Hi
Maybe I am missing something but isn't this
which(letters %in% c("a", "x"))
what you want?
Petr
> -----Original Message-----
> From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-
> project.org] On Behalf Of Rainer M Krug
> Sent: Thursday, February 13, 2014 3:43 PM
> To: R-help at r-project.org
> Subject: [R] grep for multiple pattern?
>
> Hi
>
> I want to search for multiple pattern as grep is doing for a single
> pattern, but this obviously not work:
>
> > grep("an", month.name)
> [1] 1
> > grep("em", month.name)
> [1] 9 11 12
> > grep("eb", month.name)
> [1] 2
> > grep(c("an", "em", "eb"), month.name)
> [1] 1
> Warning message:
> In grep(c("an", "em", "eb"), month.name) :
> argument 'pattern' has length > 1 and only the first element
will be
> used
> >
>
> Is there an equivalent which returns the positions as grep is doing,
> but not using the strict full-string matching of match()?
>
> I could obviously do:
>
> > unlist( sapply(pat, grep, month.name ) )
> an em1 em2 em3 eb
> 1 9 11 12 2
>
> but is there a more compact command I am missing?
>
> Thanks,
>
> Rainer
>
> --
> Rainer M. Krug, PhD (Conservation Ecology, SUN), MSc (Conservation
> Biology, UCT), Dipl. Phys. (Germany)
>
> Centre of Excellence for Invasion Biology Stellenbosch University South
> Africa
>
> Tel : +33 - (0)9 53 10 27 44
> Cell: +33 - (0)6 85 62 59 98
> Fax : +33 - (0)9 58 10 27 44
>
> Fax (D): +49 - (0)3 21 21 25 22 44
>
> email: Rainer at krugs.de
>
> Skype: RMkrug
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