You need a list object indeed of a vector, try this:
rbind(df, dreps = c(rep(list(TRUE), 7), 5, 0))
On Tue, Mar 22, 2011 at 10:12 PM, Alexy Khrabrov <deliverable at
gmail.com> wrote:> I have a dataframe with many rows like this:
>
>> df
> ? ? ? ? ? ? ? ? X1 ? X2 ? X3 ? X4 ? X5 ? X6 ? X7 week ? ? ? ? d
> sim1 FALSE TRUE TRUE TRUE TRUE TRUE TRUE ? ?1 0.3064985
>
> sim1 is the rowname, X1..X7,week,d are the column names. ?X1..X7 are
factors, booleans in this case.
>
> I need to add another row, represented by the following list:
>
> list(rep(T,7),5,0.0)
>
> -- i.e, TRUE in all boolean columns, 5 in the week column, 0.0 in d. ?The
name of the new row is "dreps".
>
> I used to add fully numeric rows as follows:
>
> df1 <- rbind(df,dreps=c(<all numbers>))
>
> But if I do this here,
>
> df1 <- rbind(df,dreps=c(rep(T,7),5,0.0)) -- booleans are converted to
0/1, which is not what I want.
>
> What's the recommended way to specify and bind a heterogeneous row
above?
>
> Cheers,
> Alexy
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