R help - Mar 2013 - find and replace characters in a string

Hi,

I have a string of text as follows "LOI ."

How do I replace the dot with "(%)"

gsub(".","(%)",LOI .)

gives

"(%)(%)(%)(%)(%)"

Thanks
-- 
Shane

	[[alternative HTML version deleted]]

txt<-? "LOI ."
gsub("[.]","%",txt)
#[1] "LOI %"
A.K.





________________________________
From: Shane Carey <careyshan at gmail.com>
To: r-help at r-project.org 
Sent: Wednesday, March 27, 2013 12:09 PM
Subject: [R] find and replace characters in a string

Hi,

I have a string of text as follows "LOI ."

How do I replace the dot with "(%)"

gsub(".","(%)",LOI .)

gives

"(%)(%)(%)(%)(%)"

Thanks
-- 
Shane

??? [[alternative HTML version deleted]]

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Hello,

The period is a metacharacter so you have to escape it.
The period is escaped with a '\'. In it's turn, '\' is a
metacharacter
so it needs to be escaped. Hence the double'\\'.

x <- "LOI ."
gsub("\\.", "(%)", x)


Hope this helps,

Rui Barradas

Em 27-03-2013 16:09, Shane Carey escreveu:
> Hi,
>
> I have a string of text as follows "LOI ."
>
> How do I replace the dot with "(%)"
>
> gsub(".","(%)",LOI .)
>
> gives
>
> "(%)(%)(%)(%)(%)"
>
> Thanks
>