying to make a scatterplot of removed versus duration for each type of bee. No matter what I try, I can't seem to get my code to work.
Any help would be appreciated. Thanks!
My r-code:
dat$BEE <- with(dat, factor(BEE, c(1,2)))
plot(REMOVED~DURATION,pch=BEE, col=BEE) REMOVED DURATION BEE
1 0.07 2 QUEEN
2 0.10 5 QUEEN
3 0.11 7 QUEEN
4 0.12 11 QUEEN
5 0.15 12 QUEEN
6 0.19
2008 May 25
3
How is this possible?
As an experiment, I am attempting to build a more recent version of
GNOME than 2.16.0 on CentOS 5.1. I've tried both garnome and jhbuild,
and neither one works quite right. Jhbuild blows out looking for a
dbus-glib-1 revision >= 0/74 (the release rev is 0.70), so I
downloaded that and tried to build it. This results in the following
error:
gcc -g -O2 -Wall -Wchar-subscripts
2013 May 15
1
x and y lengths differ
I have a problem with R. I try to compute the confidence interval for my
df. When I want to create the plot I have this problem: Error in
xy.coords(x, y, xlabel, ylabel, log) : 'x' and 'y' lengths differ.
I try this code:
library(dplR)
df.rwi <- detrend(rwl = df, method = "Spline",nyrs=NULL)
write.table(df.rwi,file="rwi.txt",quote=FALSE,row.names=TRUE)
2008 Apr 09
1
simple intro to cluster analysis using R
I am looking for simple introduction to cluster analysis using R, that would
be understandable to a novice in statistics. Or, could someone perhaps help
me understand how to proceed in my analysis? I am very new to both statistics
and R, but am trying hard to avoid having to use SPSS as everyone around
me...
I have dataset on people presenting their opinions on different religious
2012 Jul 06
3
estimating NA values against selected slots
Dear R Users,
Could you please help me on the following issue?
I have a real large yearly data set. For each year I have
365 flow values. Some of the flow values are not known and that’s why you will
see NA written in those slots. I wanted to know, is there a way that I can
estimate those values? I tried approx command but it seems least helpful for
the kind of issue I am up against.
2012 Aug 11
3
help counting in data
Hi
>i have this data
> X
[1] 5.79 1579.52 2323.70 68.85 426.07 110.29 108.29 1067.60 17.05
22.66
[11] 21.02 175.88 139.07 144.12 20.46 43.40 194.90 47.30 7.74
0.40
[21] 82.85 9.88 89.29 215.10 1.75 0.79 15.93 3.91 0.27
0.69
[31] 100.58 27.80 13.95 53.24 0.96 4.15 0.19 0.78 8.01
31.75
[41] 7.35 6.50
2007 Oct 22
2
Help interpreting output of Rprof
Hello there,
I am not quite sure how to interpret the output of Rprof (in the following the output I was staring at). I was poking around the web a little bit for documentation but without much success. I guess if I want to figure out what takes so long in my code the 2nd table $by.total and the total.pct column (pct = percent) is the most helpful. What does it mean that [ or [.data.frame is
2012 Aug 21
1
make check fails two tests on RHEL 6 build
I am installing R 2.15.1 onto RHEL 6, using gcc 4.7.0 with Intel MKL
10.3.7 and the following environment:
export BLAS_LIBS="-Wl,--start-group
/usr/caen/intel-12.1/mkl/lib/intel64/libmkl_gf_lp64.a
/usr/caen/intel-12.1/mkl/lib/intel64/libmkl_sequential.a
/usr/caen/intel-12.1/mkl/lib/intel64/libmkl_core.a -Wl,--end-group
-lpthread"
export LAPACK_LIBS="-Wl,--start-group
2005 Nov 01
2
Greek letters in plots
Hi, all. I know that this is probably something that others have asked,
but I can't find a reference in either the FAQ or the help pages.
I'm trying to find a way to put Greek letters as a label of the plot
*with* a value from the data. Previously I've used pasted and the word
"rho".
* paste("rho=", cor2[i])
will produce a label of
2008 Mar 16
1
pretty formatting of lists
Hello,
is there already a function in any R package which does
source code formatting of deparsed lists?
Let's create the following list:
x <- list(a = round(rnorm(3), 2),
b = round(rnorm(3), 2))
xx <-c(aa = round(rnorm(30)), f = function(a) a + b, list(x, x))
Now, I want deparse it in a way that yields something like:
list(
aa = c(0.25, 0.18, 0.84, -1.25, 0.09,
2008 Nov 08
2
lines, ecdf and colors
Hi. I'm trying to plot two ecdf's on the same graph using two
different colors. I can plot using the same color, but it doesn't
work when I change colors? Any suggestions? Thanks in advance for
your help.
x <- c(0.80, 0.83, 1.89, 1.04, 1.45, 1.38, 1.91, 1.64, 0.73, 1.46)
y <- c(1.15, 0.88, 0.90, 0.74, 1.21)
plot(ecdf(x))
# it works without col='blue', but doesn't
2008 Sep 22
1
Combine data frames using column names as "key"
Hi guys,
Suppose I have 2 data frames ie:
values
one 0.32
two 0.25
three 0.11
and
values
two 0.66
one 0.74
three 0.19
nb the first column is the row names in both cases
How can I combine them on the row names column? Ie to make something like
values.1 values.2
one 0.32 0.74
two 0.25 0.66
three 0.11 0.19
I guess its
2012 Jan 11
1
R CMD check pkg and 32/64 bit.
R gurus:
I'm trying to get another round of rconifers out and I need some advice/help crushing differences in the examples test.
I'm trying to make sure the max sdi values are being respected.
I've added a tests/rconifers-Ex.Rout.save (from windows i386-pc-mingw32) and when I ran R CMD check (both R-2.13.0), I got the following results:
* using log directory
2006 Jun 19
4
Qurey : How to add trendline( st. line) in Graph
How to add trendline (i.e. straight line passing through maximum points)
in graph.
I have worked on the data given below.
Please tell me how to add trendline in the graph.
The script is as follows
=================================== start
====================================================
# The data is as follows
data <- c( 0.01, 0.02, 0.04, 0.13, 0.17 , 0.19 , 0.21 , 0.27 , 0.27 ,
2012 Jul 10
2
estimation of NA by predict command
Dear arun and all R users,
I will first of all try to simply define my issue..
I have data in the following format
Year Discharge
dd/mm/yyyy x
.. …
… …
There are some NA values in the discharge which I would like to predict by using “predict command”. I cant figure out the way to write the coding for that. Could you please help me on that???
I have also ,written
2012 Feb 20
2
stats on transitions from one state to another
Folks,
I'm trying to get stats from a matrix for each transition from one state to another.
I have a matrix x as below.
structure(c(0, 2, 2, 2, 0, 0, 0, 1, 1, 1, 1, 2, 2, 1, 1, 1, 0,
0, 2, 2, 0.21, -0.57, -0.59, 0.16, -1.62, 0.18, -0.81, -0.19,
-0.76, 0.74, -1.51, 2.79, 0.41, 1.63, -0.86, -0.81, 0.39, -1.38,
0.06, 0.84, 0.51, -1, -1.29, 2.15, 0.39, 0.78, 0.85, 1.18, 1.66,
0.9, -0.94,