Yes.
And there's also a possibility of keeping the vector as a one column
data frame (using a drop=FALSE argument in indexing to avoid
conversion to vectors perhaps) so that nrow() can be used. This has
the disadvantage of the inefficiency of using a data frame when a
vector will do, and the advantage of avoiding the test.
Cheers,
Bert
Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374
"Data is not information. Information is not knowledge. And knowledge
is certainly not wisdom."
H. Gilbert Welch
On Fri, Feb 14, 2014 at 7:44 AM, Jorge I Velez <jorgeivanvelez at
gmail.com> wrote:> Hi Berry,
>
> What about using
>
> NROW(input)
>
> ?
>
> Best,
> Jorge.-
>
>
> On Sat, Feb 15, 2014 at 2:26 AM, Berry Boessenkool <
> berryboessenkool at hotmail.com> wrote:
>
>> Hi,
>>
>> In my function, I want to allow input to be a vector or a data.frame.
>> Certain operations need to be done if the length or nrows exceeds one,
but
>> since "nrow" doesn't work for vectors, I cannot simply
use
>>
>> if( nrow(input)>1 | length(input)>1 ) ...
>>
>> So is there a more elegant way to do this then with the following code?
>>
>> if( if(is.vector(input)) length(input)>1 else nrow(input)>1 )
...
>>
>> thanks ahead,
>> Berry
>> ______________________________________________
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>> PLEASE do read the posting guide
>> http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>>
>
> [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help at r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.