R help - Nov 2009 - solving a linear equation

Hi all,
I've a linear equation of the form:
0.95=2 ( [3+ln(x/3)]^-13  + 4 [3+2ln(x/3)]^-13  + [3+4ln(x/3)]^-13 )

and I want to solve it for x, can I do this using R? 
Thanks in advance.
Maram.


      
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On Wed, 4 Nov 2009 04:34:36 -0800 (PST) maram salem 
<marammagdysalem at yahoo.com> wrote:
> I've a linear equation of the form:
> 0.95=2 ( [3+ln(x/3)]^-13? + 4 [3+2ln(x/3)]^-13? + [3+4ln(x/3)]^-13 )
> 
> and I want to solve it for x, can I do this using R? 
Yup. Use the 'uniroot' function (assuming that your equation only has 
one solution).

BTW, your equation doesn't look very linear to me ...

-- 
Karl Ove Hufthammer

maram salem wrote:
> 
> Hi all,
> I've a linear equation of the form:
> 0.95=2 ( [3+ln(x/3)]^-13? + 4 [3+2ln(x/3)]^-13? + [3+4ln(x/3)]^-13 )
> 
> and I want to solve it for x, can I do this using R? 
> 
The equation is (highly) nonlinear.
Use uniroot.
Do plot your function for several different intervals. It has multiple
zeros.

Berend
-- 
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