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Irucka Embry

2013-Jan-09 10:44 UTC

[R] select partial name and full name columns

Hi, I have the following function:

getDataFromDVFileCustom <- function (file, hasHeader = TRUE, separator
"\t")
{
DVdatatmp <- as.matrix(read.table(file, sep = "\t", fill = TRUE,
comment.char = "#", as.is = TRUE, stringsAsFactors = FALSE, na.strings
"NA"))
DVdatatmper <- as.matrix(DVdatatmp[ , c("datetime",
grep("^_00060_00003", colnames(DVdatatmp)))])
retval <- as.data.frame(DVdatatmper, colClasses = c("character"),
fill TRUE, comment.char = "#", stringsAsFactors = FALSE)
if (ncol(retval) == 2) {
names(retval) <- c("dateTime", "value")
}
else if (ncol(retval) == 3) {
names(retval) <- c("dateTime", "value", "code")
}
if (dateFormatCheck(retval$dateTime)) {
retval$dateTime <- as.Date(retval$dateTime)
}
else {
retval$dateTime <- as.Date(retval$dateTime, format = "%m/%d/%Y")
}
retval$value <- as.numeric(retval$value)
return(retval)
}

The function gives me this error:
getDataFromDVFileCustom(file)
Error in as.matrix(DVdatatmp[, c("datetime",
grep("^_00060_00003",
colnames(DVdatatmp)))]) : 
subscript out of bounds

I am trying to only select 3 columns (datetime and then two partial name
columns that end in 00060_00003 and 00060_00003_cd. Each file that I
will be reading into the function has a different number of columns and
a different prefix in front of 00060_00003 and 00060_00003_cd. I have
searched online and tried those possible solutions, but they did not
work for my function and data.

What is the best way to select those 3 columns only?

Thank-you.

Irucka Embry 


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arun

2013-Jan-09 13:13 UTC

head link

[R] select partial name and full name columns

Hi,

May be this is creating the problem:

set.seed(15)
dat1<-data.frame(A_00060_00003=sample(1:10,5,replace=TRUE),B_00060_00003_cd=sample(20:30,5,replace=TRUE),C_00060_00003=sample(1:15,5,replace=TRUE),D_00060=sample(1:8,5,replace=TRUE),datetime=as.POSIXct(paste(rep("6/3/2011",5),c("0:00","0:30","0:35","0:40","0:45")),format="%m/%d/%Y
%H:%M"))
?dat1[,c("datetime",grep("00060_00003",colnames(dat1)))]
#Error in `[.data.frame`(dat1, , c("datetime",
grep("00060_00003", colnames(dat1)))) :
? #undefined columns selected
dat1[,c("datetime",colnames(dat1)[grep("00060_00003",colnames(dat1))])]
#???????????? datetime A_00060_00003 B_00060_00003_cd C_00060_00003
#1 2011-06-03 00:00:00???????????? 7?????????????? 30???????????? 2
#2 2011-06-03 00:30:00???????????? 2?????????????? 28??????????? 10
#3 2011-06-03 00:35:00??????????? 10?????????????? 22???????????? 8
#4 2011-06-03 00:40:00???????????? 7?????????????? 27??????????? 11
#5 2011-06-03 00:45:00???????????? 4?????????????? 29??????????? 13
A.K.



----- Original Message -----
From: Irucka Embry <iruckaE at mail2world.com>
To: r-help at r-project.org
Cc: 
Sent: Wednesday, January 9, 2013 5:44 AM
Subject: [R] select partial name and full name columns

Hi, I have the following function:

getDataFromDVFileCustom <- function (file, hasHeader = TRUE, separator
"\t")
{
DVdatatmp <- as.matrix(read.table(file, sep = "\t", fill = TRUE,
comment.char = "#", as.is = TRUE, stringsAsFactors = FALSE, na.strings
"NA"))
DVdatatmper <- as.matrix(DVdatatmp[ , c("datetime",
grep("^_00060_00003", colnames(DVdatatmp)))])
retval <- as.data.frame(DVdatatmper, colClasses = c("character"),
fill TRUE, comment.char = "#", stringsAsFactors = FALSE)
if (ncol(retval) == 2) {
names(retval) <- c("dateTime", "value")
}
else if (ncol(retval) == 3) {
names(retval) <- c("dateTime", "value", "code")
}
if (dateFormatCheck(retval$dateTime)) {
retval$dateTime <- as.Date(retval$dateTime)
}
else {
retval$dateTime <- as.Date(retval$dateTime, format = "%m/%d/%Y")
}
retval$value <- as.numeric(retval$value)
return(retval)
}

