Dear R-users,
given the following data frame called hospital_2004
gender d_birth m_birth y_birth address d_admittance m_admittance y_admittance
yard_admittance d_release m_release y_release yard_release diaprinc diasec1
diasec2 diasec3 diasec4 diasec5
2 13 12 1929 42002 30 3 2004 3003 6 5 2004 4902 430 4299 51881 4275 78001 0
1 1 8 1935 42002 7 4 2004 2401 18 5 2004 1801 20500 V581 0388 5849 0 0
1 23 12 1956 42018 26 4 2004 2402 31 5 2004 2402 1552 5715 7895 25000 4148 5722
1 9 8 1919 42002 05 5 2004 2602 22 5 2004 4902 51881 4254 4275 0 0 0
2 11 1 1925 52014 30 4 2004 2603 13 6 2004 4902 51881 49121 2732 4275 4299 5849
2 1 3 1963 44060 1 5 2004 5101 16 5 2004 2401 3201 1519 1976 1983 4019 0
1 6 3 1937 45010 6 5 2004 3003 12 5 2004 4901 431 3314 41189 25001 4019 V594
1 3 9 1931 42034 3 5 2004 5101 5 5 2004 5101 78559 4829 5119 1619 4241 585
2 13 9 1912 41007 5 5 2004 4901 7 5 2004 4901 85225 4019 42731 49121 0 0
1 21 10 1936 15146 7 5 2004 4901 10 5 2004 4901 431 430 V594 V595 0 0
2 8 5 1933 43044 8 5 2004 5802 8 6 2004 5802 5712 45620 2851 5119 5184 0
1 25 1 1926 41057 8 5 2004 4901 15 5 2004 4901 431 78001 49121 0 0 0
1 6 1 1923 42002 10 5 2004 1401 11 5 2004 4901 4440 412 4413 0 0 0
1 19 3 1934 42022 9 5 2004 1401 21 6 2004 4901 4413 5609 99811 4019 412 0
1 6 6 1921 43052 15 5 2004 4302 4 6 2004 4302 1890 20280 436 49121 9986 V1005
when I try to evaluate the frequency of daily releases through
release_freq <- as.data.frame(xtabs( ~ d_release + m_release + y_release,
data=hospital_2004))
I get the following result:
d_release m_release y_release Freq
4 5 2004 0
5 5 2004 1
6 5 2004 1
7 5 2004 1
8 5 2004 0
10 5 2004 1
11 5 2004 1
12 5 2004 1
13 5 2004 0
15 5 2004 1
16 5 2004 1
18 5 2004 1
21 5 2004 0
22 5 2004 1
31 5 2004 1
4 6 2004 1
5 6 2004 0
6 6 2004 0
7 6 2004 0
8 6 2004 1
10 6 2004 0
11 6 2004 0
12 6 2004 0
13 6 2004 1
15 6 2004 0
16 6 2004 0
18 6 2004 0
21 6 2004 1
22 6 2004 0
31 6 2004 0
Why the 1st, 2nd, 3rd, 9th, 14th, 17th, 19th, 20th, from 23rd to 30th of both
May and June are missing? (and there is the 31st of June?)
And a final question: why given another data frame called temp_h12
y_temp m_temp d_temp temp
2004 5 1 16.90
2004 5 2 18.00
2004 5 3 17.40
2004 5 4 19.70
2004 5 5 105.70
2004 5 6 17.30
2004 5 7 17.00
2004 5 8 16.20
2004 5 9 16.10
2004 5 10 16.10
2004 5 11 15.80
2004 5 12 15.10
2004 5 13 17.80
2004 5 14 17.40
2004 5 15 16.00
2004 5 16 17.70
2004 5 17 17.30
2004 5 18 22.30
2004 5 19 23.30
2004 5 20 24.30
2004 5 21 19.90
2004 5 22 15.70
2004 5 23 15.80
2004 5 24 17.10
2004 5 25 18.30
2004 5 26 21.00
2004 5 27 18.20
2004 5 28 17.90
2004 5 29 19.40
2004 5 30 22.10
2004 5 31 17.40
merge(release_freq, temp_h12,
by.x=c("y_release","m_release","d_release"),
by.y=c("y_temp","m_temp","d_temp"),
stringsAsFactors=FALSE)
gives the following warning
Warning message:
In `[<-.factor`(`*tmp*`, ri, value = 1:31) :
invalid factor level, NAs generated
?
