search for: 0.7

Displaying 20 results from an estimated 1785 matches for "0.7".

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2010 Nov 10
1
Difficult doubt about choose distances randomly in a matrix with a probability of event
I would like to build a model in R to simulate the seed dispersal by one plant. The plant produced 5 seeds and the probability of falling inside the eight closest space was 0.8 and in the next space 0.2 and in the rest space 0: 0 0 0 0 0 0 0.2 0.2 0.2 0.2 0.2 0 0.2 0.8 0.8 0.8 0.2 0 0.2 0.8 1 0.8 0.2 0 0.2 0.8 0.8 0.8 0.2 0 0.2 0.2 0.2 0.2 0.2 0 0 0 0 0 0 0
2010 Jan 30
2
convert data frame of values into correlation matrix
Hi Group, Consider a data frame like this: mylabel1 <- rep(c("A","B","C"),each=3) mylabel2 <- rep(c("A","B","C"),3) corrs <- c(1,.8,.7,.8,1,.7,.7,.7,1) myData <- data.frame(mylabel1,mylabel2,corrs) myData mylabel1 mylabel2 corrs 1 A A 1.0 2 A B 0.8 3 A C 0.7 4 B
2005 Oct 03
3
Problems compiling 3.0.20a with heimdal 0.7
-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 Hi everybodey, i can't compile 3.0.20 the following message occurs : Compiling dynconfig.c In file included from include/includes.h:452, ~ from dynconfig.c:21: /usr/local/heimdal-0.7/include/krb5.h:660: error: syntax error at '#' token /usr/local/heimdal-0.7/include/krb5.h:660: warning: no semicolon at end of struct or
2012 Jul 06
3
estimating NA values against selected slots
Dear R Users, Could you please help me on the following issue? I have a real large yearly data set. For each year I have 365 flow values. Some of the flow values are not known and that’s why you will see NA written in those slots. I wanted to know, is there a way that I can estimate those values? I tried approx command but it seems least helpful for the kind of issue I am up against.
2012 Jul 02
4
how to do a graph with tree different colors??
hi i try to do a graph of a time series which shows in red the values > -0.05, in blue the values >0.05 and in white the values between -0.05 and 0.05 for un exemple :http://www.appinsys.com/globalwarming/enso.htm thanks !!!!! denisse -- View this message in context: http://r.789695.n4.nabble.com/how-to-do-a-graph-with-tree-different-colors-tp4635206.html Sent from the R help mailing
2008 Apr 09
1
error linking swfplay
Hi, swfplay does not link in latest git 0.6.2-384-g234d0b0. /bin/sh ../libtool --mode=link gcc -g -O2 -o swfplay ../swfdec-gtk/libswfdec-gtk-0.7.la ../swfdec/libswfdec-0.7.la -pthread -lgobject-2.0 -lgthread-2.0 -lrt -lglib-2.0 -lcairo -lpng12 -lz -lgtk- x11-2.0 -lgdk-x11-2.0 -latk-1.0 -lgdk_pixbuf-2.0 -lm -lpangocairo-1.0 -lpango-1.0 -lcairo -lsoup-2.4 -lgio-2.0 -lgobject-2.0
2012 Feb 02
4
The "less than" (<) operator doesnt seem to perform as expected
The example here puzzles me. It seems like the < operator doesn't work as expected. > l <- 0.6 > u <- seq(0.4, 0.7, 0.1) > u [1] 0.4 0.5 0.6 0.7 > mygrid <- expand.grid("l" = l, "u" = u) > mygrid l u 1 0.6 0.4 2 0.6 0.5 3 0.6 0.6 4 0.6 0.7 > mygridcollapsed <- mygrid[mygrid$l < mygrid$u, ] > mygridcollapsed l u 3 0.6 0.6 4
2010 Sep 08
11
problem with outer
Hello, i wrote this function guete and now i want to plot it: but i get this error message. i hope someone can help me. Error in dim(robj) <- c(dX, dY) : dims [product 16] do not match the length of object [1] p_11=seq(0,0.3,0.1) p_12=seq(0.1,0.4,0.1) guete = function(p_11,p_12) { set.seed(1000) S_vek=matrix(0,nrow=N,ncol=1) for(i in 1:N) { X_0=rmultinom(q-1,size=1,prob=p_0)
2004 Nov 22
4
How to correct this
Hi there, I tried to add a few circles on an existing figure using the following codes grid.circle(x=0.5, y=0.5, r=0.1, draw=TRUE, gp=gpar(col=5)) grid.circle(x=0.5, y=0.5, r=0.3, draw=TRUE, gp=gpar(col=5)) grid.circle(x=0.5, y=0.5, r=0.5, draw=TRUE, gp=gpar(col=5)) points(0.5, 0.5, col = 5) # centre of the circle , but all circles moved away from the centre. Could we do any
2012 Jul 10
2
estimation of NA by predict command
