One answer to your question might be ?get. A way better answer is to never use
assign to create xx1 etc in the first place but to store those results in a list
that you can simply index later. If you were to create a reproducible example
[1] by defining mydata you would be more likely to get an actual example
solution in response to your question.
[1]
http://stackoverflow.com/questions/5963269/how-to-make-a-great-r-reproducible-example
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Sent from my phone. Please excuse my brevity.
On May 10, 2014 2:07:29 AM PDT, Marco Chiapello <chiapello.m at gmail.com>
wrote:>I'd like to create several tables in which my data are stored.
>I did the follow:
>
> x<-mydata
> splitted<-split(x[,1],x[,2])
>
> #Create my function for the tables
> fxdata<-function(){
>
y.row=c("0","1","2","3","4","5")
> yy=c(rep(0,6))
> w=data.frame(A3=yy,A2=yy,A1=yy,A0=yy)
> rownames(w)<-y.row}
>
> #Create the tables
> xx<-NULL
> for (i in 1:dim(x)[2]){
> assign(paste("xx",i,sep=""),fxdata())}
>
>So, I created, for example, 3 tables: xx1, xx2 and xx3. Now I have to
>populate the tables and here I have the problem. I do not know how to
>recall xx1, xx2 or xx3 in a loop. The idea is insert the follow loop in
>the previous one, in order to populate all the tables.
>
> #Populate the table
> for (ii in 1:length(splitted[[1]]{
> #IF 0
> if (splitted[[1]][ii] == "0"){
> y[1,4]=y[1,4]+1}
> #IF A0
> if (splitted[[1]][ii] == "1A0"){
> y[2,4]=y[2,4]+1}
> if (splitted[[1]][ii] == "2A0"){
> y[3,4]=y[3,4]+1}
> if (splitted[[1]][ii] == "3A0"){
> y[4,4]=y[4,4]+1}
> ...}
>
>The question is: what I have to write in place of "y" in the last
loop
>in order to refer to xx1, xx2 or xx3?? I want to write something like:
>
> for (i in 1:3) {
> xxi<-1}
>
>Thank you for any advice.
>
>Marco
>______________________________________________
>R-help at r-project.org mailing list
>https://stat.ethz.ch/mailman/listinfo/r-help
>PLEASE do read the posting guide
>http://www.R-project.org/posting-guide.html
>and provide commented, minimal, self-contained, reproducible code.