R help - Dec 2012 - Formatting a path for unix with gsub

I have a path:

path = "/nfs/users/nfs_n/ns9/
Phenotype Analysis/Results/Run_AmplRatio_neg
BinaryAll trained without akapn+tnik.csv"

I wish to replace the spaces with "\ " so that it can be read by a
system
call to unix.

Using gsub I try:
> gsub(" ","\\ ",path)
[1] "/nfs/users/nfs_n/ns9/Phenotype Analysis/Results/Run_AmplRatio_neg
BinaryAll trained without akapn+tnik.csv"

Various variations on this result in either adding no backslashes, or two at
once. How do I just get one backslash inserted?

Thanks

	[[alternative HTML version deleted]]

On Dec 17, 2012, at 9:44 AM, Nathan Skene wrote:
> I have a path:
> 
> path = "/nfs/users/nfs_n/ns9/
> Phenotype Analysis/Results/Run_AmplRatio_neg
> BinaryAll trained without akapn+tnik.csv"
> 
> I wish to replace the spaces with "\ " so that it can be read by
a system
> call to unix.
> 
> Using gsub I try:
> 
>> gsub(" ","\\ ",path)
> [1] "/nfs/users/nfs_n/ns9/Phenotype Analysis/Results/Run_AmplRatio_neg
> BinaryAll trained without akapn+tnik.csv"
> 
> Various variations on this result in either adding no backslashes, or two
at
> once. How do I just get one backslash inserted?
You are probably being fooled by the print representation of backslashes in R
output:
> gsub("\\s","\\\\ ",path)
[1] "/nfs/users/nfs_n/ns9/\\ Phenotype\\
Analysis/Results/Run_AmplRatio_neg\\ BinaryAll\\ trained\\ without\\
akapn+tnik.csv"

To check for the presence of backslashes with grepl, you need an R-grep pattern
of "\\\\"
> grepl("\\\\", "\ ")   # surprise?  "\ " is
not what it appears.
[1] FALSE
> grepl("\\\\", "\\ ")
[1] TRUE
> nchar("\ ")
[1] 1
> nchar("\\ ")
[1] 2


-- 
David Winsemius
Alameda, CA, USA

Use either
  > gsub(" ", "\\\\ ", "one two  three") #
double space after 'two'
  [1] "one\\ two\\ \\ three"
or
  > gsub(" ", "\\ ", "one two  three",
fixed=TRUE)
  [1] "one\\ two\\ \\ three"

When 'fixed' is not TRUE then a backslash gives a special meaning to
the next character in the replacement argument.
E.g., "\\1" means to put the match corresponding to the first
parenthesized
subpattern into the replacement and, when perl=TRUE "\\U" means to
capitalize the alphabetic characters in \\<digit> replacements.  E.g.,
  > gsub("([[:alpha:]])([[:alpha:]])", "\\2\\1",
"one two three")
  [1] "noe wto htere"
  > gsub("( [[:alpha:]])", "\\U\\1", "one two 
three", perl=TRUE)
  [1] "one Two  Three"

Hence you need to have 2 backslashes in the replacement to put a backslash
in the ouput when fixed is FALSE.

You need to type 2 backslashes to put 1 backslash in a string, hence you need
to type 4 backslashes to have 2 in the replacement string.

Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com

> -----Original Message-----
> From: r-help-bounces at r-project.org [mailto:r-help-bounces at
r-project.org] On Behalf
> Of Nathan Skene
> Sent: Monday, December 17, 2012 9:45 AM
> To: r-help at r-project.org
> Subject: [R] Formatting a path for unix with gsub
> 
> I have a path:
> 
> path = "/nfs/users/nfs_n/ns9/
> Phenotype Analysis/Results/Run_AmplRatio_neg
> BinaryAll trained without akapn+tnik.csv"
> 
> I wish to replace the spaces with "\ " so that it can be read by
a system
> call to unix.
> 
> Using gsub I try:
> 
> > gsub(" ","\\ ",path)
> [1] "/nfs/users/nfs_n/ns9/Phenotype Analysis/Results/Run_AmplRatio_neg
> BinaryAll trained without akapn+tnik.csv"
> 
> Various variations on this result in either adding no backslashes, or two
at
> once. How do I just get one backslash inserted?
> 
> Thanks
> 
> 	[[alternative HTML version deleted]]
> 
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