Dear arun and all R users, I will first of all try to simply define my issue.. I have data in the following format Year Discharge dd/mm/yyyy x .. … … … There are some NA values in the discharge which I would like to predict by using “predict command”. I cant figure out the way to write the coding for that. Could you please help me on that??? I have also ,written
2007 Nov 29
0
CESA-2007:1084 Critical CentOS 3 s390(x) seamonkey - security update
CentOS Errata and Security Advisory 2007:1084 https://rhn.redhat.com/errata/RHSA-2007-1084.html The following updated files have been uploaded and are currently syncing to the mirrors: s390: updates/s390/RPMS/seamonkey-1.0.9-0.7.el3.centos3.s390.rpm updates/s390/RPMS/seamonkey-chat-1.0.9-0.7.el3.centos3.s390.rpm updates/s390/RPMS/seamonkey-devel-1.0.9-0.7.el3.centos3.s390.rpm
2006 Jul 07
2
BUG in " == " ? (PR#9065)
Hello, here is the version of R that I use : > version _ platform i486-pc-linux-gnu arch i486 os linux-gnu system i486, linux-gnu status major 2 minor 3.1 year 2006 month 06 day 01 svn rev 38247 language R version.string Version 2.3.1 (2006-06-01) And here is one of the sequences of
2006 Jun 25
1
Puzzled with contour()
Folks, The contour() function wants x and y to be in increasing order. I have a situation where I have a grid in x and y, and associated z values, which looks like this: x y z [1,] 0.00 20 1.000 [2,] 0.00 30 1.000 [3,] 0.00 40 1.000 [4,] 0.00 50 1.000 [5,] 0.00 60 1.000 [6,] 0.00 70 1.000 [7,] 0.00 80 0.000 [8,] 0.00 90
2006 Feb 22
4
exponent confusion
please excuse me if this ones a basic error > y<-c(-0.7,-0.6,-0.5) > -0.7^1.22 [1] -0.6471718 > y^1.22 [1] NaN NaN NaN am I missing something important in my basic math?
2007 Nov 30
0
CentOS-announce Digest, Vol 33, Issue 15
Send CentOS-announce mailing list submissions to centos-announce at centos.org To subscribe or unsubscribe via the World Wide Web, visit http://lists.centos.org/mailman/listinfo/centos-announce or, via email, send a message with subject or body 'help' to centos-announce-request at centos.org You can reach the person managing the list at centos-announce-owner at centos.org When
2005 Jun 22
1
legend
I color some area grey with polygon() (with a red border) and then I want to have the dashed red border in the legend as well. How do I manage it? And I want to mix (latex) expressions with text in my legend. Just execute my lines below and you know want I mean. Or pass by at http://de.wikipedia.org/wiki/Bild:GBM.png to see the picture online. Thomas bm <- function(n=500, from=0, to=1) {
2004 Sep 03
6
seq
Hi everyone, I've tried the below on R 1.9.1 and the 2004-08-30 builds of R 1.9.1 Patched and R 2.0.0 on Windows 2000, and the results are consistent. > seq(0.5, 0, by = -0.1) [1] 0.5 0.4 0.3 0.2 0.1 0.0 > seq(0.7, 0, by = -0.1) [1] 7.000000e-01 6.000000e-01 5.000000e-01 4.000000e-01 3.000000e-01 2.000000e-01 1.000000e-01 -1.110223e-16 Is this really the intended behaviour?
2013 May 07
4
how to calculate the mean in a period of time?
Hi, Your question is still not clear. May be this helps: dat2<- read.table(text=" patient_id????? t???????? scores 1????????????????????? 0??????????????? 1.6 1????????????????????? 1??????????????? 2.6 1????????????????????? 2???????????????? 2.2 1????????????????????? 3???????????????? 1.8 2????????????????????? 0????????????????? 2.3 2?????????????????????? 2???????????????? 2.5
2016 Jan 06
0
opusfiles 0.7 release
I'm pleased to announce the release of opusfile v0.7. The opusfile and opusurl libraries provide a high-level API for decoding and seeking within .opus files on disk or over http(s). Changes since the v0.6 release: - Add API to access and preserve binary metadata. - Add support for R128_ALBUM_GAIN metadata tag. - Better seeking with continued packets and multiplexed streams. - Portability
2013 Aug 24
1
Divide the data into sub data on a particular condition
Hi, Use ?split() #dat1 is the dataset: lst1<- split(dat1,dat1$BaseProd) lst1 #$`2231` ?# BaseProd? CF OSA #1???? 2231 0.5 0.7 #2???? 2231 0.8 0.6 #3???? 2231 0.4 0.8 # #$`2232` ?# BaseProd CF OSA #4???? 2232? 1?? 2 #5???? 2232? 3?? 1 # #$`2233` ?# BaseProd? CF OSA #6???? 2233 0.9 0.5 #7???? 2233 0.7 0.5 #8???? 2233 4.0 5.0 #9???? 2233 5.0 7.0 lst1[[1]] #? BaseProd? CF OSA #1???? 2231 0.5 0.7