Thank you for your help
Stefano Sofia
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[[alternative HTML version deleted]]
Hello, Please use dput() to provide useful dataset and avoid the use of HTML when sending a e-mail to this list. Regards, Pascal 2013/7/23 Stefano Sofia <stefano.sofia@regione.marche.it>> Dear R-users, > given the following data frame called hospital_2004 > > gender d_birth m_birth y_birth address d_admittance m_admittance > y_admittance yard_admittance d_release m_release y_release yard_release > diaprinc diasec1 diasec2 diasec3 diasec4 diasec5 > 2 13 12 1929 42002 30 3 2004 3003 6 5 2004 4902 430 4299 51881 4275 78001 0 > 1 1 8 1935 42002 7 4 2004 2401 18 5 2004 1801 20500 V581 0388 5849 0 0 > 1 23 12 1956 42018 26 4 2004 2402 31 5 2004 2402 1552 5715 7895 25000 4148 > 5722 > 1 9 8 1919 42002 05 5 2004 2602 22 5 2004 4902 51881 4254 4275 0 0 0 > 2 11 1 1925 52014 30 4 2004 2603 13 6 2004 4902 51881 49121 2732 4275 4299 > 5849 > 2 1 3 1963 44060 1 5 2004 5101 16 5 2004 2401 3201 1519 1976 1983 4019 0 > 1 6 3 1937 45010 6 5 2004 3003 12 5 2004 4901 431 3314 41189 25001 4019 > V594 > 1 3 9 1931 42034 3 5 2004 5101 5 5 2004 5101 78559 4829 5119 1619 4241 585 > 2 13 9 1912 41007 5 5 2004 4901 7 5 2004 4901 85225 4019 42731 49121 0 0 > 1 21 10 1936 15146 7 5 2004 4901 10 5 2004 4901 431 430 V594 V595 0 0 > 2 8 5 1933 43044 8 5 2004 5802 8 6 2004 5802 5712 45620 2851 5119 5184 0 > 1 25 1 1926 41057 8 5 2004 4901 15 5 2004 4901 431 78001 49121 0 0 0 > 1 6 1 1923 42002 10 5 2004 1401 11 5 2004 4901 4440 412 4413 0 0 0 > 1 19 3 1934 42022 9 5 2004 1401 21 6 2004 4901 4413 5609 99811 4019 412 0 > 1 6 6 1921 43052 15 5 2004 4302 4 6 2004 4302 1890 20280 436 49121 9986 > V1005 > > when I try to evaluate the frequency of daily releases through > > release_freq <- as.data.frame(xtabs( ~ d_release + m_release + y_release, > data=hospital_2004)) > > I get the following result: > > d_release m_release y_release Freq > 4 5 2004 0 > 5 5 2004 1 > 6 5 2004 1 > 7 5 2004 1 > 8 5 2004 0 > 10 5 2004 1 > 11 5 2004 1 > 12 5 2004 1 > 13 5 2004 0 > 15 5 2004 1 > 16 5 2004 1 > 18 5 2004 1 > 21 5 2004 0 > 22 5 2004 1 > 31 5 2004 1 > 4 6 2004 1 > 5 6 2004 0 > 6 6 2004 0 > 7 6 2004 0 > 8 6 2004 1 > 10 6 2004 0 > 11 6 2004 0 > 12 6 2004 0 > 13 6 2004 1 > 15 6 2004 0 > 16 6 2004 0 > 18 6 2004 0 > 21 6 2004 1 > 22 6 2004 0 > 31 6 2004 0 > > Why the 1st, 2nd, 3rd, 9th, 14th, 17th, 19th, 20th, from 23rd to 30th of > both May and June are missing? (and there is the 31st of June?) > > And a final question: why given another data frame called temp_h12 > > y_temp m_temp d_temp temp > 2004 5 1 16.90 > 2004 5 2 18.00 > 2004 5 3 17.40 > 2004 5 4 19.70 > 2004 5 5 105.70 > 2004 5 6 17.30 > 2004 5 7 17.00 > 2004 5 8 16.20 > 2004 5 9 16.10 > 2004 5 10 16.10 > 2004 5 11 15.80 > 2004 5 12 15.10 > 2004 5 13 17.80 > 2004 5 14 17.40 > 2004 5 15 16.00 > 2004 5 16 17.70 > 2004 5 17 17.30 > 2004 5 18 22.30 > 2004 5 19 23.30 > 2004 5 20 24.30 > 2004 5 21 19.90 > 2004 5 22 