R help - Dec 2010 - simple payoff function

Just wondering if there is a better way to do this?

x <-  seq(4,20,1)

y <- sapply(x, function(x) (max(x-10,0)))

Is there a easier way to get to y? i.e. max(x-10,0)

Le 11/12/10 16:09, Santosh Srinivas a ?crit :
>
> Just wondering if there is a better way to do this?
>
> x<-  seq(4,20,1)
>
> y<- sapply(x, function(x) (max(x-10,0)))
>
> Is there a easier way to get to y? i.e. max(x-10,0)
Hello,

You are probably looking for pmax, that is described in the same help 
page as max.

 > pmax(x-10, 0)
  [1]  0  0  0  0  0  0  0  1  2  3  4  5  6  7  8  9 10
 > ?pmax

Romain

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