Rails - Dec 2006 - Presenting a grouped list of objects from STI

Hello,

I have been following the STI example in AWDWR and have a question about
presenting the output.

I want to output a list of Person objects that are grouped by their
type.

I have an array of all the Person objects and I would like the output to
be as follows.

Employee x3
<ul>
<li>Employee 1</li>
<li>Employee 2</li>
<li>Employee 3</li>
</ul>
Manager x2
<ul>
<li>Manager 1</li>
<li>Manager 2</li>
</ul>
 ... etc

What is the best method for building the output in the view?  Should I
use acts_as_list or tree?  You''ll notice I also want to have the count
for each type.  Is there a built in way to do this or should I hack
something together?

Thank you,
Ryan Glover

-- 
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On Dec 31, 2:58 pm, Ryan Glover
<rails-mailing-l...-ARtvInVfO7ksV2N9l4h3zg@public.gmane.org>
wrote:
> Hello,
>
> I have been following the STI example in AWDWR and have a question about
> presenting the output.
>
> I want to output a list of Person objects that are grouped by their
> type.
>
> I have an array of all the Person objects and I would like the output to
> be as follows.
>
> Employee x3
> <ul>
> <li>Employee 1</li>
> <li>Employee 2</li>
> <li>Employee 3</li>
> </ul>
> Manager x2
> <ul>
> <li>Manager 1</li>
> <li>Manager 2</li>
> </ul>
>  ... etc
>
> What is the best method for building the output in the view?  Should I
> use acts_as_list or tree?  You''ll notice I also want to have the
count
> for each type.  Is there a built in way to do this or should I hack
> something together?
I would just pull each group out separately in the controller:

  @employees = Employee.find(:all)
  @managers = Manager.find(:all)

It''s then simple to count and list them out in the view.

Best,

-r
>
> Thank you,
> Ryan Glover
>
> --
> Posted viahttp://www.ruby-forum.com/.
--
Ryan Raaum
http://raaum.org
http://rails.raaum.org -- Rails docs
http://locomotive.raaum.org -- Self contained Rails for Mac OS X


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Ryan Glover wrote:
> What is the best method for building the output in the view?  Should I
> use acts_as_list or tree?  You''ll notice I also want to have the
count
> for each type.  Is there a built in way to do this or should I hack
> something together?
I would use Enumerable#group_by

@people = Person.find(:all)
@people_by_type = @people.group_by(&:class)

Number of managers: @people_by_type[Manager].size
Number of employees: @people_by_type[Employee].size
etc.

To loop through:
<% for klass in @people_by_type.keys %>
  <% for person in @people_by_type[klass] %>
    .....

Dan Manges


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