15.70 > 2004 5 23 15.80 > 2004 5 24 17.10 > 2004 5 25 18.30 > 2004 5 26 21.00 > 2004 5 27 18.20 > 2004 5 28 17.90 > 2004 5 29 19.40 > 2004 5 30 22.10 > 2004 5 31 17.40 > > merge(release_freq, temp_h12, by.x=c("y_release","m_release","d_release"), > by.y=c("y_temp","m_temp","d_temp"), stringsAsFactors=FALSE) > > gives the following warning > > Warning message: > In `[<-.factor`(`*tmp*`, ri, value = 1:31) : > invalid factor level, NAs generated > ? > > > > Thank you for your help > Stefano Sofia > > > > ________________________________ > > AVVISO IMPORTANTE: Questo messaggio di posta elettronica può contenere > informazioni confidenziali, pertanto è destinato solo a persone autorizzate > alla ricezione. I messaggi di posta elettronica per i client di Regione > Marche possono contenere informazioni confidenziali e con privilegi legali. > Se non si è il destinatario specificato, non leggere, copiare, inoltrare o > archiviare questo messaggio. Se si è ricevuto questo messaggio per errore, > inoltrarlo al mittente ed eliminarlo completamente dal sistema del proprio > computer. Ai sensi dell'art. 6 della DGR n. 1394/2008 si segnala che, in > caso di necessità ed urgenza, la risposta al presente messaggio di posta > elettronica può essere visionata da persone estranee al destinatario. > IMPORTANT NOTICE: This e-mail message is intended to be received only by > persons entitled to receive the confidential information it may contain. > E-mail messages to clients of Regione Marche may contain information that > is confidential and legally privileged. Please do not read, copy, forward, > or store this message unless you are an intended recipient of it. If you > have received this message in error, please forward it to the sender and > delete it completely from your computer system. > > [[alternative HTML version deleted]] > > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > >[[alternative HTML version deleted]]
Hello, Why should those numbers show up in the final result? They are missing in the original data frame. A hack could be fac <- factor(hospital_2004$d_release, levels = seq_len(max(hospital_2004$d_release))) as.data.frame(xtabs( ~ fac + m_release + y_release, data=hospital_2004)) And there would still be a 31 in m_release 6, which you call June but in fact is just a number. Hope this helps, Rui Barradas Em 23-07-2013 10:33, Stefano Sofia escreveu:> Dear R-users, > given the following data frame called hospital_2004 > > gender d_birth m_birth y_birth address d_admittance m_admittance y_admittance yard_admittance d_release m_release y_release yard_release diaprinc diasec1 diasec2 diasec3 diasec4 diasec5 > 2 13 12 1929 42002 30 3 2004 3003 6 5 2004 4902 430 4299 51881 4275 78001 0 > 1 1 8 1935 42002 7 4 2004 2401 18 5 2004 1801 20500 V581 0388 5849 0 0 > 1 23 12 1956 42018 26 4 2004 2402 31 5 2004 2402 1552 5715 7895 25000 4148 5722 > 1 9 8 1919 42002 05 5 2004 2602 22 5 2004 4902 51881 4254 4275 0 0 0 > 2 11 1 1925 52014 30 4 2004 2603 13 6 2004 