R help - Apr 2011 - Undestanding return()

As soon as you execute the 'return' , the value is returned.  What you
did not show is did the code have if-then-else to go down separate
paths.

On Tue, Apr 26, 2011 at 5:29 PM, Bogaso Christofer
<bogaso.christofer at gmail.com> wrote:
> Here, I have following generic function:
>
>
>
> Fn1 <- function(x) {
>
> ? ? ? ? ? ? ? ?........
>
> ? ? ? ? ? ? ? ?return(x) ?# assume x is calculated in previous steps
>
>
>
> ? ? ? ? ? ? ? ?.........
>
> ? ? ? ? ? ? ? ?return(y) ?# assume y is calculated in previous steps
>
>
>
> ? ? ? ? ? ? ? ?..........
>
> ? ? ? ? ? ? ? ?return(z) ?# assume z is calculated in previous steps
>
> }
>
>
>
> In this case what fn1 will return. Is it the value of "x" all the
time? And
> hence this function will never calculate y and z?
>
>
>
> Thanks and regards,
>
>
>
>
>
>
> ? ? ? ?[[alternative HTML version deleted]]
>
> ______________________________________________
> R-help at r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>


-- 
Jim Holtman
Data Munger Guru

What is the problem that you are trying to solve?

Here, I have following generic function:

 

Fn1 <- function(x) {

                ........

                return(x)  # assume x is calculated in previous steps

 

                .........

                return(y)  # assume y is calculated in previous steps

 

                ..........

                return(z)  # assume z is calculated in previous steps

}

 

In this case what fn1 will return. Is it the value of "x" all the
time? And
hence this function will never calculate y and z?

 

Thanks and regards,

 

 


	[[alternative HTML version deleted]]

Yes, if there are no control statements such as "if" that prevent that
return function from being activated.
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Bogaso Christofer <bogaso.christofer@gmail.com> wrote:

Here, I have following generic function: Fn1 <- function(x) { ........
return(x) # assume x is calculated in previous steps ......... return(y) #
assume y is calculated in previous steps .......... return(z) # assume z is
calculated in previous steps } In this case what fn1 will return. Is it the
value of "x" all the time? And hence this function will never
calculate y and z? Thanks and regards, 	[[alternative HTML version
deleted]]_____________________________________________
R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and
provide commented, minimal, self-contained, reproducible code.


	[[alternative HTML version deleted]]