R help - Oct 2009 - Creating new variables

Hi all,

I have a data set called x with    200 rows  and 12  columns.  I want
create  two more columns based on  probability. ie
 if p >0 .4 then  v1 =1 else v1=0;
 if p >0 .6 then  v2 =1 else v2=0;

Finally x will have 14 variables.

Can any one show me how to do that?

Thanks
Ashta


.

	[[alternative HTML version deleted]]

If the 'data set' is a dataframe, the following will work:

x$v1 <- ifelse(x$p > 0.4, 1, 0)
x$v2 <- ifelse(x$p > 0.6, 1, 0)

If it is matrix, try

x <- cbind(x, v1=ifelse(x[,'p'] > 0.4, 1, 0),
v2=ifelse(x[,'p'] > 0.6, 1, 2))

If helps a lot if you follow the posting rules and  provide commented,
minimal, self-contained, reproducible code.

On Sat, Oct 10, 2009 at 6:04 PM, Ashta <sewashm at gmail.com>
wrote:
> Hi all,
>
> I have a data set called x with ? ?200 rows ?and 12 ?columns. ?I want
> create ?two more columns based on ?probability. ie
> ?if p >0 .4 then ?v1 =1 else v1=0;
> ?if p >0 .6 then ?v2 =1 else v2=0;
>
> Finally x will have 14 variables.
>
> Can any one show me how to do that?
>
> Thanks
> Ashta
>
>
> .
>
> ? ? ? ?[[alternative HTML version deleted]]
>
> ______________________________________________
> R-help at r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>


-- 
Jim Holtman
Cincinnati, OH
+1 513 646 9390

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