Assume you have a vector of characters x:> x[1] "a" "b" "a" "d" "d" "c" I use a function that counts the number of times each string occurs in x:> sapply(unique(x), function(s) {sum(x == s)})a b d c 2 1 2 1 Is there a more efficient way of doing this? Cheers, /Ali
On Mar 29, 2010, at 6:52 PM, Ali Tofigh wrote:> Assume you have a vector of characters x: > >> x > [1] "a" "b" "a" "d" "d" "c" > > I use a function that counts the number of times each string occurs > in x: > >> sapply(unique(x), function(s) {sum(x == s)}) > a b d c > 2 1 2 1 > > Is there a more efficient way of doing this?table(x)>-- David Winsemius, MD West Hartford, CT