Hi everybody,
I am beginer in R and I need your precious help.
I want to create a small function in R as in sas to retrieve date.
I have a file with data that import in R.
DATE PAYS nb_pays.ILI.
1 24/04/2009 usa 0
2 24/04/2009 usa 0
3 24/04/2009 Mexique 0
4 24/04/2009 Mexique 0
5 26/04/2009 usa 20
6 26/04/2009 usa 20
7 26/04/2009 usa 20
8 26/04/2009 usa 20
9 26/04/2009 usa 20
10 26/04/2009 Mexique 18
11 27/04/2009 usa 40
12 27/04/2009 Mexique 26
13 27/04/2009 Canada 6
14 27/04/2009 Spain 1
15 28/04/2009 Canada 6
I want to create something like that:
? When entering two dates date1,date2 in the fuction extraction.
The result must be: a new subdata with one line per date , per PAYS,per
nb_pays.ILI (by summing all the number in variable nb_pays.ILI per date,per
country) and the date must be between date1 and date2.
I sart to do somethings like that
extraction=function(date1,date2)
{date<-derdata[["DATE"]]
date
sort(date)
PAYS<-derdata[["PAYS"]]
nb_pays.ILI<-derdata[["nb_pays.ILI."]]
test1<-as.character(date,"%d %m %y")
test1
#the first date
date1<- "04 03 2009"
date1 <- strptime(date1, "%d %m %Y")
date1
unlist(unclass(date1))
date1 <- as.POSIXct(date1)
date1
attributes(date1)
date1 <-unclass(date1)
date1
#the second date
date2<- "04 12 2009"
date2 <- strptime(date2, "%d %m %Y")
date2
unlist(unclass(date2))
date2 <- as.POSIXct(date2)
date2
attributes(date2)
date2 <-unclass(date2)
date2
B1<- as.POSIXct(test1)
B1 <-unclass(B1)
B1
B4 <- B1[(B1>date1) & (B1<date2)]
B4
}
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HI,
May be this helps:
dat1<-read.table(text="
?DATE?????????????????????? PAYS???????? nb_pays.ILI.
1?? 24/04/2009???????????????? usa??????????? 0
2?? 24/04/2009???????????????? usa??????????? 0
3?? 24/04/2009???????????? Mexique??????????? 0
4?? 24/04/2009???????????? Mexique??????????? 0
5?? 26/04/2009???????????????? usa?????????? 20
6?? 26/04/2009???????????????? usa?????????? 20
7?? 26/04/2009???????????????? usa?????????? 20
8?? 26/04/2009???????????????? usa?????????? 20
9?? 26/04/2009???????????????? usa?????????? 20
10? 26/04/2009???????????? Mexique?????????? 18
11? 27/04/2009???????????????? usa?????????? 40
12? 27/04/2009???????????? Mexique?????????? 26
13? 27/04/2009????????????? Canada??????????? 6
14? 27/04/2009?????????????? Spain??????????? 1
15? 27/04/2009?????????????? Spain??????????? 18
16? 28/04/2009???????????? Canada???????????? 6
",sep="",header=TRUE,stringsAsFactors=FALSE)
fun1<-function(dat,date1,date2){
date1new<-as.Date(date1,format="%d/%m/%Y")
date2new<-as.Date(date2,format="%d/%m/%Y")
dat[,1]<-as.Date(dat$DATE,format="%d/%m/%Y")
res1<-with(dat,aggregate(nb_pays.ILI.,by=list(DATE,PAYS),sum))
names(res1)<-names(dat)
res2<-res1[res1[,1]>=date1new & res1[,1] <=date2new,]
res2<-res2[order(res2[,1],res2[,2]),]
#res2[,1]<-as.POSIXct(res2[,1])??? #if you want to convert to as.POSIXct()
rownames(res2)<-1:nrow(res2)
res2}
date1="24/04/2009"
?date2="27/04/2009"
?fun1(dat1,date1,date2)
#??????? DATE??? PAYS nb_pays.ILI.
#1 2009-04-24 Mexique??????????? 0
#2 2009-04-24???? usa??????????? 0
#3 2009-04-26 Mexique?????????? 18
#4 2009-04-26???? usa????????? 100
#5 2009-04-27? Canada??????????? 6
#6 2009-04-27 Mexique?????????? 26
#7 2009-04-27?? Spain?????????? 19
#8 2009-04-27???? usa?????????? 40
fun1(dat1,"27/04/2009","28/04/2009")
#??????? DATE??? PAYS nb_pays.ILI.
