Hi, I am fitting a weibull model as follows my models is s <- Surv(DFBR$Time,DFBR$Censor) wei <- survreg(s~Group+UsefulLife,data = DFBR,dist="weibull") How can i predict the probabilty of failure in next 10 days, for a new data with group =10 and usefuleLife =100 Thx shilpi [[alternative HTML version deleted]]
Perhaps: G10 <- predict(wei, list(Group =10 , UsefulLife =10), type="response") You should get a single km-type object and will need to extract a time-specific value. (You really _should_ post what you have tried.) -- David Sent from my iPhone Sent from my iPhone> On Mar 14, 2014, at 9:11 PM, shilpi harpavat <tshilpi at hotmail.com> wrote: > > Hi, > I am fitting a weibull model as follows > my models is > > s <- Surv(DFBR$Time,DFBR$Censor) > > wei <- survreg(s~Group+UsefulLife,data = DFBR,dist="weibull") > > > > How can i predict the probabilty of failure in next 10 days, for a new data with group =10 and usefuleLife =100 > Thx > shilpi > [[alternative HTML version deleted]] > > ______________________________________________ > R-help at r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code.
Perhaps: G10 <- predict(wei, list(Group =10 , UsefulLife =10), type="response") You should get a single km-type object and will need to extract a time-specific value. (You really _should_ post what you have tried.) -- David Sent from my iPhone> On Mar 14, 2014, at 7:11 PM, shilpi harpavat <tshilpi at hotmail.com> wrote: > > Hi, > I am fitting a weibull model as follows > my models is > > s <- Surv(DFBR$Time,DFBR$Censor) > > wei <- survreg(s~Group+UsefulLife,data = DFBR,dist="weibull") > > > > How can i predict the probabilty of failure in next 10 days, for a new data with group =10 and usefuleLife =100 > Thx > shilpi > [[alternative HTML version deleted]] > > ______________________________________________ > R-help at r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code.
Perhaps: G10 <- predict(wei, list(Group =10 , UsefulLife =10), type="response") You should get a single km-type object and will need to extract a time-specific value. (You really _should_ post what you have tried.) -- David Sent from my iPhone> On Mar 14, 2014, at 7:11 PM, shilpi harpavat <tshilpi at hotmail.com> wrote: > > Hi, > I am fitting a weibull model as follows > my models is > > s <- Surv(DFBR$Time,DFBR$Censor) > > wei <- survreg(s~Group+UsefulLife,data = DFBR,dist="weibull") > > > > How can i predict the probabilty of failure in next 10 days, for a new data with group =10 and usefuleLife =100 > Thx > shilpi > [[alternative HTML version deleted]] > > ______________________________________________ > R-help at r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code.