Rich,
If your data frame is called df, try
row.names(df) <- df$sampdate
Jean
On Thu, Jun 19, 2014 at 5:07 PM, Rich Shepard <rshepard@appl-ecosys.com>
wrote:
> I recall reading how to do this somewhere, but I cannot find just where I
> read it. I have compositional data frames of this format:
>
> sampdate filter gather graze predate shred
> 1 2000-07-18 0.0550 0.5596 0.0734 0.2294 0.0826
> 2 2003-07-08 0.0734 0.6147 0.0183 0.2294 0.0642
> 3 2005-07-13 0.1161 0.5714 0.0357 0.1696 0.1071
> 4 2006-06-28 0.1000 0.4667 0.1500 0.1333 0.1500
> 5 2010-09-14 0.0778 0.6111 0.0444 0.1889 0.0778
> 6 2011-07-13 0.0879 0.5714 0.0659 0.2747 0.0000
> 7 2012-07-11 0.1042 0.5313 0.0625 0.2396 0.0625
>
> and the sampdate column should be the row headings rather than the numeric
> sequence seen above. What is the command to move the sampdates to row
> headers?
>
> Rich
>
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