Hi, I have defined a function (my.func) which is used as parameter (f) of another function. As I want to give the user the possibility to define his own function instead of my.func, how can I find out if in other functions, the parameter f has the my.func value (if the user has defined a new function or not)? Moreover, I think I should impose to the user to use another function name than my.func for this (?). Or a boolean variable is better to be used to indicate if my function (my.func) or user-defined function is used? Thanks Carol
Wel, just let the user give the function in form of an argument, say
"foo", and use your code so that
bar <- function(x, ....., foo){
if(missing(foo)) foo <- Namespace::my.func
.....
}
but perhaps I misunderstood your question.
Uwe Ligges
On 10.01.2011 13:47, carol white wrote:> Hi,
> I have defined a function (my.func) which is used as parameter (f) of
another
> function. As I want to give the user the possibility to define his own
function
> instead of my.func, how can I find out if in other functions, the parameter
f
> has the my.func value (if the user has defined a new function or not)?
>
>
> Moreover, I think I should impose to the user to use another function name
than
> my.func for this (?). Or a boolean variable is better to be used to
indicate if
> my function (my.func) or user-defined function is used?
>
> Thanks
>
> Carol
>
> ______________________________________________
> R-help at r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
In fact, what the function is returning is the most important. So knowing that
the parameters and the number of parameters of my.func defined by the user could
be different from one definition to another, how to use what my.func returns in
other functions? Moreover, if the function is defined by the user in an R
session, it is then defined globally. In this case, does it need to be passed as
a parameter? Note that my.func defined by me is loaded before.
Carol
----- Original Message ----
From: Uwe Ligges <ligges at statistik.tu-dortmund.de>
To: carol white <wht_crl at yahoo.com>
Cc: r-help at stat.math.ethz.ch
Sent: Mon, January 10, 2011 2:11:48 PM
Subject: Re: [R] Evaluation of variable assigned to a function name
Wel, just let the user give the function in form of an argument, say
"foo", and use your code so that
bar <- function(x, ....., foo){
if(missing(foo)) foo <- Namespace::my.func
.....
}
but perhaps I misunderstood your question.
Uwe Ligges
On 10.01.2011 13:47, carol white wrote:> Hi,
> I have defined a function (my.func) which is used as parameter (f) of
another
> function. As I want to give the user the possibility to define his own
function> instead of my.func, how can I find out if in other functions, the parameter
f
> has the my.func value (if the user has defined a new function or not)?
>
>
> Moreover, I think I should impose to the user to use another function name
than> my.func for this (?). Or a boolean variable is better to be used to
indicate
if> my function (my.func) or user-defined function is used?
>
> Thanks
>
> Carol
>
> ______________________________________________
> R-help at r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
On 10.01.2011 14:39, carol white wrote:> In fact, what the function is returning is the most important. So knowing that > the parameters and the number of parameters of my.func defined by the user could > be different from one definition to another, how to use what my.func returns in > other functions? Moreover, if the function is defined by the user in an R > session, it is then defined globally. In this case, does it need to be passed as > a parameter? Note that my.func defined by me is loaded before.It depends. 1. The output of a function can always be wrapped in a list. 2. You should always pass objects that you want to use in another environment unless you really know what you are doing - and reading does not suggest you are too sure about it. 3. In this case, if your package has a Namespace, your own function rather than a user generated one in the .GlobalEnv will be found. Note that defining stuff in .GlobalEnv and relying on the fact that this version is found by another function would imply you really have to get it from the specific environment. Best, Uwe> Carol > > > > ----- Original Message ---- > From: Uwe Ligges<ligges at statistik.tu-dortmund.de> > To: carol white<wht_crl at yahoo.com> > Cc: r-help at stat.math.ethz.ch > Sent: Mon, January 10, 2011 2:11:48 PM > Subject: Re: [R] Evaluation of variable assigned to a function name > > Wel, just let the user give the function in form of an argument, say > "foo", and use your code so that > > > bar<- function(x, ....., foo){ > if(missing(foo)) foo<- Namespace::my.func > ..... > } > > > but perhaps I misunderstood your question. > > Uwe Ligges > > > > On 10.01.2011 13:47, carol white wrote: >> Hi, >> I have defined a function (my.func) which is used as parameter (f) of another >> function. As I want to give the user the possibility to define his own > function >> instead of my.func, how can I find out if in other functions, the parameter f >> has the my.func value (if the user has defined a new function or not)? >> >> >> Moreover, I think I should impose to the user to use another function name > than >> my.func for this (?). Or a boolean variable is better to be used to indicate > if >> my function (my.func) or user-defined function is used? >> >> Thanks >> >> Carol >> >> ______________________________________________ >> R-help at r-project.org mailing list >> https://stat.ethz.ch/mailman/listinfo/r-help >> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html >> and provide commented, minimal, self-contained, reproducible code. > > > >
Let the following definitions:
# my definition
my.func <- function (x,y,z){
....
