drflxms
2011-Sep-13 08:11 UTC
[R] How to use a variable after $ ($x) for subscripting a list, How to source from a character object (source(x))
Dear R colleagues, as result of a function a huge list is generated. From this result list I'd like to extract information. Think of the list i.e. as an object named "listResult" with the following form: [[a]] [1] [2] [3] [4] [5] [[b]] [1] [2] [3] [4] [5] [[c]] [1] [2] [3] [4] [5] where levels=c(a,b,c) I'd like to extract a data.frame like a [2] b [2] c [2] What I tried, is a function like this: library(foreach) loopExtract <- function(input) { foreach(i=1:length(levels)) %do% {listResult[[i]]$input} ... where the name of the variable [2] is meant to be the input. Unfortunately it turned out, that the "input"-variable after the $ is not substituted as expected. Subscripting the list with a variable after the $ seems not possible. The only workaround I found for that is a function like loopExtract <- function(input) { codetemplate <- as.character("result <- foreach(i=1:length(levels)) %do% {listResult[[i]]$input)}") require(stringr) write(str_replace_all(codetemplate, "input", input), file="tmp.r") source("tmp.r") return(result) } in other words I stored a template of the desired code as characters in an object, substituted the "input" string in that character object, wrote the result to a file and sourced the code of that file. I stored the result in a file cause the expression source(codetemplate) did not work. From the documentation I learned, that one can only source "connections". And there seems no chance to establish a connection to an object. (Probably no one else, except me, has such a strange idea.) Well, it works that way, but even though I am not a real programmer, I realize how dirty this solution is. There must be a much simpler and elegant way. To sum it all up, my problem can be reduced to the following two questions (1) How to subscript a list with a variable after $ (2) How to source from an object containing a code template or (probably the most promising) (3) How to avoid both ;) Unfortunately I am not experienced enough to find the solution. Please help! Greetings from sunny Munich, Felix
R. Michael Weylandt
2011-Sep-13 08:29 UTC
[R] How to use a variable after $ ($x) for subscripting a list, How to source from a character object (source(x))
I had a little bit of trouble following what exactly you mean to do (specifically, I'm having a little bit of trouble understanding your sample object "listResult" -- is it a list or a set of factors or a list of lists or something else entirely), but I believe that replacing the `$` operator with additional copies of `[` or `[[` as appropriate should get the job done. $ is, for almost all purposes, a less flexible version of `[[`. Consider the following: R> a = list(a1 = rnorm(5), rnorm(6), rnorm(7)) R> b = list(runif(5), b2 = runif(6), runif(7)) R> c = list(-runif(5), -runif(6), c3 = -runif(7)) R> A = list(a = a,b = b,c = c) R> for( i in seq_along(A)) { print(A[[i]][[3]][i]) } which seems to work for me (even if it is frustratingly opaque as to its function). Specifically, R> identical(A$a, A[["a"]]) TRUE R> identical(A$a,A[[1]]) TRUE If this doesn't work, please clarify what exactly the object you have is and what you are trying to get out of it and I'll give a more concrete answer. On Tue, Sep 13, 2011 at 4:11 AM, drflxms <drflxms@googlemail.com> wrote:> Dear R colleagues, > > as result of a function a huge list is generated. From this result list > I'd like to extract information. > > Think of the list i.e. as an object named "listResult" with the > following form: > > [[a]] > [1] [2] [3] [4] [5] > > [[b]] > [1] [2] [3] [4] [5] > > [[c]] > [1] [2] [3] [4] [5] > > where levels=c(a,b,c) > > I'd like to extract a data.frame like > > a [2] > b [2] > c [2] > > What I tried, is a function like this: > > library(foreach) > loopExtract <- function(input) { > foreach(i=1:length(levels)) %do% {listResult[[i]]$input} > ... > > where the name of the variable [2] is meant to be the input. > > Unfortunately it turned out, that the "input"-variable after the $ is > not substituted as expected. Subscripting the list with a variable after > the $ seems not possible. > The only workaround I found for that is a function like > > loopExtract <- function(input) { > codetemplate <- as.character("result <- foreach(i=1:length(levels)) %do% > {listResult[[i]]$input)}") > require(stringr) > write(str_replace_all(codetemplate, "input", input), file="tmp.r") > source("tmp.r") > return(result) > } > > in other words I stored a template of the desired code as characters in > an object, substituted the "input" string in that character object, > wrote the result to a file and sourced the code of that file. > > I stored the result in a file cause the expression source(codetemplate) > did not work. From the documentation I learned, that one can only source > "connections". And there seems no chance to establish a connection to an > object. (Probably no one else, except me, has such a strange idea.) > > Well, it works that way, but even though I am not a real programmer, I > realize how dirty this solution is. There must be a much simpler and > elegant way. > > To sum it all up, my problem can be reduced to the following two questions > > (1) How to subscript a list with a variable after $ > (2) How to source from an object containing a code template > or (probably the most promising) (3) How to avoid both ;) > > Unfortunately I am not experienced enough to find the solution. Please > help! > > Greetings from sunny Munich, Felix > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. >[[alternative HTML version deleted]]
David Winsemius
2011-Sep-13 13:15 UTC
[R] How to use a variable after $ ($x) for subscripting a list, How to source from a character object (source(x))
On Sep 13, 2011, at 4:11 AM, drflxms wrote:> Dear R colleagues, > > as result of a function a huge list is generated. From this result > list > I'd like to extract information. > > Think of the list i.e. as an object named "listResult" with the > following form: > > [[a]] > [1] [2] [3] [4] [5] > > [[b]] > [1] [2] [3] [4] [5] > > [[c]] > [1] [2] [3] [4] [5] > > where levels=c(a,b,c) > > I'd like to extract a data.frame like > > a [2] > b [2] > c [2] >Naming the last dog "cc" instead of "c": > as.data.frame(lapply(listResult, "[", 2) ) a b cc 1 2 2 2> What I tried, is a function like this: > > library(foreach) > loopExtract <- function(input) { > foreach(i=1:length(levels)) %do% {listResult[[i]]$input} > ... > > where the name of the variable [2] is meant to be the input.It would have been had you used this form:> foreach(i=1:length(levels)) %do% {listResult[[i]][[input]]}> > Unfortunately it turned out, that the "input"-variable after the $ is > not substituted as expected. Subscripting the list with a variable > after > the $ seems not possible.Correct. That is the main difference between "$" and "[[" and the reason "$" is far less useful in programming situations.> The only workaround I found for that is a function like > > loopExtract <- function(input) { > codetemplate <- as.character("result <- foreach(i=1:length(levels)) > %do% > {listResult[[i]]$input)}") > require(stringr) > write(str_replace_all(codetemplate, "input", input), file="tmp.r") > source("tmp.r") > return(result) > } > > in other words I stored a template of the desired code as characters > in > an object, substituted the "input" string in that character object, > wrote the result to a file and sourced the code of that file. > > I stored the result in a file cause the expression > source(codetemplate) > did not work. From the documentation I learned, that one can only > source > "connections". And there seems no chance to establish a connection > to an > object. (Probably no one else, except me, has such a strange idea.) > > Well, it works that way, but even though I am not a real programmer, I > realize how dirty this solution is. There must be a much simpler and > elegant way. > > To sum it all up, my problem can be reduced to the following two > questions > > (1) How to subscript a list with a variable after $ > (2) How to source from an object containing a code template > or (probably the most promising)I'm afraid you lost me after a while. If using "[[" with a character- valued argument which is intended to be interpreted is not what you needed, then make a slightly less wordy posting that has an example of what you wanted.> (3) How to avoid both ;)Avoid .... what?> > Unfortunately I am not experienced enough to find the solution. > Please help! > > Greetings from sunny Munich, Felix >-- David Winsemius, MD West Hartford, CT
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