So are the names of the columns in the dataset x, y, and z? or are
they area, concentration, and year? you seem to be mixing these
together? If you provide a minimal reproducible example (provide some
data with dput, or the commands to generate random data, or use a
built in dataset) then it makes it easier for us to help you.
Is the z/year variable a set of character strings? a factor? or a
numeric/integer variable?
Assuming the column names are x, y, and z and that z is the numeric
year and data is a data frame, then here are some options that should
work:
plot( data$x[ data$z >= 2012 ], data$y[ data$z >= 2012 )
with( data[ data$z >= 2012, ], plot(x,y) )
plot( y~x, data=data, subset= z >= 2012 )
Also see `fortune("dog")` about choosing names for data frames.
On Mon, Feb 17, 2014 at 9:18 AM, arun <smartpink111 at yahoo.com>
wrote:> Hi,
> Try:
> set.seed(49)
> dat1 <- data.frame(year=
rep(2010:2013,c(10,8,9,13)),x=sample(1e4,40,replace=TRUE),y=sample(40,40,replace=TRUE))
> plot(x~y,data=dat1,subset=year > 2012)
> #or
> with(subset(dat1,year > 2012),plot(y,x))
>
>
> A.K.
>
>
>
> Hi R people
>
> This might take me the whole day to figure out, instead I will ask so I can
save some PhD time.
>
> I want to plot a subset of my data.
>
> x = area
> y = concentration
>
> these data are sorted by
>
> z = year (2008 to 2013)
>
> So I want to make a plot where I can see x and y >=2012 and <2012.
>
> I have tied
> plot(data$y[year>='2012'], x[year>='2012']) That did
not work.
>
> also plot(data$y, data$x, year>'2012') did not give the right
data plot
>
> Any suggestions on how to do this would be appreciated.
> thanks
>
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--
Gregory (Greg) L. Snow Ph.D.
538280 at gmail.com