The function gives me this error:
getDataFromDVFileCustom(file)
Error in as.matrix(DVdatatmp[, c("datetime",
grep("^_00060_00003",
colnames(DVdatatmp)))]) : 
subscript out of bounds

I am trying to only select 3 columns (datetime and then two partial name
columns that end in 00060_00003 and 00060_00003_cd. Each file that I
will be reading into the function has a different number of columns and
a different prefix in front of 00060_00003 and 00060_00003_cd. I have
searched online and tried those possible solutions, but they did not
work for my function and data.

What is the best way to select those 3 columns only?

Thank-you.

Irucka Embry 


<span id=m2wTl><p><font face="Arial, Helvetica,
sans-serif" size="2"
style="font-size:13.5px">_______________________________________________________________<BR>Get
the Free email that has everyone talking at <a href=http://www.mail2world.com
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??? [[alternative HTML version deleted]]

______________________________________________
R-help at r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

Irucka Embry

2013-Jan-09 16:36 UTC

head link

[R] select partial name and full name columns

Hi Arun, thank-you for your suggestion.

I made a mistake previously when I suggested that there was a "prefix"
in front of "00060_00003" possibly suggesting that it was a string of
characters rather than numbers. The "prefix" in front of
"00060_00003"
is actually two numbers, see the examples below:

01_00060_00003 01_00060_00003_cd 15_00060_00003 15_00060_00003_cd
02_00060_00003 02_00060_00003_cd

How can the following code be modified to reflect the numerical rather
than character prefix? 

dat1[,c("datetime",colnames(dat1)[grep("00060_00003",colnames(dat1))])]

Thank-you.