return (v)
}
# user-defined definition
my.func <- function (x){
...
return(v)
}
Considering that my.func can have different parameters but always return a
vector, how to use v in bar by initializing parameters when calling my.func (x =
2 or a = 3,y=4,z=5)? How can my.func could be invoked in bar and v could be
used?
bar<- function(x, ....., foo){> if(missing(foo)) foo<- Namespace::my.func
> .....
> }
----- Original Message ----
From: Uwe Ligges <ligges at statistik.tu-dortmund.de>
To: carol white <wht_crl at yahoo.com>
Cc: r-help at stat.math.ethz.ch
Sent: Mon, January 10, 2011 2:48:04 PM
Subject: Re: [R] Evaluation of variable assigned to a function name
On 10.01.2011 14:39, carol white wrote:> In fact, what the function is returning is the most important. So knowing
that
> the parameters and the number of parameters of my.func defined by the user
>could
> be different from one definition to another, how to use what my.func
returns
in> other functions? Moreover, if the function is defined by the user in an R
> session, it is then defined globally. In this case, does it need to be
passed
>as
> a parameter? Note that my.func defined by me is loaded before.
It depends.
1. The output of a function can always be wrapped in a list.
2. You should always pass objects that you want to use in another
environment unless you really know what you are doing - and reading does
not suggest you are too sure about it.
3. In this case, if your package has a Namespace, your own function
rather than a user generated one in the .GlobalEnv will be found.
Note that defining stuff in .GlobalEnv and relying on the fact that this
version is found by another function would imply you really have to get
it from the specific environment.
Best,
Uwe
> Carol
>
>
>
> ----- Original Message ----
> From: Uwe Ligges<ligges at statistik.tu-dortmund.de>
> To: carol white<wht_crl at yahoo.com>
> Cc: r-help at stat.math.ethz.ch
> Sent: Mon, January 10, 2011 2:11:48 PM
> Subject: Re: [R] Evaluation of variable assigned to a function name
>
> Wel, just let the user give the function in form of an argument, say
> "foo", and use your code so that
>
>
> bar<- function(x, ....., foo){
> if(missing(foo)) foo<- Namespace::my.func
> .....
> }
>
>
> but perhaps I misunderstood your question.
>
> Uwe Ligges
>
>
>
> On 10.01.2011 13:47, carol white wrote:
>> Hi,
>> I have defined a function (my.func) which is used as parameter (f) of
another
>> function. As I want to give the user the possibility to define his own
> function
>> instead of my.func, how can I find out if in other functions, the
parameter f
>> has the my.func value (if the user has defined a new function or not)?
>>
>>
>> Moreover, I think I should impose to the user to use another function
name
> than
>> my.func for this (?). Or a boolean variable is better to be used to
indicate
> if
>> my function (my.func) or user-defined function is used?
