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Edgar Gonzalez

2007-Jun-14 04:35 UTC

Help with this code

Hello,

I am doing a menu and i got this code,, what i want is to print the
categories and subcategories but with the products on all of these
categories.

Actually i am printing the categories and subcategories of each one, but
how can i print the products of each categorie?, What error i have?


These are my helpers methods:


def display_categories(categories, parent_id)
    ret = "<ul>"
      for category in categories
        if category.parent_id == parent_id
          ret << display_category(category)
        end
      end
    ret << "</ul>"
  end

  def display_category(category)

  cm = "&nbsp;&nbsp;>>"

    ret = "<li>"
  ret << "<a
href=\"#\"><span>#{category.nombre}#{cm if
category.children.any?}</span></a>"
    ret << display_products(category)
  ret << display_categories(category.children, category.id)
   ret << "</li>"
  end

  def display_products(category)
    ps = Product.find_all_by_category_id(category)
    for p in ps
         ret = "<li>"
         ret << link_to_remote(
"<span>#{p.nombre}</span>",
                        :url=>{:action => "prod_id", :id =>
p.id},
                        :update => ''info'')
         ret << "</li>"
    end
  end

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shai

2007-Jun-14 07:12 UTC

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Re: Help with this code

...seems kinda rough;
why not do something like this:

def display_categories(categories, p_id)
list=<<EOF
 <ul>
  <% for c in categories %>
    <li><%= c if c.parent_id==p_id %></li>
....
....
....
    #  AND HERE DO:
    <ul>
      <li><%= c.product %></li>
    </ul>
  <% end %>
 </ul>
EOF
list # last statement in def is the value returned
end


the c.product call will bring forth the product that is associated with 
c.
(i.e, if c.id=X then product.category_id=X)
the only thing u need to assure is that in your category model, the 
association is defined.

hth,

shai


Edgar Gonzalez wrote:> Hello,
> 
> I am doing a menu and i got this code,, what i want is to print the
> categories and subcategories but with the products on all of these
> categories.
> 
> Actually i am printing the categories and subcategories of each one, but
> how can i print the products of each categorie?, What error i have?
> 
> 
> These are my helpers methods:
> 
> 
> def display_categories(categories, parent_id)
>     ret = "<ul>"
>       for category in categories
>         if category.parent_id == parent_id
>           ret << display_category(category)
>         end
>       end
>     ret << "</ul>"
>   end
> 
>   def display_category(category)
> 
>   cm = "&nbsp;&nbsp;>>"
> 
>     ret = "<li>"
>   ret << "<a
href=\"#\"><span>#{category.nombre}#{cm if
> category.children.any?}</span></a>"
>     ret << display_products(category)
>   ret << display_categories(category.children, category.id)
>    ret << "</li>"
>   end
> 
>   def display_products(category)
>     ps = Product.find_all_by_category_id(category)
>     for p in ps
>          ret = "<li>"
>          ret << link_to_remote(
"<span>#{p.nombre}</span>",
>                         :url=>{:action => "prod_id", :id
=> p.id},
>                         :update => ''info'')
>          ret << "</li>"
>     end
>   end

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Edgar Gonzalez

2007-Jun-14 15:15 UTC

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Re: Help with this code

What is list=<<EOF?
shai wrote:> ...seems kinda rough;
> why not do something like this:
> 
> def display_categories(categories, p_id)
> list=<<EOF
>  <ul>
>   <% for c in categories %>
>     <li><%= c if c.parent_id==p_id %></li>
-- 
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Hugh Sasse

2007-Jun-14 15:40 UTC

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Re: Help with this code

On Thu, 14 Jun 2007, Edgar Gonzalez wrote:
> 
> What is list=<<EOF?
Assignment from ''here document'' (document directly embedded in
the source)

http://ruby.about.com/od/learnruby/p/here_document.htm

has examples.

        Hugh

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Edgar Gonzalez

2007-Jun-15 04:12 UTC

head link

Re: Help with this code

Now i got this to display the products:

  def display_products(category)

    category.productos.each do |p|
        ret = "<li>"
        ret << link_to_remote(
"<span>#{p.nombre}</span>",
                        :url=>{:action => "prod_id", :id =>
p.id},
                        :update => ''info'')
        ret << "</li>"
    end
  end




but it present an error:

can''t convert Array into String




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Daniel N

2007-Jun-15 04:22 UTC

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Re: Help with this code

On 6/15/07, Edgar Gonzalez
<rails-mailing-list-ARtvInVfO7ksV2N9l4h3zg@public.gmane.org>
wrote:>
>
> Now i got this to display the products:
>
>   def display_products(category)
>
>     category.productos.each do |p|
>         ret = "<li>"
>         ret << link_to_remote(
"<span>#{p.nombre}</span>",
>                         :url=>{:action => "prod_id", :id
=> p.id},
>                         :update => ''info'')
>         ret << "</li>"
>     end
>   end
>
>
>
>
> but it present an error:
>
> can''t convert Array into String

this is because your display_products returns category.productos which is an
Array (sort of)

This is the last statement in your method.  The each loop is basically
spinning it''s wheels.

ret = "<li>"  # Makes a new string at the beginning of each loop
...
ret << "</li>"

At the end of the block you have a string.  But you don''t do anything
with
it.

Perhaps if you collected the results of each loop in an array and then
joined them.  eg

def display_products(category)

    category.productos.map do |p|
        ret = "<li>"
        ret << link_to_remote(
"<span>#{p.nombre}</span>",
                        :url=>{:action => "prod_id", :id =>
p.id},
                        :update => ''info'')
        ret << "</li>"
    end.join
  end


 This would return the finished string at the end of the method.

There has to be a cleaner way though.  Like just appending to the view
buffer directly.

Hope this helps
Daniel

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Rails - Jun 2007 - Help with this code

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