Peter Browne
2009-Feb-16 15:10 UTC
How do I create a find method that retrieves all of the records that do NOT belong to an association?
I have 3 models with a has_many through association: class Recording has_many :listenings has_many :listeners, :through => :listenings, :source => :user ... end class User has_many :listenings, :foreign_key => "listener_id" has_many :listened_recordings, :foreign_key => "listener_id", :through => :listenings, :source => :recording ... end class Listening belongs_to :recording belongs_to :listener, :class_name => "User" ... end So I can get the recordings the user has listened to, easily with: user.listened_recordings How do create a find method that retrieves all of the recordings the user has not listened to? The way I have been doing it is: Recording.all.reject { |r| listened_recordings.include?(r) } --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Ruby on Rails: Talk" group. To post to this group, send email to rubyonrails-talk-/JYPxA39Uh5TLH3MbocFFw@public.gmane.org To unsubscribe from this group, send email to rubyonrails-talk+unsubscribe-/JYPxA39Uh5TLH3MbocFFw@public.gmane.org For more options, visit this group at http://groups.google.com/group/rubyonrails-talk?hl=en -~----------~----~----~----~------~----~------~--~---
Jeff Lewis
2009-Feb-16 19:52 UTC
Re: How do I create a find method that retrieves all of the records that do NOT belong to an association?
Hi Peter, One way, via two queries would be something like: # in app/models/user.rb: def not_yet_listened_recordings ls = Listening.find_by_sql(["select distinct recording_id from listenings where user_id=?, self.id]) return Recording.find(:all) if not ls or ls.empty? criteria_a = [] vals_a = [] ls.each do |l| criteria_a << "id<>?" vals_a << l.recording_id.to_i end qstr = "select * from recordings where #{criteria_a.join('' and '')}" sql_a = [qstr] + vals_a return Recording.find_by_sql(sql_a) end ... which you would then be able to call like: ... user.not_yet_listened_recordings ... Jeff On Feb 16, 7:10 am, Peter Browne <peterpe...-Re5JQEeQqe8AvxtiuMwx3w@public.gmane.org> wrote:> I have 3 models with a has_many through association: > > class Recording > has_many :listenings > has_many :listeners, :through => :listenings, :source => :user > ... > end > > class User > has_many :listenings, :foreign_key => "listener_id" > has_many :listened_recordings, :foreign_key => > "listener_id", :through => :listenings, :source => :recording > ... > end > > class Listening > belongs_to :recording > belongs_to :listener, :class_name => "User" > ... > end > > So I can get the recordings the user has listened to, easily with: > > user.listened_recordings > > How do create a find method that retrieves all of the recordings the > user has not listened to? > The way I have been doing it is: > > Recording.all.reject { |r| listened_recordings.include?(r) }--~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Ruby on Rails: Talk" group. To post to this group, send email to rubyonrails-talk-/JYPxA39Uh5TLH3MbocFFw@public.gmane.org To unsubscribe from this group, send email to rubyonrails-talk+unsubscribe@googlegroups.com For more options, visit this group at http://groups.google.com/group/rubyonrails-talk?hl=en -~----------~----~----~----~------~----~------~--~---
Peter Browne
2009-Feb-16 21:11 UTC
Re: How do I create a find method that retrieves all of the records that do NOT belong to an association?
Thanks Jeff, I just tried this out and it''s much faster (5-8x) than my method (I''m guessing it''s because it dosen''t have to select * from recordings). On Feb 16, 1:52 pm, Jeff Lewis <jeff.bu...-Re5JQEeQqe8AvxtiuMwx3w@public.gmane.org> wrote:> Hi Peter, > > One way, via two queries would be something like: > > # in app/models/user.rb: > def not_yet_listened_recordings > ls = Listening.find_by_sql(["select distinct recording_id from > listenings where user_id=?, self.id]) > return Recording.find(:all) if not ls or ls.empty? > > criteria_a = [] > vals_a = [] > ls.each do |l| > criteria_a << "id<>?" > vals_a << l.recording_id.to_i > end > qstr = "select * from recordings where #{criteria_a.join('' and > '')}" > sql_a = [qstr] + vals_a > return Recording.find_by_sql(sql_a) > end > > ... > > which you would then be able to call like: > > ... > user.not_yet_listened_recordings > ... > > Jeff > > On Feb 16, 7:10 am, Peter Browne <peterpe...-Re5JQEeQqe8AvxtiuMwx3w@public.gmane.org> wrote: > > > I have 3 models with a has_many through association: > > > class Recording > > has_many :listenings > > has_many :listeners, :through => :listenings, :source => :user > > ... > > end > > > class User > > has_many :listenings, :foreign_key => "listener_id" > > has_many :listened_recordings, :foreign_key => > > "listener_id", :through => :listenings, :source => :recording > > ... > > end > > > class Listening > > belongs_to :recording > > belongs_to :listener, :class_name => "User" > > ... > > end > > > So I can get the recordings the user has listened to, easily with: > > > user.listened_recordings > > > How do create a find method that retrieves all of the recordings the > > user has not listened to? > > The way I have been doing it is: > > > Recording.all.reject { |r| listened_recordings.include?(r) }--~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Ruby on Rails: Talk" group. To post to this group, send email to rubyonrails-talk-/JYPxA39Uh5TLH3MbocFFw@public.gmane.org To unsubscribe from this group, send email to rubyonrails-talk+unsubscribe@googlegroups.com For more options, visit this group at http://groups.google.com/group/rubyonrails-talk?hl=en -~----------~----~----~----~------~----~------~--~---
Frederick Cheung
2009-Feb-16 22:34 UTC
Re: How do I create a find method that retrieves all of the records that do NOT belong to an association?