#1 2009-04-27? Canada??????????? 6
#2 2009-04-27 Mexique?????????? 26
#3 2009-04-27?? Spain?????????? 19
#4 2009-04-27???? usa?????????? 40
#5 2009-04-28? Canada??????????? 6
A.K.
----- Original Message -----
From: anoumou <teko_maurice at yahoo.fr>
To: r-help at r-project.org
Cc:
Sent: Saturday, November 10, 2012 8:21 AM
Subject: [R] help on date dataset
Hi everybody,
I am beginer in R and I need your precious help.
I want to create a small function? in R as in sas to retrieve date.
I have a file with data that import in R.
DATE? ? ? ? ? ? ? ? ? ? ? PAYS? ? ? ? nb_pays.ILI.
1? 24/04/2009? ? ? ? ? ? ? ? usa? ? ? ? ? ? 0
2? 24/04/2009? ? ? ? ? ? ? ? usa? ? ? ? ? ? 0
3? 24/04/2009? ? ? ? ? ? Mexique? ? ? ? ? ? 0
4? 24/04/2009? ? ? ? ? ? Mexique? ? ? ? ? ? 0
5? 26/04/2009? ? ? ? ? ? ? ? usa? ? ? ? ? 20
6? 26/04/2009? ? ? ? ? ? ? ? usa? ? ? ? ? 20
7? 26/04/2009? ? ? ? ? ? ? ? usa? ? ? ? ? 20
8? 26/04/2009? ? ? ? ? ? ? ? usa? ? ? ? ? 20
9? 26/04/2009? ? ? ? ? ? ? ? usa? ? ? ? ? 20
10? 26/04/2009? ? ? ? ? ? Mexique? ? ? ? ? 18
11? 27/04/2009? ? ? ? ? ? ? ? usa? ? ? ? ? 40
12? 27/04/2009? ? ? ? ? ? Mexique? ? ? ? ? 26
13? 27/04/2009? ? ? ? ? ? ? Canada? ? ? ? ? ? 6
14? 27/04/2009? ? ? ? ? ? ? Spain? ? ? ? ? ? 1
15? 28/04/2009? ? ? ? ? ? Canada? ? ? ? ? ? 6
I want to create something like that:
???? When entering two dates date1,date2 in the fuction extraction.
The result must be: a? new subdata? with one line? per date , per PAYS,per
nb_pays.ILI (by summing all the number in variable nb_pays.ILI per date,per
country)? and the date must be between date1 and date2.
I sart to do somethings like that
extraction=function(date1,date2)
? {date<-derdata[["DATE"]]
? date
? sort(date)
? PAYS<-derdata[["PAYS"]]
? nb_pays.ILI<-derdata[["nb_pays.ILI."]]
? test1<-as.character(date,"%d %m %y")
? test1
? #the first date
? date1<- "04 03 2009"
? date1 <- strptime(date1, "%d %m %Y")
? date1
? unlist(unclass(date1))
? date1 <- as.POSIXct(date1)
? date1
? attributes(date1)
? date1 <-unclass(date1)
? date1
?
? #the second date
? date2<- "04 12 2009"
? date2 <- strptime(date2, "%d %m %Y")
? date2
? unlist(unclass(date2))
? date2 <- as.POSIXct(date2)
? date2
? attributes(date2)
? date2 <-unclass(date2)
? date2
? B1<- as.POSIXct(test1)
? B1 <-unclass(B1)
? B1
? B4 <- B1[(B1>date1) & (B1<date2)]
? B4
?
}
--
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______________________________________________
R-help at r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Hello,
If I understand it correctly, you have a data.frame whose first column
is a date and want to extract all lines between two given dates. If so,
try the following. Note that I've added two new arguments to your function.
dat <- read.table(text="
DATE PAYS nb_pays.ILI.