Irucka Embry


<-----Original Message-----> >From: arun [smartpink111@yahoo.com]
>Sent: 1/9/2013 7:13:05 AM
>To: iruckaE@mail2world.com
>Cc: r-help@r-project.org
>Subject: Re: [R] select partial name and full name columns
>
>
>
>Hi,
>
>May be this is creating the problem:
>
>set.seed(15)
>dat1<-data.frame(A_00060_00003=sample(1:10,5,replace=TRUE),B_00060_00003_cd=sample(20:30,5,replace=TRUE),C_00060_00003=sample(1:15,5,replace=TR
UE),D_00060=sample(1:8,5,replace=TRUE),datetime=as.POSIXct(paste(rep("6/
3/2011",5),c("0:00","0:30","0:35","0:40","0:45")),format="%m/%d/%Y>%H:%M"))
> dat1[,c("datetime",grep("00060_00003",colnames(dat1)))]
>#Error in `[.data.frame`(dat1, , c("datetime",
grep("00060_00003",
>colnames(dat1)))) : 
>  #undefined columns selected
>dat1[,c("datetime",colnames(dat1)[grep("00060_00003",colnames(dat1))])]
>#             datetime A_00060_00003 B_00060_00003_cd C_00060_00003
>#1 2011-06-03 00:00:00             7               30             2
>#2 2011-06-03 00:30:00             2               28            10
>#3 2011-06-03 00:35:00            10               22             8
>#4 2011-06-03 00:40:00             7               27            11
>#5 2011-06-03 00:45:00             4               29            13
>A.K.
>
>
>
>----- Original Message -----
>From: Irucka Embry <iruckaE@mail2world.com>
>To: r-help@r-project.org
>Cc: 
>Sent: Wednesday, January 9, 2013 5:44 AM
>Subject: [R] select partial name and full name columns
>
>Hi, I have the following function:
>
>getDataFromDVFileCustom <- function (file, hasHeader = TRUE, separator
>"\t") 
>{
>DVdatatmp <- as.matrix(read.table(file, sep = "\t", fill =
TRUE,
>comment.char = "#", as.is = TRUE, stringsAsFactors = FALSE,
na.strings
>"NA"))
>DVdatatmper <- as.matrix(DVdatatmp[ , c("datetime",
>grep("^_00060_00003", colnames(DVdatatmp)))])
>retval <- as.data.frame(DVdatatmper, colClasses =
c("character"), fill
>TRUE, comment.char = "#", stringsAsFactors = FALSE)
>if (ncol(retval) == 2) {
>names(retval) <- c("dateTime", "value")
>}
>else if (ncol(retval) == 3) {
>names(retval) <- c("dateTime", "value",
"code")
>}
>if (dateFormatCheck(retval$dateTime)) {
>retval$dateTime <- as.Date(retval$dateTime)
>}
>else {
>retval$dateTime <- as.Date(retval$dateTime, format =
"%m/%d/%Y")
>}
>retval$value <- as.numeric(retval$value)
>return(retval)
>}
>
>The function gives me this error:
>getDataFromDVFileCustom(file)
>Error in as.matrix(DVdatatmp[, c("datetime",
grep("^_00060_00003",
>colnames(DVdatatmp)))]) : 
>subscript out of bounds
>
>I am trying to only select 3 columns (datetime and then two partial
name>columns that end in 00060_00003 and 00060_00003_cd. Each file that I
>will be reading into the function has a different number of columns and
>a different prefix in front of 00060_00003 and 00060_00003_cd. I have
>searched online and tried those possible solutions, but they did not
>work for my function and data.
>
>What is the best way to select those 3 columns only?
>
>Thank-you.
>
>Irucka Embry 
>
>
>______________________________________________
>R-help@r-project.org mailing list
>https://stat.ethz.ch/mailman/listinfo/r-help
>PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html>and provide commented, minimal, self-contained, reproducible code. 

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	[[alternative HTML version deleted]]

arun

2013-Jan-09 17:09 UTC

head link

[R] select partial name and full name columns

Hi,
You can use the same code:
set.seed(15)
?dat1<-data.frame(sample(1:10,5,replace=TRUE),sample(20:30,5,replace=TRUE),sample(1:15,5,replace=TRUE),sample(1:8,5,replace=TRUE),datetime=as.POSIXct(paste(rep("6/3/2011",5),c("0:00","0:30","0:35","0:40","0:45")),format="%m/%d/%Y
%H:%M"))

?colnames(dat1)[1:4]<-c("01_00060_00003","01_000060_00003_cd","15_000060_00003","15_00060")


dat1
#? 01_00060_00003 01_000060_00003_cd 15_000060_00003 15_00060
#1????????????? 7???????????????? 30?????????????? 2??????? 7
#2????????????? 2???????????????? 28????????????? 10??????? 4
#3???????????? 10???????????????? 22?????????????? 8??????? 8
#4????????????? 7???????????????? 27????????????? 11??????? 2
#5????????????? 4???????????????? 29????????????? 13??????? 7
? # ????????? datetime
#1 2011-06-03 00:00:00
#2 2011-06-03 00:30:00
#3 2011-06-03 00:35:00
#4 2011-06-03 00:40:00
#5 2011-06-03 00:45:00


dat1[,c("datetime",colnames(dat1)[grep("00060_00003",colnames(dat1))])]
#???????????? datetime 01_00060_00003 01_000060_00003_cd 15_000060_00003
#1 2011-06-03 00:00:00????????????? 7???????????????? 30?????????????? 2
#2 2011-06-03 00:30:00????????????? 2???????????????? 28????????????? 10
#3 2011-06-03 00:35:00???????????? 10???????????????? 22?????????????? 8
#4 2011-06-03 00:40:00????????????? 7???????????????? 27????????????? 11
#5 2011-06-03 00:45:00????????????? 4???????????????? 29????????????? 13


A.K.
________________________________
From: Irucka Embry <iruckaE at mail2world.com>
To: smartpink111 at yahoo.com 
Cc: r-help at r-project.org 
Sent: Wednesday, January 9, 2013 11:36 AM
Subject: Re: [R] select partial name and full name columns


Hi Arun, thank-you for your suggestion.

