Hi:
Perhaps something like this, assuming DATE is a Date object (try str(plcm60)
to check) - if not, you need to use as.Date() to convert.
jandays <- data.frame(DATE = seq(as.Date('2003-01-01'), by =
'days', length
= 23))
merge(jandays, plcm60, by = 'DATE', all.x = TRUE)
HTH,
Dennis
On Wed, Nov 24, 2010 at 5:58 PM, Jagdish Gangolly
<gangolly@csc.albany.edu>wrote:
> I have a stock price dataset a snippet of which is:
>
> > plcm60[1:15, c(1,3,4,5,6,7)]
> DATE BIDLO ASKHI PRC VOL RET
> 1 1/2/03 9.450 9.79 9.700 1531819 0.018907
> 2 1/3/03 9.670 9.94 9.940 1582192 0.024742
> 3 1/6/03 9.830 10.05 9.960 1843298 0.002012
> 4 1/7/03 9.835 10.38 10.350 1412441 0.039157
> 5 1/8/03 10.220 10.67 10.260 961400 -0.008696
> 6 1/9/03 10.280 11.05 11.020 1742989 0.074074
> 7 1/10/03 10.900 11.29 11.100 701203 0.007260
> 8 1/13/03 11.150 11.44 11.350 959718 0.022523
> 9 1/14/03 11.130 11.40 11.230 994991 -0.010573
> 10 1/15/03 11.110 11.73 11.410 1678751 0.016029
> 11 1/16/03 10.850 11.40 11.079 887901 -0.029010
> 12 1/17/03 10.560 10.91 10.710 968015 -0.033306
> 13 1/21/03 10.430 10.76 10.680 747969 -0.002801
> 14 1/22/03 10.510 10.82 10.560 2702355 -0.011236
> 15 1/23/03 10.700 11.95 11.910 2262855 0.127841
>
> Since the market is closed saturdays, sundays and holidays,
> the dataset has gaps. I need to insert rows (with dates
> but all other columns blank) so that the date
> column in the dataset will have all dates on the calendar?
>
> Is there a simple solution using only strptime, and for loops?
>
> Jagdish
>
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
[[alternative HTML version deleted]]