>>
>> Thanks
>>
>> Carol
>>
>> ______________________________________________
>> R-help at r-project.org mailing list
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>
>
>
>
On 10.01.2011 14:56, carol white wrote:> Let the following definitions: > > > # my definition > my.func<- function (x,y,z){ > .... > return (v) > } > > # user-defined definition > my.func<- function (x){ > ... > return(v) > } > > Considering that my.func can have different parameters but always return a > vector, how to use v in bar by initializing parameters when calling my.func (x > 2 or a = 3,y=4,z=5)? How can my.func could be invoked in bar and v could be > used?Well, both versions will need the same number of arguments unless you want to pass the as well. Example: bar <- function(arglist, foo){ if(missing(foo)) foo <- my.func v <- do.call(foo, arglist) return(v*3) } my.func <- function(x,y,z){ return(x+y+z) } my.func.user <- function(x){ return(x) } Then you can do, e.g.: bar(arglist=list(x=1, y=2, z=3)) bar(arglist=list(x=1), foo=my.func.user) Hope this clarifies the idea. Best, Uwe> > bar<- function(x, ....., foo){ >> if(missing(foo)) foo<- Namespace::my.func >> ..... >> } > > > > ----- Original Message ---- > From: Uwe Ligges<ligges at statistik.tu-dortmund.de> > To: carol white<wht_crl at yahoo.com> > Cc: r-help at stat.math.ethz.ch > Sent: Mon, January 10, 2011 2:48:04 PM > Subject: Re: [R] Evaluation of variable assigned to a function name > > > > On 10.01.2011 14:39, carol white wrote: >> In fact, what the function is returning is the most important. So knowing that >> the parameters and the number of parameters of my.func defined by the user >> could >> be different from one definition to another, how to use what my.func returns > in >> other functions? Moreover, if the function is defined by the user in an R >> session, it is then defined globally. In this case, does it need to be passed >> as >> a parameter? Note that my.func defined by me is loaded before. > > It depends. > > 1. The output of a function can always be wrapped in a list. > 2. You should always pass objects that you want to use in another > environment unless you really know what you are doing - and reading does > not suggest you are too sure about it. > 3. In this case, if your package has a Namespace, your own function > rather than a user generated one in the .GlobalEnv will be found. > > Note that defining stuff in .GlobalEnv and relying on the fact that this > version is found by another function would imply you really have to get > it from the specific environment. > > Best, > Uwe > > > > >> Carol >> >> >> >> ----- Original Message ---- >> From: Uwe Ligges<ligges at statistik.tu-dortmund.de> >> To: carol white<wht_crl at yahoo.com> >> Cc: r-help at stat.math.ethz.ch >> Sent: Mon, January 10, 2011 2:11:48 PM >> Subject: Re: [R] Evaluation of variable assigned to a function name >> >> Wel, just let the user give the function in form of an argument, say >> "foo", and use your code so that >> >> >> bar<- function(x, ....., foo){ >> if(missing(foo)) foo<- Namespace::my.func >> ..... >> } >> >> >> but perhaps I misunderstood your question. >> >> Uwe Ligges >> >> >> >> On 10.01.2011 13:47, carol white wrote: >>> Hi, >>> I have defined a function (my.func) which is used as parameter (f) of another >>> function. As I want to give the user the possibility to define his own >> function >>> instead of my.func, how can I find out if in other functions, the parameter f >>> has the my.func value (if the user has defined a new function or not)? >>> >>> >>> Moreover, I think I should impose to the user to use another function name >> than >>> my.func for this (?). Or a boolean variable is better to be used to indicate >> if >>> my function (my.func) or user-defined function is used? >>> >>> Thanks >>> >>> Carol >>> >>> ______________________________________________ >>> R-help at r-project.org mailing list >>> https://stat.ethz.ch/mailman/listinfo/r-help >>> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html >>> and provide commented, minimal, self-contained, reproducible code. >> >> >> >> > > > >
Note that I will call my function or user-defined function in bar function to
have the value that my or user-defined function returns. So how can these
function be invoked? Can it be like this?
bar <- function(arglist, foo){
if(missing(foo)) {
foo <- my.func
v = my.func(x = 2)
}
else{
foo <- my.func.user
v <- do.call(foo, arglist) # since arglist is not known in advance
}
return(v*3)
}
----- Original Message ----
From: Uwe Ligges <ligges at statistik.tu-dortmund.de>
To: carol white <wht_crl at yahoo.com>
Cc: r-help at stat.math.ethz.ch
Sent: Mon, January 10, 2011 3:04:19 PM
Subject: Re: [R] Evaluation of variable assigned to a function name
On 10.01.2011 14:56, carol white wrote:> Let the following definitions:
>
>
> # my definition
> my.func<- function (x,y,z){
> ....
> return (v)
> }
>
> # user-defined definition
> my.func<- function (x){
> ...
> return(v)
> }
>
> Considering that my.func can have different parameters but always return a
> vector, how to use v in bar by initializing parameters when calling my.func
(x
>> 2 or a = 3,y=4,z=5)? How can my.func could be invoked in bar and v
could be
> used?