I made a mistake previously when I suggested that there was a "prefix"
in front of "00060_00003" possibly suggesting that it was a string of
characters rather than numbers. The "prefix" in front of
"00060_00003" is actually two numbers, see the examples below:

01_00060_00003 01_00060_00003_cd 15_00060_00003 15_00060_00003_cd 02_00060_00003
02_00060_00003_cd

How can the following code be modified to reflect the numerical rather than
character prefix?

dat1[,c("datetime",colnames(dat1)[grep("00060_00003",colnames(dat1))])]

Thank-you.

Irucka Embry


<-----Original Message-----> >From: arun [smartpink111 at yahoo.com]
>Sent: 1/9/2013 7:13:05 AM
>To: iruckaE at mail2world.com
>Cc: r-help at r-project.org
>Subject: Re: [R] select partial name and full name columns
>
>
>
>Hi,
>
>May be this is creating the problem:
>
>set.seed(15)
>dat1<-data.frame(A_00060_00003=sample(1:10,5,replace=TRUE),B_00060_00003_cd=sample(20:30,5,replace=TRUE),C_00060_00003=sample(1:15,5,replace=TRUE),D_00060=sample(1:8,5,replace=TRUE),datetime=as.POSIXct(paste(rep("6/3/2011",5),c("0:00","0:30","0:35","0:40","0:45")),format="%m/%d/%Y
>%H:%M"))
> dat1[,c("datetime",grep("00060_00003",colnames(dat1)))]
>#Error in `[.data.frame`(dat1, , c("datetime",
grep("00060_00003",
>colnames(dat1)))) : 
>??#undefined columns selected
>dat1[,c("datetime",colnames(dat1)[grep("00060_00003",colnames(dat1))])]
>#???????????? datetime A_00060_00003 B_00060_00003_cd C_00060_00003
>#1 2011-06-03 00:00:00???????????? 7?????????????? 30???????????? 2
>#2 2011-06-03 00:30:00???????????? 2?????????????? 28????????????10
>#3 2011-06-03 00:35:00????????????10?????????????? 22???????????? 8
>#4 2011-06-03 00:40:00???????????? 7?????????????? 27????????????11
>#5 2011-06-03 00:45:00???????????? 4?????????????? 29????????????13
>A.K.
>
>
>
>----- Original Message -----
>From: Irucka Embry <iruckaE at mail2world.com>
>To: r-help at r-project.org
>Cc: 
>Sent: Wednesday, January 9, 2013 5:44 AM
>Subject: [R] select partial name and full name columns
>
>Hi, I have the following function:
>
>getDataFromDVFileCustom <- function (file, hasHeader = TRUE, separator
>"\t")
>{
>DVdatatmp <- as.matrix(read.table(file, sep = "\t", fill =
TRUE,
>comment.char = "#", as.is = TRUE, stringsAsFactors = FALSE,
na.strings >"NA"))
>DVdatatmper <- as.matrix(DVdatatmp[ , c("datetime",
>grep("^_00060_00003", colnames(DVdatatmp)))])
>retval <- as.data.frame(DVdatatmper, colClasses =
c("character"), fill >TRUE, comment.char = "#",
stringsAsFactors = FALSE)
>if (ncol(retval) == 2) {
>names(retval) <- c("dateTime", "value")
>}
>else if (ncol(retval) == 3) {
>names(retval) <- c("dateTime", "value",
"code")
>}
>if (dateFormatCheck(retval$dateTime)) {
>retval$dateTime <- as.Date(retval$dateTime)
>}
>else {
>retval$dateTime <- as.Date(retval$dateTime, format =
"%m/%d/%Y")
>}
>retval$value <- as.numeric(retval$value)
>return(retval)
>}
>
>The function gives me this error:
>getDataFromDVFileCustom(file)
>Error in as.matrix(DVdatatmp[, c("datetime",
grep("^_00060_00003",
>colnames(DVdatatmp)))]) : 
>subscript out of bounds
>
>I am trying to only select 3 columns (datetime and then two partial name
>columns that end in 00060_00003 and 00060_00003_cd. Each file that I
>will be reading into the function has a different number of columns and
>a different prefix in front of 00060_00003 and 00060_00003_cd. I have
>searched online and tried those possible solutions, but they did not
>work for my function and data.
>
>What is the best way to select those 3 columns only?
>
>Thank-you.
>
>Irucka Embry 
>
>
>______________________________________________
>R-help at r-project.org mailing list
>https://stat.ethz.ch/mailman/listinfo/r-help
>PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
>and provide commented, minimal, self-contained, reproducible code.
_______________________________________________________________Get the Free email that has everyone talking at http://www.mail2world.com
Unlimited Email Storage ? POP3 ? Calendar ? SMS ? Translator ? Much More!

