You don't need to wrap 1:12 in c().
Since matrices are just folded vectors, you can convert vector X to a matrix
Xm:
Xm <- matrix( X, nrow=3 )
and access columns to get your your sub-vectors:
Xm[,1]
Xm[,2]
and so on.
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Sent from my phone. Please excuse my brevity.
Long Vo <long_vo_hai at yahoo.com.vn> wrote:>Hi, I am quite new to R so I know that this probably is very basic ,
>but how
>can I split a sequence of number into multiple parts with equal length?
>For example I have a vector
>
>X=c(1:12)
>I simply need to split it into sub-vectors with the same length N . Say
>N=3
>then I need the output to be like
>1 2 3
>4 5 6
>7 8 9
>10 11 12
>
>And better if the sub-vectors can be named so that I can use them later
>for
>individual study, probably a do-loop in which a function can be applied
>to
>them.
>I just want them to be in consecutive order so really no fancy
>conditions
>here.
>
>Any helps to this amateur is greatly appreciated,
>Long
>
>
>
>--
>View this message in context:
>http://r.789695.n4.nabble.com/Splitting-a-vector-tp4681930.html
>Sent from the R help mailing list archive at Nabble.com.
>
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