Hi,
I''m a new bee to Ruby and I''m trying to parse the html
content from a
website using net/http. All urls work fine except for
"https://www.google.com/accounts/AuthSubRequest?scope=http%3A%2%2Fwww.google.com%2Fcalendar%2Ffeeds%2F&session=0&secure=0&next=http%3A%2F%2Fwww.google.com".
When I try to access this url I get an error like this :
/usr/lib/ruby/1.8/net/protocol.rb:135:in `sysread'': Connection reset by
peer (Errno::ECONNRESET)
from /usr/lib/ruby/1.8/net/protocol.rb:135:in `rbuf_fill''
from /usr/lib/ruby/1.8/timeout.rb:62:in `timeout''
from /usr/lib/ruby/1.8/timeout.rb:93:in `timeout''
from /usr/lib/ruby/1.8/net/protocol.rb:134:in `rbuf_fill''
from /usr/lib/ruby/1.8/net/protocol.rb:116:in `readuntil''
from /usr/lib/ruby/1.8/net/protocol.rb:126:in `readline''
from /usr/lib/ruby/1.8/net/http.rb:2020:in `read_status_line''
from /usr/lib/ruby/1.8/net/http.rb:2009:in `read_new''
from /usr/lib/ruby/1.8/net/http.rb:1050:in `request''
from ./rssModule.rb:40:in `extractor''
from /usr/lib/ruby/1.8/net/http.rb:543:in `start''
from ./rssModule.rb:38:in `extractor''
from ./rssModule.rb:19:in `each''
from ./rssModule.rb:19:in `extractor''
from rss.rb:38
I don''t know exactly about the problem ie. whether it is OS dependent
or
browser dependent etc.. My code snippet is shown below :
uri
URI.parse("https://www.google.com/accounts/AuthSubRequest?scope=http%3A%2%2Fwww.google.com%2Fcalendar%2Ffeeds%2F&session=0&secure=0&next=http%3A%2F%2Fwww.google.com")
header = { "User-Agent"=>"Mozilla/4.0 (compatible; MSIE 5.5;
Windows NT
5.0)" }
http = Net::HTTP.new(uri.host, uri.port)
http.use_ssl()
http.start do |https|
request = Net::HTTP::Get.new(uri.path,
header)
response = https.request(request,
header)
response.value
end
Please help me. I''m in big trouble if I can''t solve it.
Regards
Arun
--
Posted via http://www.ruby-forum.com/.
First, the URL is badly encoded, in the end of the string: http%3A%2%2Fwww...." should be http%3A%2F%2Fwww...." Second, to access a protected resource, it''s not enought just to start a URL with https :) You need to know the login & password, once you know them you can should set them before performing a request: request.basic_auth ''account'', ''password'' Dmitry
Dmitry Sokurenko wrote:> First, the URL is badly encoded, in the end of the string: > http%3A%2%2Fwww...." > should be > http%3A%2F%2Fwww...." > > Second, to access a protected resource, it''s not enought just to start > a URL with https :) > > You need to know the login & password, once you know them you can > should set them before performing a request: > > request.basic_auth ''account'', ''password'' > > DmitryHi, Thanks for the reply. I applied basic authentication and changed the url but still it is showing the same error. Besides can you please tell me is this error generated only for those sites which require basic authentication or this error can be generated for other sites which doesnot require any type of authentication at all. I''ll be pleased to hear from you. Thanking you Regards Arun -- Posted via http://www.ruby-forum.com/.
The error will be generated anytime when the server doesn''t want to talk to you, eg. because of auth failure or service outage. And about basic auth, actually it''s only one of the many ways to authenticate on the web, and I''m sure that Google Account protected services support it. Probably the only way to fullfil such request is to emulate a browser request and store all cookies & headers the google will set. But it won''t be easy, if possible at all. So you''ll better find an API way to access the service, either don''t scrap such URLs. And also I''m quite sure that it violates Google Terms. Dmitry
Dmitry Sokurenko wrote:> The error will be generated anytime when the server doesn''t want to > talk to you, eg. because of auth failure or service outage. > > And about basic auth, actually it''s only one of the many ways to > authenticate on the web, and I''m sure that Google Account protected > services support it. Probably the only way to fullfil such request is > to emulate a browser request and store all cookies & headers the > google will set. But it won''t be easy, if possible at all. So you''ll > better find an API way to access the service, either don''t scrap such > URLs. And also I''m quite sure that it violates Google Terms. > > DmitryHi Dmitry, Thanks very much for the suggestion. Anyway have a few doubts: 1) Is this error has any connection with Connection TimeOut? 2) Is there any possible way to resolve the error other than you mentioned ie. anything I can do to resolve the proble. Thanks again for the quick reply Regards Arun Kumar -- Posted via http://www.ruby-forum.com/.