You can add
if(is.na(tab[i])) browser()
or
if(is.na(tab[i])) break
see inline
On Fri, Feb 10, 2012 at 7:22 AM, ikuzar <razuki@hotmail.fr> wrote:
> Hi,
>
> I'd like to debug in a loop (using debug() and browser() etc but not
> print()
> ). I'am looking for the first occurence of NA.
> For instance:
>
> tab = c(1:300)
> tab[250] = NA
> len = length(tab)
> for (i in 1:len){
> if(i != len){
>
if(is.na(tab[i])) browser()
> tab[i] = tab[i]+tab[i+1]
> }
> }
>
> I do not want to do "Browse[2]> n" for each step ... I'd
like to declare a
> "browser()" in the loop with a condition. But how to write
"stop running
> when you encounter NA" ?
>
> Thanks for your help
>
> --
> View this message in context:
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> Sent from the R help mailing list archive at Nabble.com.
>
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