Irucka Embry

2013-Jan-09 17:56 UTC

head link

[R] select partial name and full name columns

Hi Arun, thanks again for your assistance.

Previously I did not read the files with the headers so I could not
search for those prefixed names. I corrected my mistake and the code
that you suggested does work.

Irucka

<-----Original Message-----> >From: arun [smartpink111@yahoo.com]
>Sent: 1/9/2013 11:09:13 AM
>To: iruckaE@mail2world.com
>Cc: r-help@r-project.org
>Subject: Re: [R] select partial name and full name columns
>
>
>
>Hi,
>You can use the same code:
>set.seed(15)
> dat1<-data.frame(sample(1:10,5,replace=TRUE),sample(20:30,5,replace=TRUE),sample(1:15,5,replace=TRUE),sample(1:8,5,replace=TRUE),datetime=as.P
OSIXct(paste(rep("6/3/2011",5),c("0:00","0:30","0:35","0:40","0:45")),fo
rmat="%m/%d/%Y>%H:%M"))
>
>
colnames(dat1)[1:4]<-c("01_00060_00003","01_000060_00003_cd","15_00006
0_00003","15_00060")>
>
>dat1
>#  01_00060_00003 01_000060_00003_cd 15_000060_00003 15_00060
>#1              7                 30               2        7
>#2              2                 28              10        4
>#3             10                 22               8        8
>#4              7                 27              11        2
>#5              4                 29              13        7
>  #           datetime
>#1 2011-06-03 00:00:00
>#2 2011-06-03 00:30:00
>#3 2011-06-03 00:35:00
>#4 2011-06-03 00:40:00
>#5 2011-06-03 00:45:00
>
>
>dat1[,c("datetime",colnames(dat1)[grep("00060_00003",colnames(dat1))])]
>#             datetime 01_00060_00003 01_000060_00003_cd
15_000060_00003>#1 2011-06-03 00:00:00              7                 30              
2>#2 2011-06-03 00:30:00              2                 28             
10>#3 2011-06-03 00:35:00             10                 22              
8>#4 2011-06-03 00:40:00              7                 27             
11>#5 2011-06-03 00:45:00              4                 29             
13>
>
>A.K.
>________________________________
>From: Irucka Embry <iruckaE@mail2world.com>
>To: smartpink111@yahoo.com 
>Cc: r-help@r-project.org 
>Sent: Wednesday, January 9, 2013 11:36 AM
>Subject: Re: [R] select partial name and full name columns
>
>
>Hi Arun, thank-you for your suggestion.
>
>I made a mistake previously when I suggested that there was a
"prefix"
in front>of "00060_00003" possibly suggesting that it was a string of
characters
rather>than numbers. The "prefix" in front of "00060_00003" is
actually two
numbers,>see the examples below:
>
>01_00060_00003 01_00060_00003_cd 15_00060_00003 15_00060_00003_cd
02_00060_00003>02_00060_00003_cd
>
>How can the following code be modified to reflect the numerical rather
than>character prefix? 
>
>dat1[,c("datetime",colnames(dat1)[grep("00060_00003",colnames(dat1))])]
>
>Thank-you.
>
>Irucka Embry
>
>
><-----Original Message-----> 
>>From: arun [smartpink111@yahoo.com]
>>Sent: 1/9/2013 7:13:05 AM
>>To: iruckaE@mail2world.com
>>Cc: r-help@r-project.org
>>Subject: Re: [R] select partial name and full name columns
>>
>>
>>
>>Hi,
>>
>>May be this is creating the problem:
>>
>>set.seed(15)
