Try this:
> library(chron)
> times(100/(24*60*60)) # 100 seconds
[1] 00:01:40
On Fri, Oct 30, 2009 at 5:37 AM, Stefano Leonardi
<stefano.leonardi at unipr.it> wrote:> Hi,
> I could not find a function that returns a time in hours and minutes given
> seconds as argument. I looked also in the chron package.
>
> I would need something like this:
>
> mytime(61) #61 are seconds
> [1] "00:01:01"
>
> mytime(7385) #7385 are seconds
> [1] "02:03:05"
>
> Am I missing something? or should I write it by myself?
> Thank you
> Stefano
>
>
> --
> =====================================================================>
?Stefano Leonardi
> ?Dipartimento di Scienze Ambientali
> ?Universita` di Parma ? ? ? ? ? ? ? E-mail: stefano.leonardi at unipr.it
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>
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