Displaying 20 results from an estimated 1785 matches for "0.7".
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0.0
2010 Nov 10
1
Difficult doubt about choose distances randomly in a matrix with a probability of event
I would like to build a model in R to simulate the seed dispersal by one plant.
The plant produced 5 seeds and the probability of falling inside the eight closest space was 0.8 and in the next space 0.2 and in the rest space 0:
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0.8
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0.8
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0.8
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2010 Jan 30
2
convert data frame of values into correlation matrix
Hi Group,
Consider a data frame like this:
mylabel1 <- rep(c("A","B","C"),each=3)
mylabel2 <- rep(c("A","B","C"),3)
corrs <- c(1,.8,.7,.8,1,.7,.7,.7,1)
myData <- data.frame(mylabel1,mylabel2,corrs)
myData
mylabel1 mylabel2 corrs
1 A A 1.0
2 A B 0.8
3 A C 0.7
4 B
2005 Oct 03
3
Problems compiling 3.0.20a with heimdal 0.7
-----BEGIN PGP SIGNED MESSAGE-----
Hash: SHA1
Hi everybodey,
i can't compile 3.0.20 the following message occurs :
Compiling dynconfig.c
In file included from include/includes.h:452,
~ from dynconfig.c:21:
/usr/local/heimdal-0.7/include/krb5.h:660: error: syntax error at '#' token
/usr/local/heimdal-0.7/include/krb5.h:660: warning: no semicolon at end
of struct or
2012 Jul 06
3
estimating NA values against selected slots
Dear R Users,
Could you please help me on the following issue?
I have a real large yearly data set. For each year I have
365 flow values. Some of the flow values are not known and that’s why you will
see NA written in those slots. I wanted to know, is there a way that I can
estimate those values? I tried approx command but it seems least helpful for
the kind of issue I am up against.
2012 Jul 02
4
how to do a graph with tree different colors??
hi
i try to do a graph of a time series which shows in red the values > -0.05,
in blue the values >0.05 and in white the values between -0.05 and 0.05
for un exemple :http://www.appinsys.com/globalwarming/enso.htm
thanks !!!!!
denisse
--
View this message in context: http://r.789695.n4.nabble.com/how-to-do-a-graph-with-tree-different-colors-tp4635206.html
Sent from the R help mailing
2008 Apr 09
1
error linking swfplay
Hi,
swfplay does not link in latest git 0.6.2-384-g234d0b0.
/bin/sh ../libtool --mode=link gcc -g -O2 -o swfplay ../swfdec-gtk/libswfdec-gtk-0.7.la ../swfdec/libswfdec-0.7.la -pthread -lgobject-2.0 -lgthread-2.0 -lrt -lglib-2.0 -lcairo -lpng12 -lz -lgtk-
x11-2.0 -lgdk-x11-2.0 -latk-1.0 -lgdk_pixbuf-2.0 -lm -lpangocairo-1.0 -lpango-1.0 -lcairo -lsoup-2.4 -lgio-2.0 -lgobject-2.0
2012 Feb 02
4
The "less than" (<) operator doesnt seem to perform as expected
The example here puzzles me. It seems like the < operator doesn't work as expected.
> l <- 0.6
> u <- seq(0.4, 0.7, 0.1)
> u
[1] 0.4 0.5 0.6 0.7
> mygrid <- expand.grid("l" = l, "u" = u)
> mygrid
l u
1 0.6 0.4
2 0.6 0.5
3 0.6 0.6
4 0.6 0.7
> mygridcollapsed <- mygrid[mygrid$l < mygrid$u, ]
> mygridcollapsed
l u
3 0.6 0.6
4
2010 Sep 08
11
problem with outer
Hello,
i wrote this function guete and now i want to plot it: but i get this error
message. i hope someone can help me.
Error in dim(robj) <- c(dX, dY) :
dims [product 16] do not match the length of object [1]
p_11=seq(0,0.3,0.1)
p_12=seq(0.1,0.4,0.1)
guete = function(p_11,p_12) {
set.seed(1000)
S_vek=matrix(0,nrow=N,ncol=1)
for(i in 1:N) {
X_0=rmultinom(q-1,size=1,prob=p_0)
2004 Nov 22
4
How to correct this
Hi there,
I tried to add a few circles on an existing figure using the following
codes
grid.circle(x=0.5, y=0.5, r=0.1, draw=TRUE, gp=gpar(col=5))
grid.circle(x=0.5, y=0.5, r=0.3, draw=TRUE, gp=gpar(col=5))
grid.circle(x=0.5, y=0.5, r=0.5, draw=TRUE, gp=gpar(col=5))
points(0.5, 0.5, col = 5) # centre of the circle
, but all circles moved away from the centre. Could we do any
2012 Jul 10
2
estimation of NA by predict command
Dear arun and all R users,
I will first of all try to simply define my issue..
I have data in the following format
Year Discharge
dd/mm/yyyy x
.. …
… …
There are some NA values in the discharge which I would like to predict by using “predict command”. I cant figure out the way to write the coding for that. Could you please help me on that???
