Hi, Any ideas on how to efficiently convert> list(c(1,2,3),c(4,5,6))to> data.frame(OriginalListIndex=c(1,1,1,2,2,2),Item=c(1,2,3,4,5,6))Thanks for any hints, Joh
Try this:
stack(data.frame(list('A' = c(1,2,3), 'B' = c(4,5,6))))
On Mon, Jul 26, 2010 at 11:46 AM, Johannes Graumann <
johannes_graumann@web.de> wrote:
> Hi,
>
> Any ideas on how to efficiently convert
>
> > list(c(1,2,3),c(4,5,6))
>
> to
>
> > data.frame(OriginalListIndex=c(1,1,1,2,2,2),Item=c(1,2,3,4,5,6))
>
> Thanks for any hints,
>
> Joh
>
> ______________________________________________
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> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
--
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40" S 49° 16' 22" O
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Hi, Here is another option if you already have a list you want to convert. This will handle different elements of the list being different lengths. #Using your example data mydata <- list(c(1,2,3),c(4,5,6)) data.frame( OriginalListIndex = rep(x = seq_along(mydata), times = unlist(lapply(mydata, length))), Item = unlist(mydata) ) #Just to demonstrate that this method works generally mydata <- list(c(1,2,3), c(7,6), c(3,4,5,6,7,8,9)) data.frame( OriginalListIndex = rep(x = seq_along(mydata), times = unlist(lapply(mydata, length))), Item = unlist(mydata) ) HTH, Josh On Mon, Jul 26, 2010 at 7:46 AM, Johannes Graumann <johannes_graumann at web.de> wrote:> Hi, > > Any ideas on how to efficiently convert > >> list(c(1,2,3),c(4,5,6)) > > to > >> data.frame(OriginalListIndex=c(1,1,1,2,2,2),Item=c(1,2,3,4,5,6)) > > Thanks for any hints, > > Joh > > ______________________________________________ > R-help at r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. >-- Joshua Wiley Ph.D. Student, Health Psychology University of California, Los Angeles http://www.joshuawiley.com/
Thanks a lot! This solves my problem! Joh On Monday 26 July 2010 17:06:37 Joshua Wiley wrote:> Hi, > > Here is another option if you already have a list you want to convert. > This will handle different elements of the list being different > lengths. > > #Using your example data > mydata <- list(c(1,2,3),c(4,5,6)) > > data.frame( > OriginalListIndex = rep(x = seq_along(mydata), > times = unlist(lapply(mydata, length))), > Item = unlist(mydata) > ) > > #Just to demonstrate that this method works generally > mydata <- list(c(1,2,3), c(7,6), c(3,4,5,6,7,8,9)) > > data.frame( > OriginalListIndex = rep(x = seq_along(mydata), > times = unlist(lapply(mydata, length))), > Item = unlist(mydata) > ) > > > HTH, > > Josh > > On Mon, Jul 26, 2010 at 7:46 AM, Johannes Graumann > > <johannes_graumann at web.de> wrote: > > Hi, > > > > Any ideas on how to efficiently convert > > > >> list(c(1,2,3),c(4,5,6)) > > > > to > > > >> data.frame(OriginalListIndex=c(1,1,1,2,2,2),Item=c(1,2,3,4,5,6)) > > > > Thanks for any hints, > > > > Joh > > > > ______________________________________________ > > R-help at r-project.org mailing list > > https://stat.ethz.ch/mailman/listinfo/r-help > > PLEASE do read the posting guide > > http://www.R-project.org/posting-guide.html and provide commented, > > minimal, self-contained, reproducible code.