Hi,
No problem.
Please ?dput() your dataset.
dat<- read.table(text="
strategy region result
conservative desert 64.68427
moderate mountains 10.880242
moderate desert 48.72387
aggressive desert 34.37877
aggressive mountains 37.43783
moderate grassland 60.572490
aggressive forest 5.193187
aggressive grassland
15.527508",sep="",header=TRUE,stringsAsFactors=FALSE)
dat[with(dat,(result>mean(result)) & region!="grassland" ),]
#????? strategy??? region?? result
#1 conservative??? desert 64.68427
#3???? moderate??? desert 48.72387
#5?? aggressive mountains 37.43783
dat$result[dat$region=="grassland"]<- NA
A.K.
Thank you so much for your help throughout these weeks! You've been such
a great help to me. I just have one more question sorry.
When I try to get the mean I get this error
In number 8 should I use subset or replace()?
----- Original Message -----
From: arun <smartpink111 at yahoo.com>
To: R help <r-help at r-project.org>
Cc:
Sent: Monday, September 16, 2013 2:56 PM
Subject: Re: How do you do this in R?
Hi,
Try:
?sum(sapply(1:100,function(i) i^3+ 4*(i^2)))
#[1] 26855900
?169551560477066118158651749177/79632685831739040000
#[1] 2129170437
sum(sapply(1:25,function(i) ((2^i)/i)+ ((3^i)/(i^2))))
#[1] 2129170437
A.K.
I have done this on myself using paper and I know the answer for A is 26,855,900
B I got 169,551,560,477,066,118,158,651,749,177/79,632,685,831,739,040,000
So sorry for the constant questions here.