1 24/04/2009 usa 0
2 24/04/2009 usa 0
3 24/04/2009 Mexique 0
4 24/04/2009 Mexique 0
5 26/04/2009 usa 20
6 26/04/2009 usa 20
7 26/04/2009 usa 20
8 26/04/2009 usa 20
9 26/04/2009 usa 20
10 26/04/2009 Mexique 18
11 27/04/2009 usa 40
12 27/04/2009 Mexique 26
13 27/04/2009 Canada 6
14 27/04/2009 Spain 1
15 28/04/2009 Canada 6
", header = TRUE)
dat
dat$DATE <- as.Date(dat$DATE, format = "%d/%m/%Y")
extraction <- function(DF, date1, date2, format = "%Y-%m-%d"){
date1 <- as.Date(date1, format)
date2 <- as.Date(date2, format)
idx <- date1 < DF[[1]] & DF[[1]] < date2
DF[idx, ]
}
date1 <- "04 03 2009"
date2 <- "04 12 2009"
extraction(dat, date1, date2, format = "%d %m %Y")
Hope this helps,
Rui Barradas
Em 10-11-2012 13:21, anoumou escreveu:> Hi everybody,
> I am beginer in R and I need your precious help.
> I want to create a small function in R as in sas to retrieve date.
> I have a file with data that import in R.
> DATE PAYS nb_pays.ILI.
> 1 24/04/2009 usa 0
> 2 24/04/2009 usa 0
> 3 24/04/2009 Mexique 0
> 4 24/04/2009 Mexique 0
> 5 26/04/2009 usa 20
> 6 26/04/2009 usa 20
> 7 26/04/2009 usa 20
> 8 26/04/2009 usa 20
> 9 26/04/2009 usa 20
> 10 26/04/2009 Mexique 18
> 11 27/04/2009 usa 40
> 12 27/04/2009 Mexique 26
> 13 27/04/2009 Canada 6
> 14 27/04/2009 Spain 1
> 15 28/04/2009 Canada 6
>
> I want to create something like that:
> ? When entering two dates date1,date2 in the fuction extraction.
> The result must be: a new subdata with one line per date , per PAYS,per
> nb_pays.ILI (by summing all the number in variable nb_pays.ILI per date,per
> country) and the date must be between date1 and date2.
> I sart to do somethings like that
> extraction=function(date1,date2)
> {date<-derdata[["DATE"]]
> date
> sort(date)
> PAYS<-derdata[["PAYS"]]
> nb_pays.ILI<-derdata[["nb_pays.ILI."]]
> test1<-as.character(date,"%d %m %y")
> test1
> #the first date
> date1<- "04 03 2009"
> date1 <- strptime(date1, "%d %m %Y")
> date1
> unlist(unclass(date1))
> date1 <- as.POSIXct(date1)
> date1
> attributes(date1)
> date1 <-unclass(date1)
> date1
>
> #the second date
> date2<- "04 12 2009"
> date2 <- strptime(date2, "%d %m %Y")
> date2
> unlist(unclass(date2))
> date2 <- as.POSIXct(date2)
> date2
> attributes(date2)
> date2 <-unclass(date2)
> date2
> B1<- as.POSIXct(test1)
> B1 <-unclass(B1)
> B1
> B4 <- B1[(B1>date1) & (B1<date2)]
> B4
>
> }
>
>
>
>
> --
> View this message in context:
http://r.789695.n4.nabble.com/help-on-date-dataset-tp4649175.html
> Sent from the R help mailing list archive at Nabble.com.
>
> ______________________________________________
> R-help at r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
Ok, I've coerced DATE to class Date before running the function:
dat$DATE <- as.Date(dat$DATE, format = "%d/%m/%Y")
Without it the function would be:
extraction <- function(DF, date1, date2, format = "%Y-%m-%d"){
date <- as.Date(DF[[1]], format)
date1 <- as.Date(date1, format)
date2 <- as.Date(date2, format)
idx <- date1 < date & date < date2
aggregate(DF[idx, 3], DF[idx, 1:2], FUN = sum)
}
date1<-"24/04/2009"
date2<-"27/04/2009"
extraction(dat, date1, date2, format = "%d/%m/%Y")
# DATE PAYS x
#1 26/04/2009 Mexique 18
#2 26/04/2009 usa 100
Note also that the op uses '<' and '>' not'<='
and '>=' so our results
are different.
Rui Barradas
Em 10-11-2012 19:15, arun escreveu:> Thanks Rui,
>
> I tried that too:
> dat <- read.table(text="
> DATE PAYS nb_pays.ILI.