Well, both versions will need the same number of arguments unless you
want to pass the as well. Example:
bar <- function(arglist, foo){
if(missing(foo)) foo <- my.func
v <- do.call(foo, arglist)
return(v*3)
}
my.func <- function(x,y,z){
return(x+y+z)
}
my.func.user <- function(x){
return(x)
}
Then you can do, e.g.:
bar(arglist=list(x=1, y=2, z=3))
bar(arglist=list(x=1), foo=my.func.user)
Hope this clarifies the idea.
Best,
Uwe
>
> bar<- function(x, ....., foo){
>> if(missing(foo)) foo<- Namespace::my.func
>> .....
>> }
>
>
>
> ----- Original Message ----
> From: Uwe Ligges<ligges at statistik.tu-dortmund.de>
> To: carol white<wht_crl at yahoo.com>
> Cc: r-help at stat.math.ethz.ch
> Sent: Mon, January 10, 2011 2:48:04 PM
> Subject: Re: [R] Evaluation of variable assigned to a function name
>
>
>
> On 10.01.2011 14:39, carol white wrote:
>> In fact, what the function is returning is the most important. So
knowing
that>> the parameters and the number of parameters of my.func defined by the
user
>> could
>> be different from one definition to another, how to use what my.func
returns
> in
>> other functions? Moreover, if the function is defined by the user in an
R
>> session, it is then defined globally. In this case, does it need to be
passed
>> as
>> a parameter? Note that my.func defined by me is loaded before.
>
> It depends.
>
> 1. The output of a function can always be wrapped in a list.
> 2. You should always pass objects that you want to use in another
> environment unless you really know what you are doing - and reading does
> not suggest you are too sure about it.
> 3. In this case, if your package has a Namespace, your own function
> rather than a user generated one in the .GlobalEnv will be found.
>
> Note that defining stuff in .GlobalEnv and relying on the fact that this
> version is found by another function would imply you really have to get
> it from the specific environment.
>
> Best,
> Uwe
>
>
>
>
>> Carol
>>
>>
>>
>> ----- Original Message ----
>> From: Uwe Ligges<ligges at statistik.tu-dortmund.de>
>> To: carol white<wht_crl at yahoo.com>
>> Cc: r-help at stat.math.ethz.ch
>> Sent: Mon, January 10, 2011 2:11:48 PM
>> Subject: Re: [R] Evaluation of variable assigned to a function name
>>
>> Wel, just let the user give the function in form of an argument, say
>> "foo", and use your code so that
>>
>>
>> bar<- function(x, ....., foo){
>> if(missing(foo)) foo<- Namespace::my.func
>> .....
>> }
>>
>>
>> but perhaps I misunderstood your question.
>>
>> Uwe Ligges
>>
>>
>>
>> On 10.01.2011 13:47, carol white wrote:
>>> Hi,
>>> I have defined a function (my.func) which is used as parameter (f)
of
another>>> function. As I want to give the user the possibility to define his
own
>> function
>>> instead of my.func, how can I find out if in other functions, the
parameter
f>>> has the my.func value (if the user has defined a new function or
not)?
>>>
>>>
>>> Moreover, I think I should impose to the user to use another
function name
>> than
>>> my.func for this (?). Or a boolean variable is better to be used to
indicate
>> if
>>> my function (my.func) or user-defined function is used?
>>>
>>> Thanks
>>>
>>> Carol
>>>
>>> ______________________________________________
>>> R-help at r-project.org mailing list
>>> https://stat.ethz.ch/mailman/listinfo/r-help
>>> PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
>>> and provide commented, minimal, self-contained, reproducible code.