4902 51881 49121 2732 4275 4299 5849 > 2 1 3 1963 44060 1 5 2004 5101 16 5 2004 2401 3201 1519 1976 1983 4019 0 > 1 6 3 1937 45010 6 5 2004 3003 12 5 2004 4901 431 3314 41189 25001 4019 V594 > 1 3 9 1931 42034 3 5 2004 5101 5 5 2004 5101 78559 4829 5119 1619 4241 585 > 2 13 9 1912 41007 5 5 2004 4901 7 5 2004 4901 85225 4019 42731 49121 0 0 > 1 21 10 1936 15146 7 5 2004 4901 10 5 2004 4901 431 430 V594 V595 0 0 > 2 8 5 1933 43044 8 5 2004 5802 8 6 2004 5802 5712 45620 2851 5119 5184 0 > 1 25 1 1926 41057 8 5 2004 4901 15 5 2004 4901 431 78001 49121 0 0 0 > 1 6 1 1923 42002 10 5 2004 1401 11 5 2004 4901 4440 412 4413 0 0 0 > 1 19 3 1934 42022 9 5 2004 1401 21 6 2004 4901 4413 5609 99811 4019 412 0 > 1 6 6 1921 43052 15 5 2004 4302 4 6 2004 4302 1890 20280 436 49121 9986 V1005 > > when I try to evaluate the frequency of daily releases through > > release_freq <- as.data.frame(xtabs( ~ d_release + m_release + y_release, data=hospital_2004)) > > I get the following result: > > d_release m_release y_release Freq > 4 5 2004 0 > 5 5 2004 1 > 6 5 2004 1 > 7 5 2004 1 > 8 5 2004 0 > 10 5 2004 1 > 11 5 2004 1 > 12 5 2004 1 > 13 5 2004 0 > 15 5 2004 1 > 16 5 2004 1 > 18 5 2004 1 > 21 5 2004 0 > 22 5 2004 1 > 31 5 2004 1 > 4 6 2004 1 > 5 6 2004 0 > 6 6 2004 0 > 7 6 2004 0 > 8 6 2004 1 > 10 6 2004 0 > 11 6 2004 0 > 12 6 2004 0 > 13 6 2004 1 > 15 6 2004 0 > 16 6 2004 0 > 18 6 2004 0 > 21 6 2004 1 > 22 6 2004 0 > 31 6 2004 0 > > Why the 1st, 2nd, 3rd, 9th, 14th, 17th, 19th, 20th, from 23rd to 30th of both May and June are missing? (and there is the 31st of June?) > > And a final question: why given another data frame called temp_h12 > > y_temp m_temp d_temp temp > 2004 5 1 16.90 > 2004 5 2 18.00 > 2004 5 3 17.40 > 2004 5 4 19.70 > 2004 5 5 105.70 > 2004 5 6 17.30 > 2004 5 7 17.00 > 2004 5 8 16.20 > 2004 5 9 16.10 > 2004 5 10 16.10 > 2004 5 11 15.80 > 2004 5 12 15.10 > 2004 5 13 17.80 > 2004 5 14 17.40 > 2004 5 15 16.00 > 2004 5 16 17.70 > 2004 5 17 17.30 > 2004 5 18 22.30 > 2004 5 19 23.30 > 2004 5 20 24.30 > 2004 5 21 19.90 > 2004 5 22 15.70 > 2004 5 23 15.80 > 2004 5 24 17.10 > 2004 5 25 18.30 > 2004 5 26 21.00 > 2004 5 27 18.20 > 2004 5 28 17.90 > 2004 5 29 19.40 > 2004 5 30 22.10 > 2004 5 31 17.40 > > merge(release_freq, temp_h12, by.x=c("y_release","m_release","d_release"), by.y=c("y_temp","m_temp","d_temp"), stringsAsFactors=FALSE) > > gives the following warning > > Warning message: > In `[<-.factor`(`*tmp*`, ri, value = 1:31) : > invalid factor level, NAs generated > ? > > > > Thank you for your help > Stefano Sofia > > > > ________________________________ > > AVVISO IMPORTANTE: Questo messaggio di posta elettronica pu? contenere informazioni confidenziali, pertanto ? destinato solo a persone autorizzate alla ricezione. I messaggi di posta elettronica per i client di Regione Marche possono contenere informazioni confidenziali e con privilegi legali. Se non si ? il destinatario specificato, non leggere, copiare, inoltrare o archiviare questo messaggio. Se