> 1 24/04/2009 usa 0
> 2 24/04/2009 usa 0
> 3 24/04/2009 Mexique 0
> 4 24/04/2009 Mexique 0
> 5 26/04/2009 usa 20
> 6 26/04/2009 usa 20
> 7 26/04/2009 usa 20
> 8 26/04/2009 usa 20
> 9 26/04/2009 usa 20
> 10 26/04/2009 Mexique 18
> 11 27/04/2009 usa 40
> 12 27/04/2009 Mexique 26
> 13 27/04/2009 Canada 6
> 14 27/04/2009 Spain 1
> 15 28/04/2009 Canada 6
> ", header = TRUE)
>
>
> extraction <- function(DF, date1, date2, format = "%Y-%m-%d"){
> date1 <- as.Date(date1, format)
> date2 <- as.Date(date2, format)
> idx <- date1 < DF[[1]] & DF[[1]] < date2
> aggregate(DF[idx, 3], DF[idx, 1:2], FUN = sum)
> }
>
>
>
> extraction(dat,"24/04/2009","26/04/2009",
format="%d/%m/%Y")
> #Error in aggregate.data.frame(as.data.frame(x), ...) :
> # no rows to aggregate
> #In addition: Warning messages:
> #1: In extraction(dat, "24/04/2009", "26/04/2009",
format = "%d/%m/%Y") :
> # Incompatible methods ("Ops.Date", "Ops.factor") for
"<"
> #2: In extraction(dat, "24/04/2009", "26/04/2009",
format = "%d/%m/%Y") :
> # Incompatible methods ("Ops.factor", "Ops.Date") for
"<"
>
> date1<-"24/04/2009"
> date2<-"27/04/2009"
>
> extraction(dat,"24/04/2009","26/04/2009",
format="%d/%m/%Y")
> #Error in aggregate.data.frame(as.data.frame(x), ...) :
> # no rows to aggregate
> #In addition: Warning messages:
> #1: In extraction(dat, "24/04/2009", "26/04/2009",
format = "%d/%m/%Y") :
> # Incompatible methods ("Ops.Date", "Ops.factor") for
"<"
> #2: In extraction(dat, "24/04/2009", "26/04/2009",
format = "%d/%m/%Y") :
> # Incompatible methods ("Ops.factor", "Ops.Date") for
"<"
>
> sessionInfo()
> R version 2.15.0 (2012-03-30)
> Platform: x86_64-pc-linux-gnu (64-bit)
>
> locale:
> [1] LC_CTYPE=en_US.UTF-8 LC_NUMERIC=C
> [3] LC_TIME=en_US.UTF-8 LC_COLLATE=en_US.UTF-8
> [5] LC_MONETARY=en_US.UTF-8 LC_MESSAGES=en_US.UTF-8
> [7] LC_PAPER=C LC_NAME=C
> [9] LC_ADDRESS=C LC_TELEPHONE=C
> [11] LC_MEASUREMENT=en_US.UTF-8 LC_IDENTIFICATION=C
>
> attached base packages:
> [1] stats graphics grDevices utils datasets methods base
>
> other attached packages:
> [1] zoo_1.7-7 stringr_0.6 reshape_0.8.4 plyr_1.7.1
>
> loaded via a namespace (and not attached):
> [1] grid_2.15.0 lattice_0.20-0 tools_2.15.0
>
>
>
> Arun
>
>
>
> ----- Original Message -----
> From: Rui Barradas <ruipbarradas at sapo.pt>
> To: arun <smartpink111 at yahoo.com>
> Cc: R help <r-help at r-project.org>
> Sent: Saturday, November 10, 2012 1:53 PM
> Subject: Re: [R] help on date dataset
>
> Hello,
>
> Arun, you're using the wrong format, "%Y-%m-%d" is the
default, with
> "24/04/2009" you must use
>
> extraction(dat, date1, date2, format = "%d/%m/%Y")
> # DATE PAYS x
> #1 2009-04-26 Mexique 18
> #2 2009-04-26 usa 100
>
> Rui Barradas
>
> Em 10-11-2012 18:26, arun escreveu:
>> HI Rui,
>>
>> For some reason, I am not getting the result as expected.
