R help - Sep 2013 - replace.df() function in R

Hello -

I have read about a function, replace.df(), that is available in base R. It
seems ideal since it would allow me to replace specific columns in one data
frame with columns in another data frame, while keeping all other columns
intact. The problem is that replace.df() does not seem to exist as a
function. Can anyone confirm this or provide the library in which it is
located? If it does not exist, is there another way to perform this column
specific replacement?

practice <- read.csv("data.csv", header=T)
practice1 <- aggregate(practice[, c(8,9,10,11,12,27,28)],
by=list(practice$codenumber), FUN=function(x) sub("(.*):",
"\\1.", x))
practice2 <- replace.df(practice, practice1, by=c("codenumber"),
cols=c(8,9,10,11,12,27,28))
>>Error: could not find function "replace.df"
Thank you.

Alecia

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Hello,

This function doesn't exist in any package. I found it using a web search
engine (estimated time, 30sec):
http://stackoverflow.com/questions/7971513/using-one-data-frame-to-update-another

Regards,
Pascal



2013/9/19 Alecia M Moser <amoser1@binghamton.edu>
> Hello -
>
> I have read about a function, replace.df(), that is available in base R. It
> seems ideal since it would allow me to replace specific columns in one data
> frame with columns in another data frame, while keeping all other columns
> intact. The problem is that replace.df() does not seem to exist as a
> function. Can anyone confirm this or provide the library in which it is
> located? If it does not exist, is there another way to perform this column
> specific replacement?
>
> practice <- read.csv("data.csv", header=T)
> practice1 <- aggregate(practice[, c(8,9,10,11,12,27,28)],
> by=list(practice$codenumber), FUN=function(x) sub("(.*):",
"\\1.", x))
> practice2 <- replace.df(practice, practice1,
by=c("codenumber"),
> cols=c(8,9,10,11,12,27,28))
> >>Error: could not find function "replace.df"
>
> Thank you.
>
> Alecia
>
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>
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>


-- 
Pascal Oettli
Project Scientist
JAMSTEC
Yokohama, Japan

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