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Ortiz, John

2011-Jan-20 15:12 UTC

[R] Identify duplicate numbers and to increase a value

Hi everybody.

I want to identify duplicate numbers and to increase a value of 0.01 for each
time that it is duplicated.

Example:
x=c(1,2,3,5,6,2,8,9,2,2)

I want to do this:

1
2 + 0.01
3
5 
6
2 + 0.02
8
9
2 + 0.03
2 + 0.04

I am trying to get something like this:

1
2.01
3
5
6
2.02
8
9
2.03
2.04

Actually I just know the way to identify the duplicated numbers

rbind(x, duplicated(x) | duplicated(x, fromLast=TRUE))

  [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10]
x    1    2    3    5    6    2    8    9    2     2
     0    1    0    0    0    1    0    0    1     1

Some advice?

Thanks and regards
John Ortiz

Moritz Grenke

2011-Jan-20 15:43 UTC

head link

[R] Identify duplicate numbers and to increase a value

If you haven't got so much data a loop should do: 

while(sum(duplicated(x))>0) #if this condition is TRUE then there are still
duplicates in x
{	
	x[duplicated(x)] <- x[duplicated(x)]+0.01 #using duplicated(x) to
index the x vector
}

Hope this helps, 
Regards
Moritz

____________________
Moritz Grenke
http://www.360mix.de

-----Urspr?ngliche Nachricht-----
Von: r-help-bounces at r-project.org [mailto:r-help-bounces at r-project.org] Im
Auftrag von Ortiz, John
Gesendet: Donnerstag, 20. Januar 2011 16:13
An: r-help at r-project.org
Betreff: [R] Identify duplicate numbers and to increase a value

Hi everybody.

I want to identify duplicate numbers and to increase a value of 0.01 for
each time that it is duplicated.  

Example:
x=c(1,2,3,5,6,2,8,9,2,2)

I want to do this:

1
2 + 0.01
3
5 
6
2 + 0.02
8
9
2 + 0.03
2 + 0.04

I am trying to get something like this:

1
2.01
3
5
6
2.02
8
9
2.03
2.04

Actually I just know the way to identify the duplicated numbers

rbind(x, duplicated(x) | duplicated(x, fromLast=TRUE))

  [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10]
x    1    2    3    5    6    2    8    9    2     2
     0    1    0    0    0    1    0    0    1     1

Some advice?

Thanks and regards
John Ortiz

______________________________________________
R-help at r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

Joshua Wiley

2011-Jan-20 16:00 UTC

head link

[R] Identify duplicate numbers and to increase a value

Hi John,

If you only have one duplicated number (e.g., just 2), then this will work:

x <- c(1,2,3,5,6,2,8,9,2,2)
xd <- duplicated(x)
x[xd] <- x[xd] + seq(sum(xd))/100
x

otherwise, I think a different framework than duplicated() will be
necessary, because it will matter not just if the number is duplicated
but which one how many times and where.

Cheers,

Josh

On Thu, Jan 20, 2011 at 7:12 AM, Ortiz, John <OrtizJ at si.edu>
wrote:> Hi everybody.
>
> I want to identify duplicate numbers and to increase a value of 0.01 for
each time that it is duplicated.
>
> Example:
> x=c(1,2,3,5,6,2,8,9,2,2)
>
> I want to do this:
>
> 1
> 2 + 0.01
> 3
> 5
> 6
> 2 + 0.02
> 8
> 9
> 2 + 0.03
> 2 + 0.04
>
> I am trying to get something like this:
>
> 1
> 2.01
> 3
> 5
> 6
> 2.02
> 8
> 9
> 2.03
> 2.04
>
> Actually I just know the way to identify the duplicated numbers
>
> rbind(x, duplicated(x) | duplicated(x, fromLast=TRUE))
>
> ?[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10]
> x ? ?1 ? ?2 ? ?3 ? ?5 ? ?6 ? ?2 ? ?8 ? ?9 ? ?2 ? ? 2
> ? ? 0 ? ?1 ? ?0 ? ?0 ? ?0 ? ?1 ? ?0 ? ?0 ? ?1 ? ? 1
>
> Some advice?
>
> Thanks and regards
> John Ortiz
>
> ______________________________________________
> R-help at r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>