>> date1
>> #[1] "24/04/2009"
>> date2
>> #[1] "27/04/2009"
>>
>> extraction(dat,date1,date2,format="%Y-%m-%d")
>> #[1] DATE PAYS x
>> #<0 rows> (or 0-length row.names)
>> #Warning messages:
>> #1: In extraction(dat, date1, date2, format = "%Y-%m-%d") :
>> # Incompatible methods ("Ops.Date",
"Ops.factor") for "<"
>> #2: In extraction(dat, date1, date2, format = "%Y-%m-%d") :
>> # Incompatible methods ("Ops.factor",
"Ops.Date") for "<"
>>
>>
extraction(dat,"24/04/2009","27/04/2009",format="%Y-%m-%d")
>> #[1] DATE PAYS x
>> #<0 rows> (or 0-length row.names)
>> #Warning messages:
>> #1: In extraction(dat, "24/04/2009", "27/04/2009",
format = "%Y-%m-%d") :
>>
>> I tried with my function:
>> fun1<-function(dat,date1,date2){
>> date1new<-as.Date(date1,format="%d/%m/%Y")
>> date2new<-as.Date(date2,format="%d/%m/%Y")
>> dat[,1]<-as.Date(dat$DATE,format="%d/%m/%Y")
>> res1<-with(dat,aggregate(nb_pays.ILI.,by=list(DATE,PAYS),sum))
>> names(res1)<-names(dat)
>> res2<-res1[res1[,1]>=date1new & res1[,1] <=date2new,]
>> res2<-res2[order(res2[,1],res2[,2]),]
>> #res2[,1]<-as.POSIXct(res2[,1]) #if you want to convert to
as.POSIXct()
>> rownames(res2)<-1:nrow(res2)
>> res2}
>>
>> fun1(dat,date1,date2)
>> # DATE PAYS nb_pays.ILI.
>> #1 2009-04-24 Mexique 0
>> #2 2009-04-24 usa 0
>> #3 2009-04-26 Mexique 18
>> #4 2009-04-26 usa 100
>> #5 2009-04-27 Canada 6
>> #6 2009-04-27 Mexique 26
>> #7 2009-04-27 Spain 1
>> #8 2009-04-27 usa 40
>>
>> A.K.
>>
>>
>>
>>
>> From: Rui Barradas <ruipbarradas at sapo.pt>
>> To: anoumou <teko_maurice at yahoo.fr>
>> Cc: r-help at r-project.org
>> Sent: Saturday, November 10, 2012 12:17 PM
>> Subject: Re: [R] help on date dataset
>>
>> Hello,
>>
>> Sorry, forgot the sum part.
>>
>> extraction <- function(DF, date1, date2, format =
"%Y-%m-%d"){
>> date1 <- as.Date(date1, format)
>> date2 <- as.Date(date2, format)
>> idx <- date1 < DF[[1]] & DF[[1]] < date2
>> aggregate(DF[idx, 3], DF[idx, 1:2], FUN = sum)
>> }
>>
>>
>> Hope this helps,
>>
>> Rui Barradas
>> Em 10-11-2012 17:13, Rui Barradas escreveu:
>>> Hello,
>>>
>>> If I understand it correctly, you have a data.frame whose first
column is a date and want to extract all lines between two given dates. If so,
try the following. Note that I've added two new arguments to your function.
>>>
>>> dat <- read.table(text="
>>> DATE PAYS nb_pays.ILI.
>>> 1 24/04/2009 usa 0
>>> 2 24/04/2009 usa 0
>>> 3 24/04/2009 Mexique 0
>>> 4 24/04/2009 Mexique 0
>>> 5 26/04/2009 usa 20
>>> 6 26/04/2009 usa 20
>>> 7 26/04/2009 usa 20
>>> 8 26/04/2009 usa 20
>>> 9 26/04/2009 usa 20
>>> 10 26/04/2009 Mexique 18
>>> 11 27/04/2009 usa 40
>>> 12 27/04/2009 Mexique 26
>>> 13 27/04/2009 Canada 6
>>> 14 27/04/2009 Spain 1
>>> 15 28/04/2009 Canada 6
>>> ", header = TRUE)
>>>
>>> dat
>>> dat$DATE <- as.Date(dat$DATE, format = "%d/%m/%Y")
>>>
>>> extraction <- function(DF, date1, date2, format =
"%Y-%m-%d"){
>>> date1 <- as.Date(date1, format)
>>> date2 <- as.Date(date2, format)
>>> idx <- date1 < DF[[1]] & DF[[1]] < date2
>>> DF[idx, ]
>>> }
>>>
>>> date1 <- "04 03 2009"
>>> date2 <- "04 12 2009"
>>> extraction(dat, date1, date2, format = "%d %m %Y")
>>>
>>>
>>> Hope this helps,
>>>
>>> Rui Barradas
>>> Em 10-11-2012 13:21, anoumou escreveu:
>>>> Hi everybody,
>>>> I am beginer in R and I need your precious help.
