Hi:
It's not at all clear to me what you want to do. Is each component of
your list a data frame with the same structure? Are you trying to
combine them into one data frame? If so, then try
mydata <- do.call(rbind, c)
where c is the name of the list. (Not a good choice of name, by the
way - c() is a very common function in R and it's not wise to assign
another object to that name.)
If you want to do something else, perhaps you could clarify your
intentions for the list.
HTH,
Dennis
On Wed, Jun 29, 2011 at 1:04 PM, Breno Fragomeni <brenof at gmail.com>
wrote:> Hi
> I have imported some files to a list, called "importa".
> There are 43 files (importa[1], importa[2], ..., importa[43]). Now, I'm
> trying to create a new table in "r". Each table will got the data
from the
> importa partition. Like file1<-importa[1].
> I tried two ways:
> c<-list()
> for (i in 1:43) {
> c[i]=paste("prova",a[i],sep="")}
> i <- 1
> for (j in c)
> {
> j<-importa[i]
> i <- i + 1
> }
> In this one, the program created only one table, called "j" with
the data of
> the importa[43].
>
> The second trial:
> c<-list()
> for (i in 1:43) {
> c[i]=paste("prova",a[i],sep="")}
>
> i <- 1
> a<-list()
> for (j in c)
> {
> a[j]<-importa[i]
> i <- i + 1
> }
> In this one the program created another list, with the subdivisions just
> like the "importa".
>
> Anyone knows what I got to do?
> Thank you very much
>
> --
> Breno Fragomeni
> Mestrando em Gen?tica e Melhoramento Animal - Escola de Veterin?ria - UFMG
> Genetics and Animal Breeding Master's Degree Student - UFMG
>
> ? ? ? ?[[alternative HTML version deleted]]
>
>
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