Hi,
it's generally considered a bad practice but try this,
eval(parse(text=AA))
library(fortunes)
fortune(106)
HTH,
baptiste
On 10 March 2010 07:46, jq81 <jingqian81 at gmail.com>
wrote:>
> My question is represented by the following example.
>
> For example, I have a character string a, which is defined as
>
> AA="list(x=1, y=2)"
>
> I want to take out the content of AA by using some function, so that I can
> obtain the following expression automatically.
>
> list(x=1, y=2)
>
> Does anyone know how to do it? Thanks a lot,
>
>
>
>
>
>
>
>
> --
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--
____________________
Baptiste Augui?
Departamento de Qu?mica F?sica,
Universidade de Vigo,
Campus Universitario, 36310, Vigo, Spain
tel: +34 9868 18617
http://webs.uvigo.es/coloides