R help - Jan 2014 - Three values that add to the same number by 0.01 steps

Hi,
May be this helps:
?set.seed(85)
?mat1 <- matrix(sample(seq(0,1,by=0.01),360000,replace=TRUE),ncol=3)
mat2 <- mat1[sprintf("%.2f",rowSums(mat1))=="1.00",]
?any(!rowSums(mat2))
#[1] FALSE
A.K.


Hi, 

I'd like to create a matrix with three columns so that each 
element is between 0 and 1 and each row always adds to 1. So, if in the 
same row the columns are x1, x2, and x3 and x1 =1, then x2 = 0 and x3 = 
0. Or if x1 = .03, then x2 = .97 and x3 = 0. Or... x1 = .05, x2 = .01, 
x3 = .94. 

Basically so it accounts for all values of x1,x2,x3 that add up to 1 with the
sequence by 0.01.

I tried a nested seq (if that is even possible), but that didn't work. 

Is there a way to do this? Perhaps a package that I don't know about?

> I'd like to create a matrix with three columns so that each element is
> between 0 and 1 and each row always adds to 1. So, if in the same row the
You could start with expand.grid

m <- expand.grid(x1=0:100, x2=0:100)  #Avoids comparing floats
m <- m[rowSums(m)<=100,]                    #Throw away the oversized ones
m <- cbind(m, x3=100-rowSums(m))   #Get the final column
m <- m/100                                                     #Scale to
[0,1]

table(rowSums(m))  


S Ellison



*******************************************************************
This email and any attachments are confidential. Any use...{{dropped:8}}