R help - Dec 2013 - How to use multiple test for trend in proportions?

dataorder.csv <http://r.789695.n4.nabble.com/file/n4681879/dataorder.csv> 
I
have a set of data as attached.Like (181,246,378).....(180,228,378)And I
want to use test for trend in proportions using (400,500,600) as denominator
and get 119 p-valuesSo I use the code as
below:data=read.table("dataorder.csv", sep=",", 
stringsAsFactors=F)i
<-1:nrow(data)n <- c(400,500,600)e <-
data[i,c(1,2,3)]prop.trend.test(e,
n)allpvalue = apply(data, 1, function(x) { prop.trend.test(e, n)$p.value
})However, there is something wrong but I can't figure out, can anybody
help? Thanks



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On Dec 9, 2013, at 9:46 AM, celebrex wrote:
> dataorder.csv
<http://r.789695.n4.nabble.com/file/n4681879/dataorder.csv>
>  I have a set of data as attached.Like (181,246,378).....(180,228,378). And
I
> want to use test for trend in proportions using (400,500,600) as
denominator
> and get 119 p-values. So I use the code as
> below:
Reformatted:
> 
> data=read.table("dataorder.csv", sep=",", 
stringsAsFactors=F)
> 
> i<-1:nrow(data)
> n <- c(400,500,600)
> e <- data[i,c(1,2,3)]
What is your intent with that command?

> prop.trend.test(e, n)
> 
> allpvalue = apply(data, 1, function(x) { prop.trend.test(e, n)$p.value})
In the function body there is no reference to "x". Did you intend
this:

   allpvalue = apply(data, 1, function(x) { prop.trend.test(x, n)$p.value})

> However, there is something wrong but I can't figure out, can anybody
> help? Thanks
Posting from Nabble often screws up formatting,  as it did big-time in your
case. It is possible to post in plain text from Nabble, so you should now take
the time to learn how to do that.
> View this message in context:
http://r.789695.n4.nabble.com/How-to-use-multiple-test-for-trend-in-proportions-tp4681879.html
> Sent from the R help mailing list archive at Nabble.com.
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David Winsemius
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