R help - Oct 2014 - lappy and xts get all indexes from a list ?

Dear all,

I have a list , and I want to get all indexes ( dates ) of xts objects  in one
list:

foo<-list(A = xts(seq(2),seq(Sys.Date(),Sys.Date()+2,length.out=2)), B =
xts(seq(1),seq(Sys.Date()-2,Sys.Date()-1,length.out=1)) )
> foo
$A
           [,1]
2014-10-31    1
2014-11-02    2

$B
           [,1]
2014-10-29    1

lapply(foo, function(x) index(x))      gives A and B values separately . I want
to get one list like :

"2014-10-31" "2014-11-02" "2014-10-29"

Thanks a lot.

I do this a few times in the blotter package.  Try:
Dates <- unique(do.call(c,c(lapply(foo, index), use.names=FALSE,
recursive=FALSE)))


On Fri, Oct 31, 2014 at 11:44 AM, ce <zadig_1 at excite.com>
wrote:
> Dear all,
>
> I have a list , and I want to get all indexes ( dates ) of xts objects  in
one list:
>
> foo<-list(A = xts(seq(2),seq(Sys.Date(),Sys.Date()+2,length.out=2)), B =
xts(seq(1),seq(Sys.Date()-2,Sys.Date()-1,length.out=1)) )
>
>> foo
> $A
>            [,1]
> 2014-10-31    1
> 2014-11-02    2
>
> $B
>            [,1]
> 2014-10-29    1
>
> lapply(foo, function(x) index(x))      gives A and B values separately . I
want to get one list like :
>
> "2014-10-31" "2014-11-02" "2014-10-29"
>
> Thanks a lot.
>
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