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Hi all I'm writing a pass for the llc tool. If I try to load my pass(llc -load ../mypass.so), this error message appears : Error opening '/nfs/wsi/ti/graumann/llvm-2.5/Release/lib/LLVMMicha.so': /nfs/wsi/ti/graumann/llvm-2.5/Release/lib/LLVMMicha.so: undefined symbol: _ZTVN12_GLOBAL__N_119MyRegisterAllocatorE -load request ignored. Is this code wrong for the pass registration, or the makefile? Thank you for help Michael...

On Aug 11, 2009, at 8:23 AM, Michael Graumann wrote: > I'm writing a pass for the llc tool. If I try to load my pass(llc - > load ../mypass.so), this error message appears : > > Error opening '/nfs/wsi/ti/graumann/llvm-2.5/Release/lib/ > LLVMMicha.so': /nfs/wsi/ti/graumann/llvm-2.5/Release/lib/ > LLVMMicha.so:...

Hi, Is there such a thing? If no: is it easily simulated? thanks, Joh

>From: Johannes Graumann <johannes_graumann at web.de> >Date: 2007/12/18 Tue PM 04:40:37 CST >To: r-help at stat.math.ethz.ch >Subject: [R] All anchored series from a vector? lapply(1:length(myvector) function(.length) { c(myvector[1}:myvector[.length]) }) but test it because i didn't. >Hi all, &...

Hi, Is there any way to get an expression into a data.frame, such that "grid.table" from "gridExtra" will plot it evaluated in the table body? The docu does it for the header, but is the body possible? Thanks, Joh

Why is class(spectrum[["Ion"]]) after this "factor"? spectrum <- cbind(spectrum,Ion=rep("", nrow(spectrum)),Deviation.AMU=rep(0.0, nrow(spectrum))) slowly going crazy ... Joh

Hi, Why is the following retuning a nodset of length 0: > library(XML) > test <- xmlTreeParse( > "http://www.unimod.org/xml/unimod_tables.xml",useInternalNodes=TRUE) > getNodeSet(test,"//modifications_row") Thanks for any hint. Joh

...chael -----Ursprüngliche Nachricht----- Von: llvmdev-bounces at cs.uiuc.edu [mailto:llvmdev-bounces at cs.uiuc.edu] Im Auftrag von Mike Stump Gesendet: Dienstag, 11. August 2009 19:16 An: LLVM Developers Mailing List Betreff: Re: [LLVMdev] llc undefined symbol On Aug 11, 2009, at 8:23 AM, Michael Graumann wrote: > I'm writing a pass for the llc tool. If I try to load my pass(llc - > load ../mypass.so), this error message appears : > > Error opening '/nfs/wsi/ti/graumann/llvm-2.5/Release/lib/ > LLVMMicha.so': /nfs/wsi/ti/graumann/llvm-2.5/Release/lib/ > LLVMMicha.so:...

Hello, I seem unable to construct a legend which contains a substitution as well as math symbols. I'm trying to do the following: strain2 <- "YJG48" legend.txt <- c( substitute( strain * %==% * "YJG45, rpn10" * %Delta%, list(strain=strain2) ), "Verhulst/Logistic", "Malthus" ) legend( 100,2.5, legend.txt, cex=0.75,

Hello, I have started playing around with docker (https://www.docker.io/) and am having trouble to integrate the "docker0" bridge it creates on the fly into my shorewall setup (version 4.5.16.1) on debian testing. IP forwarding is on and I have defined a "doc" ipv4 zone and the interfaces has an entry like so, > doc docker0

Dear all, Can anyone please shed some light onto how to do this? This will give me all "intensity" columsn in my data frame: intensityindeces <- grep("^Intensity",names(dataframe),value=TRUE) This will give me the maximum intensity for the first row: intensityone <- max(dataframe[1,intensityindeces]) What I'm now looking for is how to dfo this for the whole data

Hi, Is there any way to trick R CMD check into not throwing this error after I created a dedicated "plot" incarnation for my custom function? * checking S3 generic/method consistency ... WARNING plot: function(x, ...) plot.MQUSpecMatch: function(x, mozlabel, labelcex) Thanks again, Joh

Hi all, Does anybody have a magic trick handy to isolate directly consecutive integers from something like this: c(1,2,3,4,7,8,9,10,12,13) The result should be, that groups 1-4, 7-10 and 12-13 are consecutive integers ... Thanks for any hints, Joh

Hello, With the help of "seek" I can start "readBin" from any byte offset within my file that I deem appropriate. What I would like to do is to be able to define the endpoint of that read as well. Is there any solution to that already out there? Thanks for any hints, Joh

Hello, I''m stuck IPSECing my wireless network at home and would appreciate any comments. I appologize in advance if I''m wasting your time with trivia - I''m not a professional and staring at the problem for days from various angles hasn''t done me any good ... My home server/firewall (morannon) is hooked up through an USB to ethernet adapter (eth1) to my DSL

Hello, Banging my head against a wall here ... can anyone light the way to a pattern modification that would make the following TRUE? identical( grep( "^Intensity\\s[^HL]", c("Intensity","Intensity L", "Intensity H", "Intensity Rep1")), as.integer(c(1,4))) Thank you for your time. Sincerely, Joh

Hi, Any ideas on how to efficiently convert > list(c(1,2,3),c(4,5,6)) to > data.frame(OriginalListIndex=c(1,1,1,2,2,2),Item=c(1,2,3,4,5,6)) Thanks for any hints, Joh

Hello, I''m having a problem here with my setup which I could use some hints in the right direction with. I want to do the following : - Windows boxes (Instrumentation, not my choice ...) are supposed to samba into a linux fileserver (131.215.52.67) - they don''t see the net directly, but are walled up behind a linux firewall (172.16.0.1/131.215.35.26) - both linux machines

...for help Michael Von: llvmdev-bounces at cs.uiuc.edu [mailto:llvmdev-bounces at cs.uiuc.edu] Im Auftrag von Chris Lattner Gesendet: Samstag, 1. August 2009 07:24 An: LLVM Developers Mailing List Betreff: Re: [LLVMdev] Inserting Instructions (pass) On Jul 31, 2009, at 5:04 PM, Michael Graumann wrote: Thank you Chris, for your hint, but I am still too stupid. I tried two versions asm_arguments.push_back(Type::VoidTy); FunctionType *asm_type = FunctionType::get(Type::VoidTy, asm_arguments, false); Alternatively FunctionType *asm_type = FunctionType::get(Type::VoidTy, std...

Hello, I'm new to this and am trying to teach myself some R by plotting biological data. The growth curve in question is supposed to be fitted to the Verhulst equation, which may be transcribed as follows: f(x)=a/(1+((a-0.008)/0.008)*exp(-(b*x))) - for a known population density (0.008) at t(0). I am trying to rework the example from "An Introduction to R" (p. 72) for my case and