I have also ,written
2007 Nov 29
0
CESA-2007:1084 Critical CentOS 3 s390(x) seamonkey - security update
CentOS Errata and Security Advisory 2007:1084
https://rhn.redhat.com/errata/RHSA-2007-1084.html
The following updated files have been uploaded and are currently
syncing to the mirrors:
s390:
updates/s390/RPMS/seamonkey-1.0.9-0.7.el3.centos3.s390.rpm
updates/s390/RPMS/seamonkey-chat-1.0.9-0.7.el3.centos3.s390.rpm
updates/s390/RPMS/seamonkey-devel-1.0.9-0.7.el3.centos3.s390.rpm
2006 Jul 07
2
BUG in " == " ? (PR#9065)
Hello,
here is the version of R that I use :
> version
_
platform i486-pc-linux-gnu
arch i486
os linux-gnu
system i486, linux-gnu
status
major 2
minor 3.1
year 2006
month 06
day 01
svn rev 38247
language R
version.string Version 2.3.1 (2006-06-01)
And here is one of the sequences of
2006 Jun 25
1
Puzzled with contour()
Folks,
The contour() function wants x and y to be in increasing order. I have
a situation where I have a grid in x and y, and associated z values,
which looks like this:
x y z
[1,] 0.00 20 1.000
[2,] 0.00 30 1.000
[3,] 0.00 40 1.000
[4,] 0.00 50 1.000
[5,] 0.00 60 1.000
[6,] 0.00 70 1.000
[7,] 0.00 80 0.000
[8,] 0.00 90
2006 Feb 22
4
exponent confusion
please excuse me if this ones a basic error
> y<-c(-0.7,-0.6,-0.5)
> -0.7^1.22
[1] -0.6471718
> y^1.22
[1] NaN NaN NaN
am I missing something important in my basic math?
2007 Nov 30
0
CentOS-announce Digest, Vol 33, Issue 15
Send CentOS-announce mailing list submissions to
centos-announce at centos.org
To subscribe or unsubscribe via the World Wide Web, visit
http://lists.centos.org/mailman/listinfo/centos-announce
or, via email, send a message with subject or body 'help' to
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You can reach the person managing the list at
centos-announce-owner at centos.org
When
2005 Jun 22
1
legend
I color some area grey with polygon() (with a red border) and then I
want to have the dashed red border in the legend as well. How do I
manage it?
And I want to mix (latex) expressions with text in my legend.
Just execute my lines below and you know want I mean. Or pass by at
http://de.wikipedia.org/wiki/Bild:GBM.png to see the picture online.
Thomas
bm <- function(n=500, from=0, to=1) {
2004 Sep 03
6
seq
Hi everyone,
I've tried the below on R 1.9.1 and the 2004-08-30 builds of R 1.9.1
Patched and R 2.0.0 on Windows 2000, and the results are consistent.
> seq(0.5, 0, by = -0.1)
[1] 0.5 0.4 0.3 0.2 0.1 0.0
> seq(0.7, 0, by = -0.1)
[1] 7.000000e-01 6.000000e-01 5.000000e-01 4.000000e-01 3.000000e-01
2.000000e-01 1.000000e-01 -1.110223e-16
Is this really the intended behaviour?
2013 May 07
4
how to calculate the mean in a period of time?
Hi,
Your question is still not clear.
May be this helps:
dat2<- read.table(text="
patient_id????? t???????? scores
1????????????????????? 0??????????????? 1.6
1????????????????????? 1??????????????? 2.6
1????????????????????? 2???????????????? 2.2
1????????????????????? 3???????????????? 1.8
2????????????????????? 0????????????????? 2.3
2?????????????????????? 2???????????????? 2.5
2016 Jan 06
0
opusfiles 0.7 release
I'm pleased to announce the release of opusfile v0.7.
The opusfile and opusurl libraries provide a high-level API for
decoding and seeking within .opus files on disk or over http(s).
Changes since the v0.6 release:
- Add API to access and preserve binary metadata.
- Add support for R128_ALBUM_GAIN metadata tag.
- Better seeking with continued packets and multiplexed streams.
- Portability
2013 Aug 24
1
Divide the data into sub data on a particular condition
Hi,
Use ?split()
#dat1 is the dataset:
lst1<- split(dat1,dat1$BaseProd)
lst1
#$`2231`
?# BaseProd? CF OSA
#1???? 2231 0.5 0.7
#2???? 2231 0.8 0.6
#3???? 2231 0.4 0.8
#
#$`2232`
?# BaseProd CF OSA
#4???? 2232? 1?? 2
#5???? 2232? 3?? 1
#
#$`2233`
?# BaseProd? CF OSA
#6???? 2233 0.9 0.5
#7???? 2233 0.7 0.5
#8???? 2233 4.0 5.0
#9???? 2233 5.0 7.0
lst1[[1]]
#? BaseProd? CF OSA
#1???? 2231 0.5 0.7