R help - Jun 2011 - load seven files (named by date) at a time

Hello,

I'm trying to load a weeks worth of files that are each named by the 
date they were creaded (e.g., 20110601.RData), starting with the day 
before today so if today is June 1, I would like to load 20110525- 
20110531. The script was working until today, and x= 20110593 20110594 
20110595 20110596 20110597 20110598 20110599 20110600.
time=Sys.time()
t1<- as.numeric(format.Date(time, "%Y%m%d"))
#date range of data to load

t1=t1-1
t0 <-t1-7
x = t0:t1


Any solutions?

Thanks

Hi
> [R] load seven files (named by date) at a time
> 
> Hello,
> 
> I'm trying to load a weeks worth of files that are each named by the 
> date they were creaded (e.g., 20110601.RData), starting with the day 
> before today so if today is June 1, I would like to load 20110525- 
> 20110531. The script was working until today, and x= 20110593 20110594 
> 20110595 20110596 20110597 20110598 20110599 20110600.
> time=Sys.time()
> t1<- as.numeric(format.Date(time, "%Y%m%d"))
> #date range of data to load
> 
> t1=t1-1
> t0 <-t1-7
> x = t0:t1
> 
> 
> Any solutions?
work with dates not numbers

seq(as.Date(time)-7, as.Date(time)-1, by=1)

Regards
Petr
> 
> Thanks
> 
> ______________________________________________
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> PLEASE do read the posting guide 
http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.

Awesome, thanks a lot!


On 6/1/2011 11:22 AM, Petr PIKAL wrote:
> seq(as.Date(time)-7, as.Date(time)-1, by=1)