I've never seen the "/" used in a formula like that. What does it
do?
-Ista
On Mon, Oct 26, 2009 at 8:13 AM, john56 <panatheod at gmail.com>
wrote:>
> Hi,
>
> I am new in statistics and i manage to make the linear model analysis but i
> have some difficulties in explaining the results. Can someone help me
> explalinig the output of my linear model analysis ? My data are with 2
> variables habitat (e,s) and treatment (a,c,p) with multiple trials within.
>
> Thank you in advance
>
> Call:
> lm(formula = a$wild ~ a$habitat/a$treatment/a$trial)
>
> Residuals:
> ? ?Min ? ? ?1Q ?Median ? ? ?3Q ? ? Max
> -58.905 -19.958 ?-5.774 ?16.693 ?88.890
>
> Coefficients:
> ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ?Estimate Std. Error t value Pr(>|t|)
> (Intercept) ? ? ? ? ? ? ? ? ? ? ?55.4664 ? ? 2.0332 ?27.281 ?< 2e-16 ***
> a$habitats ? ? ? ? ? ? ? ? ? ? ?-11.9615 ? ? 2.8753 ?-4.160 3.26e-05 ***
> a$habitate:a$treatmentc ? ? ? ? ? 7.3581 ? ? 2.8753 ? 2.559 ?0.01054 *
> a$habitats:a$treatmentc ? ? ? ? ?-4.9803 ? ? 2.8753 ?-1.732 ?0.08335 .
> a$habitate:a$treatmentp ? ? ? ? -13.9906 ? ? 2.8753 ?-4.866 1.19e-06 ***
> a$habitats:a$treatmentp ? ? ? ? -16.1311 ? ? 2.8753 ?-5.610 2.17e-08 ***
> a$habitate:a$treatmenta:a$trial ?-0.3204 ? ? 0.3808 ?-0.841 ?0.40030
> a$habitats:a$treatmenta:a$trial ?-0.1319 ? ? 0.3808 ?-0.346 ?0.72905
> a$habitate:a$treatmentc:a$trial ?-1.1250 ? ? 0.3808 ?-2.954 ?0.00316 **
> a$habitats:a$treatmentc:a$trial ?-0.4236 ? ? 0.3808 ?-1.112 ?0.26608
> a$habitate:a$treatmentp:a$trial ?-0.3021 ? ? 0.3808 ?-0.793 ?0.42775
> a$habitats:a$treatmentp:a$trial ?-0.2873 ? ? 0.3808 ?-0.754 ?0.45072
> ---
> Signif. codes: ?0 ?***? 0.001 ?**? 0.01 ?*? 0.05 ?.? 0.1 ? ? 1
>
> Residual standard error: 26.8 on 3588 degrees of freedom
> Multiple R-squared: 0.1383, ? ? Adjusted R-squared: 0.1357
> F-statistic: 52.35 on 11 and 3588 DF, ?p-value: < 2.2e-16
>
> --
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>
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>
--
Ista Zahn
Graduate student
University of Rochester
Department of Clinical and Social Psychology
http://yourpsyche.org