>>dat1<-data.frame(A_00060_00003=sample(1:10,5,replace=TRUE),B_00060_00003_cd=sample(20:30,5,replace=TRUE),C_00060_00003=sample(1:15,5,replace=T
RUE),D_00060=sample(1:8,5,replace=TRUE),datetime=as..POSIXct(paste(rep("
6/3/2011",5),c("0:00","0:30","0:35","0:40","0:45")),format="%m/%d/%Y>>%H:%M"))
>>
dat1[,c("datetime",grep("00060_00003",colnames(dat1)))]
>>#Error in `[.data.frame`(dat1, , c("datetime",
grep("00060_00003",
>>colnames(dat1)))) : 
>>  #undefined columns selected
>>dat1[,c("datetime",colnames(dat1)[grep("00060_00003",colnames(dat1))])
]>>#             datetime A_00060_00003 B_00060_00003_cd C_00060_00003
>>#1 2011-06-03 00:00:00             7               30             2
>>#2 2011-06-03 00:30:00             2               28            10
>>#3 2011-06-03 00:35:00            10               22             8
>>#4 2011-06-03 00:40:00             7               27            11
>>#5 2011-06-03 00:45:00             4               29            13
>>A.K.
>>
>>
>>
>>----- Original Message -----
>>From: Irucka Embry <iruckaE@mail2world.com>
>>To: r-help@r-project.org
>>Cc: 
>>Sent: Wednesday, January 9, 2013 5:44 AM
>>Subject: [R] select partial name and full name columns
>>
>>Hi, I have the following function:
>>
>>getDataFromDVFileCustom <- function (file, hasHeader = TRUE,
separator
>>"\t") 
>>{
>>DVdatatmp <- as.matrix(read.table(file, sep = "\t", fill =
TRUE,
>>comment.char = "#", as.is = TRUE, stringsAsFactors = FALSE,
na.strings
>>"NA"))
>>DVdatatmper <- as.matrix(DVdatatmp[ , c("datetime",
>>grep("^_00060_00003", colnames(DVdatatmp)))])
>>retval <- as.data.frame(DVdatatmper, colClasses =
c("character"), fill
>>TRUE, comment.char = "#", stringsAsFactors = FALSE)
>>if (ncol(retval) == 2) {
>>names(retval) <- c("dateTime", "value")
>>}
>>else if (ncol(retval) == 3) {
>>names(retval) <- c("dateTime", "value",
"code")
>>}
>>if (dateFormatCheck(retval$dateTime)) {
>>retval$dateTime <- as.Date(retval$dateTime)
>>}
>>else {
>>retval$dateTime <- as.Date(retval$dateTime, format =
"%m/%d/%Y")
>>}
>>retval$value <- as.numeric(retval$value)
>>return(retval)
>>}
>>
>>The function gives me this error:
>>getDataFromDVFileCustom(file)
>>Error in as.matrix(DVdatatmp[, c("datetime",
grep("^_00060_00003",
>>colnames(DVdatatmp)))]) : 
>>subscript out of bounds
>>
>>I am trying to only select 3 columns (datetime and then two partial
name>>columns that end in 00060_00003 and 00060_00003_cd. Each file that I
>>will be reading into the function has a different number of columns
and>>a different prefix in front of 00060_00003 and 00060_00003_cd. I have
>>searched online and tried those possible solutions, but they did not
>>work for my function and data.
>>
>>What is the best way to select those 3 columns only?
>>
>>Thank-you.
>>
>>Irucka Embry 
>>
>>
>>______________________________________________
>>R-help@r-project.org mailing list
>>https://stat.ethz.ch/mailman/listinfo/r-help
>>PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html>>and provide commented, minimal, self-contained, reproducible code. 

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