>>>> I want to create a small function in R as in sas to retrieve
date.
>>>> I have a file with data that import in R.
>>>> DATE PAYS nb_pays.ILI.
>>>> 1 24/04/2009 usa 0
>>>> 2 24/04/2009 usa 0
>>>> 3 24/04/2009 Mexique 0
>>>> 4 24/04/2009 Mexique 0
>>>> 5 26/04/2009 usa 20
>>>> 6 26/04/2009 usa 20
>>>> 7 26/04/2009 usa 20
>>>> 8 26/04/2009 usa 20
>>>> 9 26/04/2009 usa 20
>>>> 10 26/04/2009 Mexique 18
>>>> 11 27/04/2009 usa 40
>>>> 12 27/04/2009 Mexique 26
>>>> 13 27/04/2009 Canada 6
>>>> 14 27/04/2009 Spain 1
>>>> 15 28/04/2009 Canada 6
>>>>
>>>> I want to create something like that:
>>>> ? When entering two dates date1,date2 in the fuction
extraction.
>>>> The result must be: a new subdata with one line per date ,
per PAYS,per
>>>> nb_pays.ILI (by summing all the number in variable nb_pays.ILI
per date,per
>>>> country) and the date must be between date1 and date2.
>>>> I sart to do somethings like that
>>>> extraction=function(date1,date2)
>>>> {date<-derdata[["DATE"]]
>>>> date
>>>> sort(date)
>>>> PAYS<-derdata[["PAYS"]]
>>>> nb_pays.ILI<-derdata[["nb_pays.ILI."]]
>>>> test1<-as.character(date,"%d %m %y")
>>>> test1
>>>> #the first date
>>>> date1<- "04 03 2009"
>>>> date1 <- strptime(date1, "%d %m %Y")
>>>> date1
>>>> unlist(unclass(date1))
>>>> date1 <- as.POSIXct(date1)
>>>> date1
>>>> attributes(date1)
>>>> date1 <-unclass(date1)
>>>> date1
>>>> #the second date
>>>> date2<- "04 12 2009"
>>>> date2 <- strptime(date2, "%d %m %Y")
>>>> date2
>>>> unlist(unclass(date2))
>>>> date2 <- as.POSIXct(date2)
>>>> date2
>>>> attributes(date2)
>>>> date2 <-unclass(date2)
>>>> date2
>>>> B1<- as.POSIXct(test1)
>>>> B1 <-unclass(B1)
>>>> B1
>>>> B4 <- B1[(B1>date1) & (B1<date2)]
>>>> B4
>>>> }
>>>>
>>>>
>>>>
>>>>
>>>> -- View this message in context:
http://r.789695.n4.nabble.com/help-on-date-dataset-tp4649175.html
>>>> Sent from the R help mailing list archive at Nabble.com.
>>>>
>>>> ______________________________________________
>>>> R-help at r-project.org mailing list
>>>> https://stat.ethz.ch/mailman/listinfo/r-help
>>>> PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
>>>> and provide commented, minimal, self-contained, reproducible
code.
>>> ______________________________________________
>>> R-help at r-project.org mailing list
>>> https://stat.ethz.ch/mailman/listinfo/r-help
>>> PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
>>> and provide commented, minimal, self-contained, reproducible code.
>> ______________________________________________
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>> and provide commented, minimal, self-contained, reproducible code.
>>
Rui and ,arun thanks you so much. as i am a beginner, i am on that subject since two days. Thanks,thanks so much. It works !!!!!!! -- View this message in context: http://r.789695.n4.nabble.com/help-on-date-dataset-tp4649175p4649203.html Sent from the R help mailing list archive at Nabble.com.