On Feb 16, 9:11 pm, Peter Browne <peterpe...-Re5JQEeQqe8AvxtiuMwx3w@public.gmane.org> wrote:> Thanks Jeff, > > I just tried this out and it''s much faster (5-8x) than my method (I''m > guessing it''s because it dosen''t have to select * from recordings). >You could also do something like this select recordings.* from recordings left outer join listened_recordings on recording_id = recordings.id and user_id = 12345 where listened_recordings.id IS NULL rewriting that sql as something you can use is left as an exercise to the reader :-) Fred> On Feb 16, 1:52 pm, Jeff Lewis <jeff.bu...-Re5JQEeQqe8AvxtiuMwx3w@public.gmane.org> wrote: > > > Hi Peter, > > > One way, via two queries would be something like: > > > # in app/models/user.rb: > > def not_yet_listened_recordings > > ls = Listening.find_by_sql(["select distinct recording_id from > > listenings where user_id=?, self.id]) > > return Recording.find(:all) if not ls or ls.empty? > > > criteria_a = [] > > vals_a = [] > > ls.each do |l| > > criteria_a << "id<>?" > > vals_a << l.recording_id.to_i > > end > > qstr = "select * from recordings where #{criteria_a.join('' and > > '')}" > > sql_a = [qstr] + vals_a > > return Recording.find_by_sql(sql_a) > > end > > > ... > > > which you would then be able to call like: > > > ... > > user.not_yet_listened_recordings > > ... > > > Jeff > > > On Feb 16, 7:10 am, Peter Browne <peterpe...-Re5JQEeQqe8AvxtiuMwx3w@public.gmane.org> wrote: > > > > I have 3 models with a has_many through association: > > > > class Recording > > > has_many :listenings > > > has_many :listeners, :through => :listenings, :source => :user > > > ... > > > end > > > > class User > > > has_many :listenings, :foreign_key => "listener_id" > > > has_many :listened_recordings, :foreign_key => > > > "listener_id", :through => :listenings, :source => :recording > > > ... > > > end > > > > class Listening > > > belongs_to :recording > > > belongs_to :listener, :class_name => "User" > > > ... > > > end > > > > So I can get the recordings the user has listened to, easily with: > > > > user.listened_recordings > > > > How do create a find method that retrieves all of the recordings the > > > user has not listened to? > > > The way I have been doing it is: > > > > Recording.all.reject { |r| listened_recordings.include?(r) }--~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Ruby on Rails: Talk" group. To post to this group, send email to rubyonrails-talk-/JYPxA39Uh5TLH3MbocFFw@public.gmane.org To unsubscribe from this group, send email to rubyonrails-talk+unsubscribe@googlegroups.com For more options, visit this group at http://groups.google.com/group/rubyonrails-talk?hl=en -~----------~----~----~----~------~----~------~--~---
Peter Browne
2009-Feb-17 01:23 UTC
Re: How do I create a find method that retrieves all of the records that do NOT belong to an association?
