Rails - Sep 2008 - [How to pass argument from a script to rails...]

I have a script with which I want to create a rails app.

Then not something like:

$ rails -d mysql name_app

in terminal, but from the script.

In the script I get the app name, database etc.
After some operations I would like to create the app from the script,
but when I try something like

`rails"#{ARGV}"`

where ARGV = name_app-d mysql

creates the app with a name like name_app-dmysql.

How can I pass ARGV to successfully create the app?
Thank you
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would ARGV.join(" ") help?

Ruby is using to_s behind the scenes. Calling to_s on an array returns
the values concatenated together in a string
>> [1,2,3].to_s
=> "123"

On Sep 27, 9:35 pm, Max Dev
<rails-mailing-l...-ARtvInVfO7ksV2N9l4h3zg@public.gmane.org>
wrote:
> I have a script with which I want to create a rails app.
>
> Then not something like:
>
> $ rails -d mysql name_app
>
> in terminal, but from the script.
>
> In the script I get the app name, database etc.
> After some operations I would like to create the app from the script,
> but when I try something like
>
> `rails"#{ARGV}"`
>
> where ARGV = name_app-d mysql
>
> creates the app with a name like name_app-dmysql.
>
> How can I pass ARGV to successfully create the app?
> Thank you
> --
> Posted viahttp://www.ruby-forum.com/.
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On 28 Sep 2008, at 02:35, Max Dev
<rails-mailing-list-ARtvInVfO7ksV2N9l4h3zg@public.gmane.org>
wrote:
>
> I have a script with which I want to create a rails app.
>
> Then not something like:
>
> $ rails -d mysql name_app
>
> in terminal, but from the script.
>
> In the script I get the app name, database etc.
> After some operations I would like to create the app from the script,
> but when I try something like
>
> `rails"#{ARGV}"`
>
> where ARGV = name_app-d mysql
>
> creates the app with a name like name_app-dmysql.
>
> How can I pass ARGV to successfully create the app?
> Thank you
Have you looked at what #{ARGV} evaluates to? The default to_s on  
arrays just concatenates the elements, whereas you want to have a  
space between them which join will do. On top of that you''ve put "
round that which will tell the shell ''all this should be one
argument''.

Fred
>
> -- 
> Posted via http://www.ruby-forum.com/.
>
> >
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Thank you for replies.
> Have you looked at what #{ARGV} evaluates to?
> would ARGV.join(" ") help?
Yes, this works well with a call like:

system (or sh) ("''rails'' #{ARGV.join(''
'')}")

but not with:

`"''rails'' #{ARGV.join('' '')}"`

sh: ''rails''  prova -d mysql: not found

I tried different forms, including with join. My real mistake was that I 
was using the notation ``

What''s the difference?
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On Sep 28, 4:20 pm, Max Dev
<rails-mailing-l...-ARtvInVfO7ksV2N9l4h3zg@public.gmane.org>
wrote:
> Thank you for replies.
>
> > Have you looked at what #{ARGV} evaluates to?
> > would ARGV.join(" ") help?
>
> Yes, this works well with a call like:
>
> system (or sh) ("''rails'' #{ARGV.join(''
'')}")
>
> but not with:
>
> `"''rails'' #{ARGV.join('' '')}"`
>
> sh: ''rails''  prova -d mysql: not found
>
> I tried different forms, including with join. My real mistake was that I
> was using the notation ``
There''s nothing wrong with using ``, except that you''re
quoting rather
excessively

`rails #{ARGV.join('' '')}`

is fine, as is

system("rails #{ARGV.join('' '')}")

but `"rails ..."` isn''t. `` is already a quoting operator so
you don''t
need the quotes (which makes the shell believe you want to run a
command called "rails -d mysql some_app" (ie it will look for
something whose filename is that whole string) whereas you want to run
a command called "rails" but passing those arguments.

Fred
>
> What''s the difference?
> --
> Posted viahttp://www.ruby-forum.com/.
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Thank you very much Frederick,

this has opened my eyes. Then, my mistake was to believe that I need
""
for interpolation in ``.
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