R help - May 2012 - replacing with NA

Dear R users, 

I was wondering  how I can replace the values of a vector with the values from
in another vector in the same row

For example, how can I replace the value of x below with NA when the value of Z
in the same row is NA?
x <-1:20
z<- c(11, 15, 17, 2, 18, 6, 7, NA, 12, 10,21, 25, 27, 12, 28, 16,17, NA, 12,
10)


Many thanks
Mintewab

________________________________________
Fr?n: Mintewab Bezabih
Skickat: den 15 maj 2012 15:53
Till: r-help at r-project.org
Kopia: r-help at r-project.org
?mne: missing observations

Dear R users,

I have missing observations in my data that I remove in my analysis. I am able
to run my codes alright but I want the non missing values to be correctly
identified and therefore want to tag my id vector along in my results. Since the
vector of ids has no role in the analysis, I dont know how to include it.



Here is my reprducable example:and my id is the vector I want to add to the
analysis somehow so that my missing values are identified. I cannot use 
na.action function and that is why I have to drop my missing obesevations
beforehand.


library(fields)
x <-1:20
y<- runif(20)
z<- c(11, 15, 17, 2, 18, 6, 7, NA, 12, 10,21, 25, 27, 12, 28, 16,
17, NA, 12, 10)
id <-1:20

mydataset<-data.frame(x, y, z)
temperature[complete.cases(mydataset),]

 x<- temperature[, c(1)]
y<- temperature[, c(2)]
z<- temperature[, c(3)]

tpsfit <- Tps(cbind(x, y), z, scale.type="unscaled")




Many thanks as always.
Regards,
Mintewab

Dear R users, 

I was wondering  how I can replace the values of a vector with the values from
in another vector in the same row

For example, how can I replace the value of x below with NA when the value of Z
in the same row is NA?
x <-1:20
z<- c(11, 15, 17, 2, 18, 6, 7, NA, 12, 10,21, 25, 27, 12, 28, 16,17, NA, 12,
10)


Many thanks
Mintewab

x[is.na(z)] <- NA

This might send you a nasty bug if x and z are different lengths
though -- just a head's up.

Michael

On Wed, May 16, 2012 at 12:55 PM, Mintewab Bezabih
<Mintewab.Bezabih at economics.gu.se> wrote:
> Dear R users,
>
> I was wondering ?how I can replace the values of a vector with the values
from in another vector in the same row
>
> For example, how can I replace the value of x below with NA when the value
of Z in the same row is NA?
> x <-1:20
> z<- c(11, 15, 17, 2, 18, 6, 7, NA, 12, 10,21, 25, 27, 12, 28, 16,17, NA,
12, 10)
>
>
> Many thanks
> Mintewab
>
> ________________________________________
> Fr?n: Mintewab Bezabih
> Skickat: den 15 maj 2012 15:53
> Till: r-help at r-project.org
> Kopia: r-help at r-project.org
> ?mne: missing observations
>
> Dear R users,
>
> I have missing observations in my data that I remove in my analysis. I am
able to run my codes alright but I want the non missing values to be correctly
identified and therefore want to tag my id vector along in my results. Since the
vector of ids has no role in the analysis, I dont know how to include it.
>
>
>
> Here is my reprducable example:and my id is the vector I want to add to the
analysis somehow so that my missing values are identified. I cannot use
?na.action function and that is why I have to drop my missing obesevations
beforehand.
>
>
> library(fields)
> x <-1:20
> y<- runif(20)
> z<- c(11, 15, 17, 2, 18, 6, 7, NA, 12, 10,21, 25, 27, 12, 28, 16,
> 17, NA, 12, 10)
> id <-1:20
>
> mydataset<-data.frame(x, y, z)
> temperature[complete.cases(mydataset),]
>
> ?x<- temperature[, c(1)]
> y<- temperature[, c(2)]
> z<- temperature[, c(3)]
>
> tpsfit <- Tps(cbind(x, y), z, scale.type="unscaled")
>
>
>
>
> Many thanks as always.
> Regards,
> Mintewab
>
> ______________________________________________
> R-help at r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.