So I have Transactions as a dataframe and Transactions$Symbol is a column in the
frame
I simply want to run sub over all elements in that column where the new value
replaces the old value
this doesn't seem to work
Transactions$Symbol = lapply(Transactions$Symbol, function(x) sub('[
-]*','INST',x))> 
> Transactions$Symbol
NULL
Henrique Dallazuanna
2010-Apr-26  13:22 UTC
[R] How use lapply over one column in a dataframe?
Try this:
Transactions$Symbol <- gsub('[
-]*','INST',Transactions$Symbol)
On Mon, Apr 26, 2010 at 10:14 AM, Robert Nicholson <
robert.nicholson@gmail.com> wrote:
> So I have Transactions as a dataframe and Transactions$Symbol is a column
> in the frame
>
> I simply want to run sub over all elements in that column where the new
> value replaces the old value
>
> this doesn't seem to work
>
> Transactions$Symbol = lapply(Transactions$Symbol, function(x) sub('[
> -]*','INST',x))
> >
> > Transactions$Symbol
> NULL
>
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> PLEASE do read the posting guide
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>
-- 
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40" S 49° 16' 22" O
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