Hi
without data we can provide just basic help.
fit<-lm(Time~I(1/Requests))
shall give you hyperbolic fit.
You can test if your data follow this assumption by
plot(1/Requests, Time)
which shall for straight line.
anyway, when you want to provide data use
dput(your.data) and copy console output directly to your mail.
Petr
> -----Original Message-----
> From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-
> project.org] On Behalf Of Manoj Srivastava
> Sent: Monday, April 08, 2013 4:08 AM
> To: r-help at stat.math.ethz.ch
> Subject: [R] fitting a hyperbola to data points
>
> Hi,
>
> I am new to R, and I suspect I am missing something simple.
>
> I have a data set that performance data that correlates
> request rate to response times
> http://pastebin.com/Xhg0RaUp
> There is some jitter in the data, but mostly it looks like a hockey
> puck curve. It does not get converted into a straight line when I tried
> log conversions, so it does not seem to be a power series relationship.
>
> My expectation is that the data will fit a curve that is a
> hyperbola, but I don't know how to formulate that regression. How does
> one fit data to a general function
> AX^2 + Bxy + Cy^2 +D = 0
>
> I have tried polynomial functions and inverse functions
> lm2 = lm(Time ~ Requests + I(Requests^2) + I(Requests^3)) but that
> does not appear to be close.
>
> Any pointers appreciated.
>
> manoj
>
> dat <- read.csv("perf.csv",header=TRUE)
> plot (Time ~ Requests)
> plot (Time ~ Requests, log="y")
> plot (Time ~ Requests, log="x")
> plot (Time ~ Requests, log="xy")
>
>
> --
> To be intoxicated is to feel sophisticated, but not be able to say it.
> George Carlin Manoj Srivastava <srivasta at acm.org>
<http://www.golden-
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