>>
>>
>>
>>
>
>
>
>
On 10.01.2011 16:41, carol white wrote:> Note that I will call my function or user-defined function in bar function to > have the value that my or user-defined function returns. So how can these > function be invoked? Can it be like this? > > bar<- function(arglist, foo){ > if(missing(foo)) { > foo<- my.func > v = my.func(x = 2) > } > else{ > foo<- my.func.userThe line abopve does nt make sense now, the rest seems to be fine. Uwe> v<- do.call(foo, arglist) # since arglist is not known in advance > } > return(v*3) > } > > > > ----- Original Message ---- > From: Uwe Ligges<ligges at statistik.tu-dortmund.de> > To: carol white<wht_crl at yahoo.com> > Cc: r-help at stat.math.ethz.ch > Sent: Mon, January 10, 2011 3:04:19 PM > Subject: Re: [R] Evaluation of variable assigned to a function name > > > > On 10.01.2011 14:56, carol white wrote: >> Let the following definitions: >> >> >> # my definition >> my.func<- function (x,y,z){ >> .... >> return (v) >> } >> >> # user-defined definition >> my.func<- function (x){ >> ... >> return(v) >> } >> >> Considering that my.func can have different parameters but always return a >> vector, how to use v in bar by initializing parameters when calling my.func (x >> >> 2 or a = 3,y=4,z=5)? How can my.func could be invoked in bar and v could be >> used? > > > Well, both versions will need the same number of arguments unless you > want to pass the as well. Example: > > bar<- function(arglist, foo){ > if(missing(foo)) foo<- my.func > v<- do.call(foo, arglist) > return(v*3) > } > > my.func<- function(x,y,z){ > return(x+y+z) > } > > my.func.user<- function(x){ > return(x) > } > > > Then you can do, e.g.: > > bar(arglist=list(x=1, y=2, z=3)) > > bar(arglist=list(x=1), foo=my.func.user) > > > Hope this clarifies the idea. > > Best, > Uwe > > > > > > >> >> bar<- function(x, ....., foo){ >>> if(missing(foo)) foo<- Namespace::my.func >>> ..... >>> } >> >> >> >> ----- Original Message ---- >> From: Uwe Ligges<ligges at statistik.tu-dortmund.de> >> To: carol white<wht_crl at yahoo.com> >> Cc: r-help at stat.math.ethz.ch >> Sent: Mon, January 10, 2011 2:48:04 PM >> Subject: Re: [R] Evaluation of variable assigned to a function name >> >> >> >> On 10.01.2011 14:39, carol white wrote: >>> In fact, what the function is returning is the most important. So knowing > that >>> the parameters and the number of parameters of my.func defined by the user >>> could >>> be different from one definition to another, how to use what my.func returns >> in >>> other functions? Moreover, if the function is defined by the user in an R >>> session, it is then defined globally. In this case, does it need to be passed >>> as >>> a parameter? Note that my.func defined by me is loaded before. >> >> It depends. >> >> 1. The output of a function can always be wrapped in a list. >> 2. You should always pass objects that you want to use in another >> environment unless you really know what you are doing - and reading does >> not suggest you are too sure about it. >> 3. In this case, if your package has a Namespace, your own function >> rather than a user generated one in the .GlobalEnv will be found. >> >> Note that defining stuff in .GlobalEnv and relying on the fact that this >> version is found by another function would imply you really have to get >> it from the specific environment. >> >> Best, >> Uwe >> >> >> >> >>> Carol >>> >>> >>> >>> ----- Original Message ---- >>> From: Uwe Ligges<ligges at statistik.tu-dortmund.de> >>> To: carol white<wht_crl at yahoo.com> >>> Cc: r-help at stat.math.ethz.ch >>> Sent: Mon, January 10, 2011 2:11:48 PM >>> Subject: Re: [R] Evaluation of variable assigned to a function name >>> >>> Wel, just let the user give the function in form of an argument, say >>> "foo", and use your code so that >>> >>> >>> bar<- function(x, ....., foo){ >>> if(missing(foo)) foo<- Namespace::my.func >>> ..... >>> } >>> >>> >>> but perhaps I misunderstood your question. >>> >>> Uwe Ligges >>> >>> >>> >>> On 10.01.2011 13:47, carol white wrote: >>>> Hi, >>>> I have defined a function (my.func) which is used as parameter (f) of > another >>>> function. As I want to give the user the possibility to define his own >>> function >>>> instead of my.func, how can I find out if in other functions, the parameter > f >>>> has the my.func value (if the user has defined a new function or not)? >>>> >>>> >>>> Moreover, I think I should impose to the user to use another function name >>> than >>>> my.func for this (?). Or a boolean variable is better to be used to indicate >>> if >>>> my function (my.func) or user-defined function is used? >>>> >>>> Thanks >>>> >>>> Carol >>>> >>>> ______________________________________________ >>>> R-help at r-project.org mailing list >>>> https://stat.ethz.ch/mailman/listinfo/r-help >>>> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html >>>> and provide commented, minimal, self-contained, reproducible code. >>> >>> >>> >>> >> >> >> >> > > > >