-- 
Joshua Wiley
Ph.D. Student, Health Psychology
University of California, Los Angeles
http://www.joshuawiley.com/

James Lawrence

2011-Jan-20 16:14 UTC

head link

[R] Identify duplicate numbers and to increase a value

Hello John,

If many numbers are duplicated, then one way is to coerce to a factor
and use the levels() function. For instance:

x <- c(1,1,2,2,2,3,3,4,1,1,2,4)
X <- factor(x)
for (i in levels(X))
{
	loc <- (X==i); len = length(loc)
	x[loc] <- x[loc] + 0.01 * (1:len)
}
x

 [1] 1.01 1.02 2.01 2.02 2.03 3.01 3.02 4.01 1.03 1.04 2.04 4.02

Hope that helps

James Lawrence 

On Thu, 2011-01-20 at 08:00 -0800, Joshua Wiley wrote:> Hi John,
> 
> If you only have one duplicated number (e.g., just 2), then this will work:
> 
> x <- c(1,2,3,5,6,2,8,9,2,2)
> xd <- duplicated(x)
> x[xd] <- x[xd] + seq(sum(xd))/100
> x
> 
> otherwise, I think a different framework than duplicated() will be
> necessary, because it will matter not just if the number is duplicated
> but which one how many times and where.
> 
> Cheers,
> 
> Josh
> 
> On Thu, Jan 20, 2011 at 7:12 AM, Ortiz, John <OrtizJ at si.edu>
wrote:
> > Hi everybody.
> >
> > I want to identify duplicate numbers and to increase a value of 0.01
for each time that it is duplicated.
> >
> > Example:
> > x=c(1,2,3,5,6,2,8,9,2,2)
> >
> > I want to do this:
> >
> > 1
> > 2 + 0.01
> > 3
> > 5
> > 6
> > 2 + 0.02
> > 8
> > 9
> > 2 + 0.03
> > 2 + 0.04
> >
> > I am trying to get something like this:
> >
> > 1
> > 2.01
> > 3
> > 5
> > 6
> > 2.02
> > 8
> > 9
> > 2.03
> > 2.04
> >
> > Actually I just know the way to identify the duplicated numbers
> >
> > rbind(x, duplicated(x) | duplicated(x, fromLast=TRUE))
> >
> >  [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10]
> > x    1    2    3    5    6    2    8    9    2     2
> >     0    1    0    0    0    1    0    0    1     1
> >
> > Some advice?
> >
> > Thanks and regards
> > John Ortiz
> >
> > ______________________________________________
> > R-help at r-project.org mailing list
> > https://stat.ethz.ch/mailman/listinfo/r-help
> > PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
> > and provide commented, minimal, self-contained, reproducible code.
> >
> 
> 
>

William Dunlap

2011-Jan-20 16:15 UTC

head link

[R] Identify duplicate numbers and to increase a value

> -----Original Message-----
> From: r-help-bounces at r-project.org 
> [mailto:r-help-bounces at r-project.org] On Behalf Of Ortiz, John
> Sent: Thursday, January 20, 2011 7:13 AM
> To: r-help at r-project.org
> Subject: [R] Identify duplicate numbers and to increase a value
> 
> Hi everybody.
> 
> I want to identify duplicate numbers and to increase a value 
> of 0.01 for each time that it is duplicated.  
> 
> Example:
> x=c(1,2,3,5,6,2,8,9,2,2)
> 
> I want to do this:
> 
> 1
> 2 + 0.01
> 3
> 5 
> 6
> 2 + 0.02
> 8
> 9
> 2 + 0.03
> 2 + 0.04
Your words made it sound like you wanted the
following
  > x + (ave(x, x, FUN=seq_along)-1)/100
   [1] 1.00 2.00 3.00 5.00 6.00 2.01 8.00 9.00 2.02 2.03
but your example indicates that you want to
alter any value that has a duplicate (including
the first) so it gets a bit more complicated.
E.g.,
  > x + ave(x, x, FUN=function(xi)if(length(xi)==1) 0.0 else
seq_along(xi))/100
   [1] 1.00 2.01 3.00 5.00 6.00 2.02 8.00 9.00 2.03 2.04
You could also use subscripting to use ave() only on
those elements of x which had duplicates.

There are trickier but faster ways (based on runs) of
doing this if you have very long vectors with lots of
unique values.

Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com  
> 
> I am trying to get something like this:
> 
> 1
> 2.01
> 3
> 5
> 6
> 2.02
> 8
> 9
> 2.03
> 2.04
> 
> Actually I just know the way to identify the duplicated numbers
> 
> rbind(x, duplicated(x) | duplicated(x, fromLast=TRUE))
> 
>   [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10]
> x    1    2    3    5    6    2    8    9    2     2
>      0    1    0    0    0    1    0    0    1     1
> 
> Some advice?
> 
> Thanks and regards
> John Ortiz
> 
> ______________________________________________
> R-help at r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide 
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>

Henrique Dallazuanna

2011-Jan-20 16:22 UTC

head link

[R] Identify duplicate numbers and to increase a value

Try this:

replace(x + ave(x, x, FUN = seq) * .01, !(duplicated(x) | duplicated(x,
fromLast = TRUE)), x)

On Thu, Jan 20, 2011 at 1:12 PM, Ortiz, John <OrtizJ@si.edu> wrote:
> Hi everybody.
>
> I want to identify duplicate numbers and to increase a value of 0.01 for
> each time that it is duplicated.
>
> Example:
> x=c(1,2,3,5,6,2,8,9,2,2)
>
> I want to do this:
>
> 1
> 2 + 0.01
> 3
> 5
> 6
> 2 + 0.02
> 8
> 9
> 2 + 0.03
> 2 + 0.04
>
> I am trying to get something like this:
>
> 1
> 2.01
> 3
> 5
> 6
> 2.02
> 8
> 9
> 2.03
> 2.04
>
> Actually I just know the way to identify the duplicated numbers
>
> rbind(x, duplicated(x) | duplicated(x, fromLast=TRUE))
>
>  [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10]
> x    1    2    3    5    6    2    8    9    2     2
>     0    1    0    0    0    1    0    0    1     1
>
> Some advice?
>
> Thanks and regards
> John Ortiz
>
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>


-- 
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40" S 49° 16' 22" O

	[[alternative HTML version deleted]]

Gabor Grothendieck

2011-Jan-20 17:15 UTC

head link

[R] Identify duplicate numbers and to increase a value

On Thu, Jan 20, 2011 at 10:12 AM, Ortiz, John <OrtizJ at si.edu>
wrote:> Hi everybody.
>
> I want to identify duplicate numbers and to increase a value of 0.01 for
each time that it is duplicated.
>
> Example:
> x=c(1,2,3,5,6,2,8,9,2,2)
>
> I want to do this:
>
> 1
> 2 + 0.01
> 3
> 5
> 6
> 2 + 0.02
> 8
> 9
> 2 + 0.03
> 2 + 0.04
>
> I am trying to get something like this:
>
> 1
> 2.01
> 3
> 5
> 6
> 2.02
> 8
> 9
> 2.03
> 2.04
>
> Actually I just know the way to identify the duplicated numbers
>
> rbind(x, duplicated(x) | duplicated(x, fromLast=TRUE))
>
> ?[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10]
> x ? ?1 ? ?2 ? ?3 ? ?5 ? ?6 ? ?2 ? ?8 ? ?9 ? ?2 ? ? 2
> ? ? 0 ? ?1 ? ?0 ? ?0 ? ?0 ? ?1 ? ?0 ? ?0 ? ?1 ? ? 1
>
There is a function in the unreleased zooExtra package that will
uniquify numbers via linear interpolation:
> library(zoo)
>
source("http://r-forge.r-project.org/scm/viewvc.php/*checkout*/pkg/zooExtra/R/make.unique.R?root=zoo")
> x <- c(1, 2, 3, 5, 6, 2, 8, 9, 2, 2)
>
>
> make.unique.approx(x)
 [1] 1.00 2.00 3.00 5.00 6.00 2.25 8.00 9.00 2.50 2.75>
> # If you wish to make the increments smaller:
>
> ifelse(x == y, x, x + (y-x)/100) [1] 1.0000 2.0000 3.0000 5.0000 6.0000 2.0025 8.0000 9.0000 2.0050 2.0075



-- 
Statistics & Software Consulting
GKX Group, GKX Associates Inc.
tel: 1-877-GKX-GROUP
email: ggrothendieck at gmail.com

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