si ? ricevuto questo messaggio per errore, inoltrarlo al mittente ed eliminarlo completamente dal sistema del proprio computer. Ai sensi dell'art. 6 della DGR n. 1394/2008 si segnala che, in caso di necessit? ed urgenza, la risposta al presente messaggio di posta elettronica pu? essere visionata da persone estranee al destinatario. > IMPORTANT NOTICE: This e-mail message is intended to be received only by persons entitled to receive the confidential information it may contain. E-mail messages to clients of Regione Marche may contain information that is confidential and legally privileged. Please do not read, copy, forward, or store this message unless you are an intended recipient of it. If you have received this message in error, please forward it to the sender and delete it completely from your computer system. > > [[alternative HTML version deleted]] > > > > ______________________________________________ > R-help at r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. >
Hello, As for your second question, before merge(), try the following. release_freq$d_release <- as.integer(as.character(release_freq$d_release)) release_freq$m_release <- as.integer(as.character(release_freq$m_release)) release_freq$y_release <- as.integer(as.character(release_freq$y_release)) And the warning is gone. Hope this helps, Rui Barradas Em 23-07-2013 10:33, Stefano Sofia escreveu:> Dear R-users, > given the following data frame called hospital_2004 > > gender d_birth m_birth y_birth address d_admittance m_admittance y_admittance yard_admittance d_release m_release y_release yard_release diaprinc diasec1 diasec2 diasec3 diasec4 diasec5 > 2 13 12 1929 42002 30 3 2004 3003 6 5 2004 4902 430 4299 51881 4275 78001 0 > 1 1 8 1935 42002 7 4 2004 2401 18 5 2004 1801 20500 V581 0388 5849 0 0 > 1 23 12 1956 42018 26 4 2004 2402 31 5 2004 2402 1552 5715 7895 25000 4148 5722 > 1 9 8 1919 42002 05 5 2004 2602 22 5 2004 4902 51881 4254 4275 0 0 0 > 2 11 1 1925 52014 30 4 2004 2603 13 6 2004 4902 51881 49121 2732 4275 4299 5849 > 2 1 3 1963 44060 1 5 2004 5101 16 5 2004 2401 3201 1519 1976 1983 4019 0 > 1 6 3 1937 45010 6 5 2004 3003 12 5 2004 4901 431 3314 41189 25001 4019 V594 > 1 3 9 1931 42034 3 5 2004 5101 5 5 2004 5101 78559 4829 5119 1619 4241 585 > 2 13 9 1912 41007 5 5 2004 4901 7 5 2004 4901 85225 4019 42731 49121 0 0 > 1 21 10 1936 15146 7 5 2004 4901 10 5 2004 4901 431 430 V594 V595 0 0 > 2 8 5 1933 43044 8 5 2004 5802 8 6 2004 5802 5712 45620 2851 5119 5184 0 > 1 25 1 1926 41057 8 5 2004 4901 15 5 2004 4901 431 78001 49121 0 0 0 > 1 6 1 1923 42002 10 5 2004 1401 11 5 2004 4901 4440 412 4413 0 0 0 > 1 19 3 1934 42022 9 5 2004 1401 21 6 2004 4901 4413 5609 99811 4019 412 0 > 1 6 6 1921 43052 15 5 2004 4302 4 6 2004 4302 1890 20280 436 49121 9986 V1005 > > when I try to evaluate the frequency of daily releases through > > release_freq <- as.data.frame(xtabs( ~ d_release + m_release + y_release, data=hospital_2004)) > > I get the following result: > > d_release