See ?colSums
On Mon, May 10, 2010 at 12:44 AM, vincent.deluard
<vincent.deluard at trimtabs.com> wrote:>
> Hi R users,
>
> I have a matrix "m" of the type:
>
> m
> ? ? ? X4.20.2010 X4.19.2010 ? X4.16.2010
> [1,] ?0.008319468 0.00000000 -0.008250825
> [2,] ?0.005574136 0.01816118 ?0.073081608
> [3,] -0.047830688 0.01612903 -0.030239833
> [4,] ? ? ? ? ? NA ? ? ? ? NA ? ? ? ? ? NA
> [5,] ?0.008746356 0.02848576 -0.025566107
> [6,] -0.007990868 0.00000000 -0.026666667
>
> I want to get the sum of each column. Normally I would do:
>
> apply(m,2,sum)
>
> but I get:
>
>> apply(m,2,sum)
> X4.20.2010 X4.19.2010 X4.16.2010
> ? ? ? ?NA ? ? ? ? NA ? ? ? ? NA
>
> This is because of the presence of "NA" in m. How do you the
equivalent of
>> sum(m[1:6,1],na.rm=TRUE)
> using apply?
>
> Many thanks!
> --
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>
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