Thanks Fred, Here''s how I implemented this method: Recording.find( :all, :joins => "LEFT OUTER JOIN listenings ON recording_id recordings.id AND listener_id = #{self.id}", :conditions => [ "recording_id IS NULL" ] ) I benchmarked the 3 methods (1. mine, 2. Jeff''s, 3. Fred''s): #1 4.540000 0.360000 4.900000 ( 6.359951) #2 0.510000 0.050000 0.560000 ( 0.854199) #3 0.470000 0.040000 0.510000 ( 0.726049) On Feb 16, 4:34 pm, Frederick Cheung <frederick.che...-Re5JQEeQqe8AvxtiuMwx3w@public.gmane.org> wrote:> On Feb 16, 9:11 pm, Peter Browne <peterpe...-Re5JQEeQqe8AvxtiuMwx3w@public.gmane.org> wrote: > > > Thanks Jeff, > > > I just tried this out and it''s much faster (5-8x) than my method (I''m > > guessing it''s because it dosen''t have to select * from recordings). > > You could also do something like this > > select recordings.* from recordings > left outer join listened_recordings on recording_id = recordings.id > and user_id = 12345 > where listened_recordings.id IS NULL > > rewriting that sql as something you can use is left as an exercise to > the reader :-) > > Fred > > > On Feb 16, 1:52 pm, Jeff Lewis <jeff.bu...-Re5JQEeQqe8AvxtiuMwx3w@public.gmane.org> wrote: > > > > Hi Peter, > > > > One way, via two queries would be something like: > > > > # in app/models/user.rb: > > > def not_yet_listened_recordings > > > ls = Listening.find_by_sql(["select distinct recording_id from > > > listenings where user_id=?, self.id]) > > > return Recording.find(:all) if not ls or ls.empty? > > > > criteria_a = [] > > > vals_a = [] > > > ls.each do |l| > > > criteria_a << "id<>?" > > > vals_a << l.recording_id.to_i > > > end > > > qstr = "select * from recordings where #{criteria_a.join('' and > > > '')}" > > > sql_a = [qstr] + vals_a > > > return Recording.find_by_sql(sql_a) > > > end > > > > ... > > > > which you would then be able to call like: > > > > ... > > > user.not_yet_listened_recordings > > > ... > > > > Jeff > > > > On Feb 16, 7:10 am, Peter Browne <peterpe...-Re5JQEeQqe8AvxtiuMwx3w@public.gmane.org> wrote: > > > > > I have 3 models with a has_many through association: > > > > > class Recording > > > > has_many :listenings > > > > has_many :listeners, :through => :listenings, :source => :user > > > > ... > > > > end > > > > > class User > > > > has_many :listenings, :foreign_key => "listener_id" > > > > has_many :listened_recordings, :foreign_key => > > > > "listener_id", :through => :listenings, :source => :recording > > > > ... > > > > end > > > > > class Listening > > > > belongs_to :recording > > > > belongs_to :listener, :class_name => "User" > > > > ... > > > > end > > > > > So I can get the recordings the user has listened to, easily with: > > > > > user.listened_recordings > > > > > How do create a find method that retrieves all of the recordings the > > > > user has not listened to? > > > > The way I have been doing it is: > > > > > Recording.all.reject { |r| listened_recordings.include?(r) }--~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Ruby on Rails: Talk" group. To post to this group, send email to rubyonrails-talk-/JYPxA39Uh5TLH3MbocFFw@public.gmane.org To unsubscribe from this group, send email to rubyonrails-talk+unsubscribe@googlegroups.com For more options, visit this group at http://groups.google.com/group/rubyonrails-talk?hl=en -~----------~----~----~----~------~----~------~--~---
Matt Jones
2009-Feb-17 23:33 UTC
Re: How do I create a find method that retrieves all of the records that do NOT belong to an association?
On Jeff''s method, one quick optimization would be to switch to using a NOT IN query: # in app/models/user.rb: def not_yet_listened_recordings ls = Listening.find_by_sql(["select distinct recording_id from listenings where user_id=?, self.id]) return Recording.find(:all) if not ls or ls.empty? Recording.find(:all, :conditions => [''id NOT IN (?)'', ls]) end A lot less code for the same result... Overall though, the Fred''s LEFT OUTER JOIN thing is much more elegant; it also lends itself to being used as a named scope - which you''ll want when it comes time to paginate the list. Example: # in recording.rb: named_scope :not_listened, lambda { |u| { :joins => "LEFT OUTER JOIN listenings ON recording_id = recordings.id AND listener_id = # {u.id}", :conditions => [ "recording_id IS NULL" ] } } Then you could have a controller action (using mislav-will_paginate); def show_not_listened # get a user object somehow - either logged in user or from params @recordings = Recording.not_listened(user).paginate(params[:page] || 1) end --Matt Jones --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Ruby on Rails: Talk" group. To post to this group, send email to rubyonrails-talk-/JYPxA39Uh5TLH3MbocFFw@public.gmane.org To unsubscribe from this group, send email to rubyonrails-talk+unsubscribe-/JYPxA39Uh5TLH3MbocFFw@public.gmane.org For more options, visit this group at http://groups.google.com/group/rubyonrails-talk?hl=en -~----------~----~----~----~------~----~------~--~---