Rails - Apr 2010 - Understand rails routing

Hello,

I''m new to rails so this will be a noob question.

Let''s say I scaffold sth. named "foos".

Rails generates a controller named foos_controller.rb with index,
show, new, edit, create, update and destroy.

The routes.rb contains

map.resources :foos
map.connect '':controller/:action/:id''
map.connect '':controller/:action/:id.:format''

So, by visiting "/foos/new" I can create a new "foo". By
visiting /
foos/new/1 I get routed to the show action with the parameter id=1
that shows the contents of this object. Okay, i get that.

But, what happens when I go to "/foos/1/edit". This is not matching
"map.connect '':controller/:action/:id''" since action
and id are
switched. Is scaffold doing some magic here, that I can''t find in the
sources? When I add a method, say "my_edit" with the exact content of
the "edit" method, i get "Unknown action No action responded to
1.",
what I expected because my URI is not matching the map.connect in the
routes.rb.

Short questions:
How does rails know the routing of /foos/1/edit without the
map.connect?
When i want to create something like that, how do I do that?

Sorry for my poor english.

Greetings from germany.

got_nil

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On Apr 26, 10:58 pm, got_nil
<awesomedomainsh...-gM/Ye1E23mwN+BqQ9rBEUg@public.gmane.org>
wrote:
> But, what happens when I go to "/foos/1/edit". This is not
matching
> "map.connect '':controller/:action/:id''" since
action and id are
> switched. Is scaffold doing some magic here, that I can''t find in
the
> sources? When I add a method, say "my_edit" with the exact
content of
> the "edit" method, i get "Unknown action No action responded
to 1.",
> what I expected because my URI is not matching the map.connect in the
> routes.rb.
>
> Short questions:
> How does rails know the routing of /foos/1/edit without the
> map.connect?
> When i want to create something like that, how do I do that?
>
map.resources is short hand for defining a bunch of routes. See
http://guides.rubyonrails.org/routing.html for more details

Fred

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