m_release y_release Freq > 4 5 2004 0 > 5 5 2004 1 > 6 5 2004 1 > 7 5 2004 1 > 8 5 2004 0 > 10 5 2004 1 > 11 5 2004 1 > 12 5 2004 1 > 13 5 2004 0 > 15 5 2004 1 > 16 5 2004 1 > 18 5 2004 1 > 21 5 2004 0 > 22 5 2004 1 > 31 5 2004 1 > 4 6 2004 1 > 5 6 2004 0 > 6 6 2004 0 > 7 6 2004 0 > 8 6 2004 1 > 10 6 2004 0 > 11 6 2004 0 > 12 6 2004 0 > 13 6 2004 1 > 15 6 2004 0 > 16 6 2004 0 > 18 6 2004 0 > 21 6 2004 1 > 22 6 2004 0 > 31 6 2004 0 > > Why the 1st, 2nd, 3rd, 9th, 14th, 17th, 19th, 20th, from 23rd to 30th of both May and June are missing? (and there is the 31st of June?) > > And a final question: why given another data frame called temp_h12 > > y_temp m_temp d_temp temp > 2004 5 1 16.90 > 2004 5 2 18.00 > 2004 5 3 17.40 > 2004 5 4 19.70 > 2004 5 5 105.70 > 2004 5 6 17.30 > 2004 5 7 17.00 > 2004 5 8 16.20 > 2004 5 9 16.10 > 2004 5 10 16.10 > 2004 5 11 15.80 > 2004 5 12 15.10 > 2004 5 13 17.80 > 2004 5 14 17.40 > 2004 5 15 16.00 > 2004 5 16 17.70 > 2004 5 17 17.30 > 2004 5 18 22.30 > 2004 5 19 23.30 > 2004 5 20 24.30 > 2004 5 21 19.90 > 2004 5 22 15.70 > 2004 5 23 15.80 > 2004 5 24 17.10 > 2004 5 25 18.30 > 2004 5 26 21.00 > 2004 5 27 18.20 > 2004 5 28 17.90 > 2004 5 29 19.40 > 2004 5 30 22.10 > 2004 5 31 17.40 > > merge(release_freq, temp_h12, by.x=c("y_release","m_release","d_release"), by.y=c("y_temp","m_temp","d_temp"), stringsAsFactors=FALSE) > > gives the following warning > > Warning message: > In `[<-.factor`(`*tmp*`, ri, value = 1:31) : > invalid factor level, NAs generated > ? > > > > Thank you for your help > Stefano Sofia > > > > ________________________________ > > AVVISO IMPORTANTE: Questo messaggio di posta elettronica pu? contenere informazioni confidenziali, pertanto ? destinato solo a persone autorizzate alla ricezione. I messaggi di posta elettronica per i client di Regione Marche possono contenere informazioni confidenziali e con privilegi legali. Se non si ? il destinatario specificato, non leggere, copiare, inoltrare o archiviare questo messaggio. Se si ? ricevuto questo messaggio per errore, inoltrarlo al mittente ed eliminarlo completamente dal sistema del proprio computer. Ai sensi dell'art. 6 della DGR n. 1394/2008 si segnala che, in caso di necessit? ed urgenza, la risposta al presente messaggio di posta elettronica pu? essere visionata da persone estranee al destinatario. > IMPORTANT NOTICE: This e-mail message is intended to be received only by persons entitled to receive the confidential information it may contain. E-mail messages to clients of Regione Marche may contain information that is confidential and legally privileged. Please do not read, copy, forward, or store this message unless you are an intended recipient of it. If you have received this message in error, please forward it to the sender and delete it completely from your computer system. > > [[alternative HTML version deleted]] > > > > ______________________________________________ > R-help at r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. >